Explanation Here we denote, ω f = ω Magnification Factor = X m P m k = 1 ( 1 − ( ω ω n ) 2 ) 2 + [ 2 ( c c c ) ( ω ω n ) ] 2 Now we have to Find value of ω ω n for which X m P m k is a maximum. 0 = d ( X m P m k ) d ( ω ω n ) = [ 2 [ 1 − ( ω ω n ) 2 ] ( − 1 ) + 4 ( c c c ) 2 ] { ( 1 − ( ω ω n ) 2 ) 2 <

12th Edition

ISBN: 9781260265521

Author: BEER

Publisher: MCG

See similar textbooks

Concept explainers

Free Damped Vibrations

Free vibration is a type of vibration in which the external force is removed after giving the initial displacement to a body/system. In other words, in this type of vibration, force is applied at the initial displacement of the system, and after the init…

Question

Chapter 19.5, Problem 19.142P

To determine

The maximum amplitude of a forced vibration when ω_f≈ω⅐ and the corresponding value of the magnification factor is 12CCc.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 19.5, Problem 19.141P

Chapter 19.5, Problem 19.143P

Students have asked these similar questions

-6- 8 من 8 Mechanical vibration HW-prob-1 lecture 8 By: Lecturer Mohammed O. attea The 8-lb body is released from rest a distance xo to the right of the equilibrium position. Determine the displacement x as a function of time t, where t = 0 is the time of release. c=2.5 lb-sec/ft wwwww k-3 lb/in. 8 lb Prob. -2 Find the value of (c) if the system is critically damping. Prob-3 Find Meq and Ceq at point B, Drive eq. of motion for the system below. Ш H -7~ + 目 T T & T тт +

Q For the following plan of building foundation, Determine immediate settlement at points (A) and (B) knowing that: E,-25MPa, u=0.3, Depth of foundation (D) =1m, Depth of layer below base level of foundation (H)=10m. 3m 2m 100kPa A 2m 150kPa 5m 200kPa B

W PE 2 43 R² 80 + 10 + kr³ Ø8=0 +0 R²+J+ kr200 R² + J-) + k r² = 0 kr20 kr20 8+ W₁ = = 0 R²+1) R²+J+) 4 lec 8.pdf Mechanical vibration lecture 6 By: Lecturer Mohammed C. Attea HW1 (Energy method) Find equation of motion and natural frequency for the system shown in fig. by energy method. m. Jo 000 HW2// For the system Fig below find 1-F.B.D 2Eq.of motion 8 wn 4-0 (1) -5- m

Chapter 19 Solutions

VECTOR MECH...,DYNAMICS(LOOSE)-W/ACCESS

Ch. 19.1 - A particle moves in simple harmonic motion....Ch. 19.1 - A particle moves in simple harmonic motion....Ch. 19.1 - Prob. 19.3P Ch. 19.1 - Prob. 19.4P Ch. 19.1 - Prob. 19.5P Ch. 19.1 - A 20-lb block is initially held so that the...Ch. 19.1 - Prob. 19.7P Ch. 19.1 - A simple pendulum consisting of a bob attached to...Ch. 19.1 - Prob. 19.9P Ch. 19.1 - A 5-kg fragile glass vase is surrounded by packing...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

The maximum amplitude of a forced vibration when ω f ≈ω⅐ and the corresponding value of the magnification factor is 1 2 C C c .

Solution Summary: The author denotes the maximum amplitude of a forced vibration when f is 17 and the corresponding value of the magnification factor. The damping constant for oil, C = 5.48 N.

Concept explainers

The maximum amplitude of a forced vibration when ω_f≈ω⅐ and the corresponding value of the magnification factor is 12CCc.

Want to see the full answer?

Chapter 19 Solutions

The maximum amplitude of a forced vibration when ω f ≈ω⅐ and the corresponding value of the magnification factor is 1 2 C C c .

Solution Summary: The author denotes the maximum amplitude of a forced vibration when f is 17 and the corresponding value of the magnification factor. The damping constant for oil, C = 5.48 N.

Concept explainers

The maximum amplitude of a forced vibration when ωf≈ω⅐ and the corresponding value of the magnification factor is 12CCc.

Want to see the full answer?

Chapter 19 Solutions

The maximum amplitude of a forced vibration when ω_f≈ω⅐ and the corresponding value of the magnification factor is 12CCc.