Explanation Given information: Constant of the spring : k = 30 l b / i n . Weight of rod AB: W A B = 20 l b Weight of the disks: W d i s k = 12 l b Calculations: For Position 1: Kinetic energy: T 1 = 0 , Potential energy: V 1 = 1 2 k x m 2 For Position 2 : Kinetic energy: T 2 = 1 2 m A B v m 2 + 2 ( 1 2 I ¯ ω m 2 + 1 2 m d i s k v ¯ m 2 ) o r , T 2 = 1 2 m A B v m 2 + ( 1 2 m d i s k r 2 ) ( v m r ) 2 + m d i s k v m 2 T 2 = 1 2 ( m A B + 3 m d i s k ) v m 2 Potential energy: V 2 = 0 , Now, applying the law of conservation of energy

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ISBN: 9781260265521

Author: BEER

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Forced undamped vibrations

In mechanical engineering, vibration is expressed as the term that occurs due to an object's backward and forward movement about a point of equilibrium. Generally, there are three types of vibrations which are,

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Chapter 19.3, Problem 19.90P

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Frequency period of vibration of the system.

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Chapter 19.3, Problem 19.89P

Chapter 19.3, Problem 19.91P

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Frequency period of vibration of the system.

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