Chemistry & Chemical Reactivity
9th Edition
ISBN: 9781133949640
Author: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher: Cengage Learning
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Textbook Question
Chapter 19.2, Problem 2CYU
The following overall
Overall chemical equation: Zn(s) + PbSO4(s) → Zn2+(aq) + Pb(s) + SO42−(aq)
Use cell notation to describe the electrochemical cell.
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Learning Goal:
This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this:
35 Cl
17
In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is:
It is also correct to write symbols by leaving off the atomic number, as in the following form:
atomic number
mass number Symbol
35 Cl or
mass number Symbol
This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons
are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written.
Watch this video to review the format for written symbols.
In the following table each column…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Chapter 19 Solutions
Chemistry & Chemical Reactivity
Ch. 19.1 - Prob. 2CYUCh. 19.1 - Prob. 3CYUCh. 19.1 - 1. Copper(II) sulfide reacts with nitric acid...Ch. 19.1 - Prob. 2RCCh. 19.1 - The balanced half-reaction for Br2 BrO3 in basic...Ch. 19.2 - Describe how to set up a voltaic cell using the...Ch. 19.2 - The following overall chemical reaction occurs in...Ch. 19.2 - Prob. 1RCCh. 19.2 - Prob. 2RCCh. 19.2 - Prob. 3RC
Ch. 19.3 - Prob. 1RCCh. 19.3 - Prob. 2RCCh. 19.4 - (a) Rank the following metals in their ability to...Ch. 19.4 - Prob. 1RCCh. 19.4 - Prob. 2RCCh. 19.4 - Prob. 3RCCh. 19.4 - Prob. 1QCh. 19.4 - Prob. 2QCh. 19.4 - Prob. 3QCh. 19.5 - A voltaic cell is set up with an aluminum...Ch. 19.5 - Check Your Understanding
The half-cells Fe2+(aq,...Ch. 19.5 - Prob. 1RCCh. 19.6 - Prob. 1CYUCh. 19.6 - Calculate the equilibrium constant at 25 C for the...Ch. 19.6 - Prob. 1RCCh. 19.7 - Predict the chemical reactions that will occur at...Ch. 19.7 - Prob. 1RCCh. 19.8 - Prob. 1CYUCh. 19.8 - 1. If you wish to convert 0.0100 mol of Au3+ (aq)...Ch. 19.8 - Prob. 1QCh. 19.8 - Use standard reduction potentials to determine...Ch. 19.8 - Prob. 3QCh. 19.8 - The overall reaction for the production of Cu(OH)2...Ch. 19.8 - Assume the following electrochemical cell...Ch. 19 - Write balanced equations for the following...Ch. 19 - Write balanced equations for the following...Ch. 19 - Balance the following redox equations. All occur...Ch. 19 - Balance the following redox equations. All occur...Ch. 19 - Balance the following redox equations. All occur...Ch. 19 - Prob. 6PSCh. 19 - A voltaic cell is constructed using the reaction...Ch. 19 - A voltaic cell is constructed using the reaction...Ch. 19 - The half-cells Fe2+(aq) | Fe(s) and O2(g) | H2O...Ch. 19 - The half cells Sn2+(aq) |Sn(s) and Cl2(g) |Cl(aq)...Ch. 19 - For each of the following electrochemical cells,...Ch. 19 - For each of the following electrochemical cells,...Ch. 19 - Use cell notation to depict an electrochemical...Ch. 19 - Use cell notation to depict an electrochemical...Ch. 19 - What are the similarities and differences between...Ch. 19 - What reactions occur when a lead storage battery...Ch. 19 - Calculate the value of E for each of the following...Ch. 19 - Calculate the value of E for each of the following...Ch. 19 - Balance each of the following unbalanced...Ch. 19 - Balance each of the following unbalanced...Ch. 19 - Consider the following half-reactions: (a) Based...Ch. 19 - Prob. 22PSCh. 19 - Which of the following elements is the best...Ch. 19 - Prob. 24PSCh. 19 - Which of the following ions is most easily...Ch. 19 - From the following list, identify the ions that...Ch. 19 - (a) Which halogen is most easily reduced in acidic...Ch. 19 - Prob. 28PSCh. 19 - Calculate the potential delivered by a voltaic...Ch. 19 - Calculate the potential developed by a voltaic...Ch. 19 - One half-cell in a voltaic cell is constructed...Ch. 19 - One half-cell in a voltaic cell is constructed...Ch. 19 - One half-cell in a voltaic cell is constructed...Ch. 19 - One half-cell in a voltaic cell is constructed...Ch. 19 - Calculate rG and the equilibrium constant for the...Ch. 19 - Prob. 36PSCh. 19 - Use standard reduction potentials (Appendix M) for...Ch. 19 - Use the standard reduction potentials (Appendix M)...Ch. 19 - Use the standard reduction potentials (Appendix M)...Ch. 19 - Use the standard reduction potentials (Appendix M)...Ch. 19 - Prob. 41PSCh. 19 - Prob. 42PSCh. 19 - Which product, O2 or F2, is more likely to form at...Ch. 19 - Which product, Ca or H2, is more likely to form at...Ch. 19 - An aqueous solution of KBr is placed in a beaker...Ch. 19 - An aqueous solution of Na2S is placed in a beaker...Ch. 19 - In the electrolysis of a solution containing...Ch. 19 - In the electrolysis of a solution containing...Ch. 19 - Electrolysis of a solution of CuSO4(aq) to give...Ch. 19 - Electrolysis of a solution of Zn(NO3)2(aq) to give...Ch. 19 - A voltaic cell can be built using the reaction...Ch. 19 - Assume the specifications of a Ni-Cd voltaic cell...Ch. 19 - Prob. 53GQCh. 19 - Balance the following equations. (a) Zn(s) +...Ch. 19 - Magnesium metal is oxidized, and silver ions are...Ch. 19 - You want to set up a series of voltaic cells with...Ch. 19 - Prob. 57GQCh. 19 - Prob. 58GQCh. 19 - In the table of standard reduction potentials,...Ch. 19 - Prob. 60GQCh. 19 - Four voltaic cells are set up. In each, one...Ch. 19 - The following half-cells are available: (i)...Ch. 19 - Prob. 63GQCh. 19 - Prob. 64GQCh. 19 - A potential of 0.142 V is recorded (under standard...Ch. 19 - Prob. 66GQCh. 19 - The standard potential, E, for the reaction of...Ch. 19 - An electrolysis cell for aluminum production...Ch. 19 - Electrolysis of molten NaCl is done in cells...Ch. 19 - A current of 0.0100 A is passed through a solution...Ch. 19 - A current of 0.44 A is passed through a solution...Ch. 19 - Prob. 72GQCh. 19 - Prob. 73GQCh. 19 - Prob. 74GQCh. 19 - The products formed in the electrolysis of aqueous...Ch. 19 - Predict the products formed in the electrolysis of...Ch. 19 - Prob. 77GQCh. 19 - The metallurgy of aluminum involves electrolysis...Ch. 19 - Prob. 79GQCh. 19 - Prob. 80GQCh. 19 - Prob. 81GQCh. 19 - Prob. 82GQCh. 19 - Two Ag+(aq) | Ag(s) half-cells are constructed....Ch. 19 - Calculate equilibrium constants for the following...Ch. 19 - Prob. 85GQCh. 19 - Use the table of standard reduction potentials...Ch. 19 - Prob. 87GQCh. 19 - Prob. 88GQCh. 19 - Prob. 89GQCh. 19 - A voltaic cell is constructed in which one...Ch. 19 - An expensive but lighter alternative to the lead...Ch. 19 - The specifications for a lead storage battery...Ch. 19 - Manganese may play an important role in chemical...Ch. 19 - Prob. 94GQCh. 19 - Iron(II) ion undergoes a disproportionation...Ch. 19 - Copper(I) ion disproportionates to copper metal...Ch. 19 - Prob. 97GQCh. 19 - Prob. 98GQCh. 19 - Consider an electrochemical cell based on the...Ch. 19 - Prob. 100ILCh. 19 - A silver coulometer (Study Question 106) was used...Ch. 19 - Four metals, A, B, C, and D, exhibit the following...Ch. 19 - Prob. 103ILCh. 19 - The amount of oxygen, O2, dissolved in a water...Ch. 19 - Prob. 105SCQCh. 19 - The free energy change for a reaction, rG, is the...Ch. 19 - Prob. 107SCQCh. 19 - (a) Is it easier to reduce water in acid or base?...Ch. 19 - Prob. 109SCQ
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- Please correct answer and don't used hand raitingarrow_forwardneed help please and thanks dont understand a-b Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal energy Divide the…arrow_forwardPlease correct answer and don't used hand raitingarrow_forward
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