
a)
Interpretation:
The name of the ketone shown is to be given.
Concept introduction:
To give:
The name of the ketone shown.
b)
Interpretation:
The name of the aldehyde shown is to be given.
Concept introduction:
To give:
The name of the aldehyde shown.
c)
Interpretation:
The name of the diketone shown is to be given.
Concept introduction:
Ketones are named by replacing the terminal –e of the parent alkane with –one. The parent chain is the longest one that includes the ketone group and the numbering begins at the end nearer to the carbonyl carbon. If other functional groups are present the double bonded oxygen is considered as a substituent on the parent chain with the prefix –oxo.
To give:
The name of the diketone shown.
d)
Interpretation:
The name of the aldehyde shown is to be given.
Concept introduction:
Aldehydes are named by replacing the terminal –e of the parent alkane with –al. The parent chain is the longest one that includes the -CHO group and the –CHO group is numbered as carbon 1. For cyclic aldehydes in which the –CHO group is directly attached to the ring, the suffix –carbaldehyde is used.
To give:
The name of the aldehyde shown.
e)
Interpretation:
The name of the aldehyde shown is to be given.
Concept introduction:
Aldehydes are named by replacing the terminal –e of the parent alkane with –al. The parent chain is the longest one that includes the –CHO group and the –CHO group is numbered as carbon 1. For cyclic aldehydes in which the –CHO group is directly attached to the ring, the suffix –carbaldehyde is used.
To give:
The name of the aldehyde shown.
f)
Interpretation:
The name of the ketone shown is to be given.
Concept introduction:
Ketones are named by replacing the terminal –e of the parent alkane with –one. For alicyclic ketones the number of carbons in the ring determines the parent name. The numbering starts from the carbonyl carbon and the numbering is done such a way that other functional groups and/or substituents get the lowest possible number.
To give:
The name of the ketone shown.

Trending nowThis is a popular solution!

Chapter 19 Solutions
Study Guide with Student Solutions Manual for McMurry's Organic Chemistry, 9th
- please helparrow_forwardPredict the products of the following reactions. Draw mechanism arrows for each step for a, b, and c. a.) HBr b.) HI H₂O H2SO4 d.) C12 HO H2SO4 1.) BH3 2.) H2O2, NaOHarrow_forwardK for the following reaction is 0.11 at constant temperature. If the equilibrium concentration of HCl is 0.5 M, what is the equilibrium concentration of NH3. NH4CI(s) ⇌ NH3(g) + HCI(g)arrow_forward
- please help by Draw the following structures (Lewis or line-angle drawing).arrow_forwardplease helparrow_forwardConsider the reaction: 2 A (aq) ⇌ B(aq) Given the following KC values and starting with the initial concentration of A = 4.00 M, complete ICE diagram(s)and find the equilibrium concentrations for A and B.A) KC = 4.00B) KC = 200C) KC = 8.00 x10-3arrow_forward
- 5) Consider the reaction: Cl2 (g) + F2 (g) ⟷ 2 ClF (g) KP=? The partial pressure of 203 kPa for Cl2 and a partial pressure of 405 kPa for F2. Upon reaching equilibrium, thepartial pressure of ClF is 180 kPa. Calculate the equilibrium concentrations and then find the value for KP.arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward(9 Pts) In one of the two Rare Earth element rows of the periodic table, identify an exception tothe general ionization energy (IE) trend. For the two elements involved, answer the followingquestions. Be sure to cite sources for all physical data that you use.a. (2 pts) Identify the two elements and write their electronic configurations.b. (2 pts) Based on their configurations, propose a reason for the IE trend exception.c. (5 pts) Calculate effective nuclear charges for the last electron in each element and theAllred-Rochow electronegativity values for the two elements. Can any of these valuesexplain the IE trend exception? Explain how (not) – include a description of how IErelates to electronegativity.arrow_forward
- Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning




