Chapter 19, Problem 91A

Interpretation Introduction

Interpretation:

The % yield of iron oxide is to be calculated by given data.

Concept introduction:

Mass-Mass relationship is used to solve the problem.

Firstly find out how much substance should produce then calculate the % yield using formula.

$\%yield=\frac{amountgiven}{amountthatshouldactuallyproduced}\times 100$

Answer to Problem 91A

% yield=92.6 %

Explanation of Solution

The given equation is:

$4FeC{l}_3+3O_2\to 2F{e}_2{O}_3+6C{l}_2$

Thus according to it 4 mol of $FeC{l}_3$ should produce 2 mol $F{e}_2{O}_3$

Or 650 gram $FeC{l}_3$ produces=320 gram $F{e}_2{O}_3$

So 45 gram should produce = $\frac{320}{650}\times 45$

=22.15 gram

Therefore % yield = $\frac{20.5}{22.15}\times 100$

=92.6 %

Conclusion

The % yield of iron oxide is 92.6 %