
Concept explainers
(a)
Interpretation: The formula for the given coordination complex needs to be determined.
- Hexakis(pyridine)cobalt(III) chloride
Concept Introduction: A coordination complex is composed of two main parts; metal atom/ ion and ligand. Ligands are the atom/ group of atom/ ion that can donate its extra pair of electrons to the electron deficient metal cation. It leads to the formation of coordinate bond between metal ion and ligand.
(a)

Answer to Problem 73AE
Explanation of Solution
In the formula of writing and naming of coordination complex; IUPAC rule must be followed.
- Atomic symbol of the metal center must be written first in the square bracket.
- Ligands must be written after metal symbol in sequence of anion then neutral ligand.
- The ligands must be written in alphabetical order.
- The number of ligands or metal must be indicated as sub-script.
- Counter ion must be written outside the square bracket.
In Hexakis(pyridine)cobalt(III) chloride; chloride ion is counter ion with
(b)
Interpretation: The formula for the given coordination complex needs to be determined.
- Pentaammineiodochromium(III) iodide
Concept Introduction: A coordination complex is composed of two main parts; metal atom/ ion and ligand. Ligands are the atom/ group of atom/ ion that can donate its extra pair of electrons to the electron deficient metal cation. It leads to the formation of coordinate bond between metal ion and ligand.
(b)

Answer to Problem 73AE
Explanation of Solution
In the formula of writing and naming of coordination complex; IUPAC rule must be followed.
- Atomic symbol of the metal center must be written first in the square bracket.
- Ligands must be written after metal symbol in sequence of anion then neutral ligand.
- The ligands must be written in alphabetical order.
- The number of ligands or metal must be indicated as sub-script.
- Counter ion must be written outside the square bracket.
In Pentaammineiodochromium(III) iodide; iodide ion is counter ion with
(c)
Interpretation: The formula for the given coordination complex needs to be determined.
- Tris(ethylenediamine)nickel(II) bromide
Concept Introduction: A coordination complex is composed of two main parts; metal atom/ ion and ligand. Ligands are the atom/ group of atom/ ion that can donate its extra pair of electrons to the electron deficient metal cation. It leads to the formation of coordinate bond between metal ion and ligand.
(c)

Answer to Problem 73AE
Explanation of Solution
In the formula of writing and naming of coordination complex; IUPAC rule must be followed.
- Atomic symbol of the metal center must be written first in the square bracket.
- Ligands must be written after metal symbol in sequence of anion then neutral ligand.
- The ligands must be written in alphabetical order.
- The number of ligands or metal must be indicated as sub-script.
- Counter ion must be written outside the square bracket.
In Tris(ethylenediamine)nickel(II) bromide; bromide ion is counter ion with
(d)
Interpretation: The formula for the given coordination complex needs to be determined.
- Potassium tetracyanonickelate(II)
Concept Introduction: A coordination complex is composed of two main parts; metal atom/ ion and ligand. Ligands are the atom/ group of atom/ ion that can donate its extra pair of electrons to the electron deficient metal cation. It leads to the formation of coordinate bond between metal ion and ligand.
(d)

Answer to Problem 73AE
Explanation of Solution
In the formula of writing and naming of coordination complex; IUPAC rule must be followed.
- Atomic symbol of the metal center must be written first in the square bracket.
- Ligands must be written after metal symbol in sequence of anion then neutral ligand.
- The ligands must be written in alphabetical order.
- The number of ligands or metal must be indicated as sub-script.
- Counter ion must be written outside the square bracket.
In Potassium tetracyanonickelate(II); potassium ion is counter ion with
(e)
Interpretation: The formula for the given coordination complex needs to be determined.
- Tetraamminedichloroplatinum(IV) tetrachloroplatinate(II)
Concept Introduction: A coordination complex is composed of two main parts; metal atom/ ion and ligand. Ligands are the atom/ group of atom/ ion that can donate its extra pair of electrons to the electron deficient metal cation. It leads to the formation of coordinate bond between metal ion and ligand.
(e)

Answer to Problem 73AE
Explanation of Solution
In the formula of writing and naming of coordination complex; IUPAC rule must be followed.
- Atomic symbol of the metal center must be written first in the square bracket.
- Ligands must be written after metal symbol in sequence of anion then neutral ligand.
- The ligands must be written in alphabetical order.
- The number of ligands or metal must be indicated as sub-script.
- Counter ion must be written outside the square bracket.
In Tetraamminedichloroplatinum(IV) tetrachloroplatinate(II); both cation and anion are complex ions. Cation Tetraamminedichloroplatinum(IV), has 4 ammine ligands, two chloro ligands with
Hence the formula must be
Want to see more full solutions like this?
Chapter 19 Solutions
Chemical Principles
- answer thisarrow_forwardplease add appropriate arrows and tell me in detail where to add which or draw itarrow_forwardPart 1. Draw monomer units of the following products and draw their reaction mechanism (with arrow pushing) Temporary cross-linked polymer Using: 4% polyvinyl alcohol+ methyl red + 4% sodium boratearrow_forward
- can you please answer both these questions and draw the neccesaryarrow_forwardcan you please give the answer for both these pictures. thankyouarrow_forwardPart 1. Draw monomer units of the following products and draw their reaction mechanism (with arrow pushing) | Bakelite like polymer Using: Resorcinol + NaOH + Formalinarrow_forward
- Question 19 0/2 pts 3 Details You have a mixture of sodium chloride (NaCl) and potassium chloride (KCl) dissolved in water and want to separate out the Cl- ions by precipitating them out using silver ions (Ag+). The chemical equation for the net ionic reaction of NaCl and KCl with silver nitrate, AgNO3, is shown below. Ag+(aq) + Cl(aq) → AgCl(s) The total mass of the NaCl/KCl mixture is 1.299 g. Adding 50.42 mL of 0.381 M solution precipitates out all of the Cl-. What are the masses of NaCl and KCl in the mixture? Atomic masses: g: Mass of NaCl g: Mass of KCL Ag = 107.868 g mol- 1 Cl = 35.453 g mol- 1 K = 39.098 g mol- N = 14.007 g mol−1 Na = 22.99 g mol−1 0 = 15.999 g mol 1 Question Help: ✓ Message instructor Submit Questionarrow_forwardPart 1. Draw monomer units of the following products and draw their reaction mechanism (with arrow pushing) Polyester fiber Using a) pthalic anhydride + anhydrous sodium acetate + ethylene glycol B)pthalic anhydride + anhydrous sodium acetate + glycerolarrow_forwardIdentify the missing starting materials/ reagents/ products in the following reactions. Show the stereochemistry clearly in the structures, if any. If there is a major product, draw the structures of the major product with stereochemistry clearly indicated where applicable. Show only the diastereomers (you do not have to draw the pairs of enantiomers). If you believe that multiple products are formed in approximately equal amounts (hence neither is the major product), draw the structures of the products, and show the detailed mechanism of these reactions to justify the formation of the multiple products. If you believe no product is formed, explain why briefly. (6 mark for each, except f and g, which are 10 mark each)arrow_forward
- 3. What starting material would you use to synthesize 3-hydroxypentanoic acid using a NaBH4 reduction?arrow_forward1. Give stereochemical (Fischer projection) formulas for all (but no extras) the stereoisomers that could theoretically form during the reduction of a. the carbonyl group of 2-methyl-3--pentanone b. both carbonyl groups of 2,4-pentanedione (careful!) 2. Predict the products of the reduction of O=CCH2CH2CH2C=O with a. LiAlH4 b. NaBH4 CH3 OHarrow_forwardWhich of the following compounds can be synthesized using one reaction from any alkene, as a major product? If it can be synthesized, propose a route, and you may use any other starting materials, reagents and solvents as needed. If you do not think that it can be synthesized as a major product from an alkene, explain in detail why.arrow_forward
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
- General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning




