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a.
Interpretation:The net change to
Concept Introduction:Thechanging of atomic and mass numbers of an element in a nuclear reaction depends on the type of nuclear decay of the atom.
a.
![Check Mark](/static/check-mark.png)
Answer to Problem 2RQ
In alpha particle production, the
Explanation of Solution
Alpha particle is produced when an element undergoes alpha decay. The element releases an alpha particle from its nucleus which is a helium atom with z=2 and a=4, hence the atomic and mass numbers of the element get decreased by the subsequent values.
b.
Interpretation: The net change to atomic and mass number needs to be calculated for beta particle production
Concept Introduction:The changing of atomic and mass numbers of an element in a nuclear reaction depends on the type of nuclear decay of the atom.
b.
![Check Mark](/static/check-mark.png)
Answer to Problem 2RQ
In beta particle production, the atomic number increases by 1 and the mass number remains the same.
Explanation of Solution
Beta particle is produced when an element undergoes negative beta decay. The element releases a beta particle from its nucleus which is an electron from a neutron with conversion of the neutron into proton, hence the atomic number increases by one due to increase in proton but the mass number remains same.
c.
Interpretation: The net change to atomic and mass number needs to be calculated for electron capture.
Concept Introduction:The changing of atomic and mass numbers of an element in a nuclear reaction depends on the type of nuclear decay of the atom.
c.
![Check Mark](/static/check-mark.png)
Answer to Problem 2RQ
In electron capture, the atomic number decreases by 1 and the mass number remains same.
Explanation of Solution
In electron capture decay,the element accepts an electron into the nucleus which neutralizes the charge of a proton converting it into a neutron, hence the atomic number decreases by 1 due to decrease in proton and electron and mass remains unchanged.
d.
Interpretation: The net change to atomic and mass number needs to be calculated for positron particle production
Concept Introduction:The changing of atomic and mass numbers of an element in a nuclear reaction depends on the type of nuclear decay of the atom.
d.
![Check Mark](/static/check-mark.png)
Answer to Problem 2RQ
In beta particle production, the atomic number decreases by 1 and the mass number remains the same.
Explanation of Solution
Positron particle is produced when an element undergoes positive beta decay. The element releases a positron particle from its nucleus which is a massless positively charged particle from a proton with conversion of the proton into neutron, hence the atomic number decreases by one due to decrease in proton but the mass number remains same.
Chapter 19 Solutions
World of Chemistry, 3rd edition
- The number of noncyclic isomers that have the composition C4H8Owith the O as part of an OH group, counting a pair of stereoisomers as1, is A. 8; B. 6; C. 9; D. 5; E. None of the other answers is correct.arrow_forwardNonearrow_forwardThe number of carbon skeletons that have 8 carbons, one of which istertiary is A. 7; B. More than 7; C. 6; D. 5; E. 4arrow_forward
- The azide ion is N3^-. In addition to the ionic charge, it’s three mostimportant contributing structures also have formal charges. The totalnumber of π bonds in these three contributing structures isA. 6; B. 12; C. 3; D. 9; E. None of the other answers is correct.arrow_forwardThe sum of the numerals in the name of the compoundis A. None of the other answers is correct.; B. 11;C. 6; D. 8; E. 5.arrow_forwardA compound has a six carbon ring with three double bonds. Attachedto the ring is a three carbon chain with a triple bond and a two carbonchain with two bromines attached. The number of hydrogens in a molecule of this compound is A. 10; B. 12; C. 14; D. 13; E. None of the other answers is correct.arrow_forward
- Can you help me? I can't seem to understand the handwriting for the five problems, and I want to be able to solve them and practice. If you'd like to give me steps, please do so to make it easier understand.arrow_forwardThe number of 2sp3 hybrid orbitals in the moleculeis A. 12; B. 8; C. 3; D. 11; E. None of the other answers is correct.arrow_forwardNonearrow_forward
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