Physical Chemistry
Physical Chemistry
2nd Edition
ISBN: 9781133958437
Author: Ball, David W. (david Warren), BAER, Tomas
Publisher: Wadsworth Cengage Learning,
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Chapter 19, Problem 19.8E
Interpretation Introduction

Interpretation:

The temperature of the N2 in the previous exercise is to be calculated.

Concept introduction:

According to the kinetic theory of gases, there are large numbers of identical particles that are present in gases. These particles are tiny and very far from each other. The volume occupied by the gaseous molecules is almost negligible in comparison of the space that is present between the particles. Therefore, gases are highly compressible. In kinetic theory, the pressure of an ideal gas is given by an expression,

P=Nmvavg23V

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The complex anion in Ba₂[Cr(CN)6] is a tetragonally distorted octahedral complex (Dan). Baz[Cr(CN)6] is paramagnetic at room temperature with S = 1. Assume that the complex is a low-spin complex. a) Identify if the [Cr(CN)6] anionic complex has 4 long and 2 short bonds (left side of figure) or if the complex has 4 short and 2 long bonds (right side of figure) with respect to Oh symmetry. Use crystal field theory to answer this question. Explain/rationalize your decision. Can the provided information decide on the order of orbital energies? Dah Tetragonal Distortion ய Dab z-compression z-elongation x and y elongation O symmetry x and y compression E eg d² dx²-y² t2g dxy dxz dyz Question 4 a) continued: Provide your explanations in the space below. b) At low temperatures Ba₂[Cr(CN)6] is ferromagnetically ordered with a phase transition to a paramagnetic phase at Tc = 150K. Sketch the magnetic susceptibility vs. temperature in the diagram below. Indicate Tc as well as the paramagnetic and…

Chapter 19 Solutions

Physical Chemistry

Ch. 19 - Prob. 19.11ECh. 19 - Interstellar space can be considered as having...Ch. 19 - Prob. 19.13ECh. 19 - SF6 is a gas at room temperature, 295K. What is...Ch. 19 - Prob. 19.15ECh. 19 - Prob. 19.16ECh. 19 - If relativistic effects were ignored, what...Ch. 19 - Prob. 19.18ECh. 19 - Prob. 19.19ECh. 19 - Prob. 19.20ECh. 19 - Prob. 19.21ECh. 19 - Prob. 19.22ECh. 19 - Prob. 19.23ECh. 19 - Prob. 19.24ECh. 19 - What is the ratio of vrms/vmostprob for any gas at...Ch. 19 - Prob. 19.26ECh. 19 - Prob. 19.27ECh. 19 - Prob. 19.28ECh. 19 - Prob. 19.29ECh. 19 - Prob. 19.30ECh. 19 - Prob. 19.31ECh. 19 - The previous exercise gives an expression for...Ch. 19 - Prob. 19.33ECh. 19 - Prob. 19.34ECh. 19 - Prob. 19.35ECh. 19 - What must the pressure be if the mean free path of...Ch. 19 - Prob. 19.37ECh. 19 - Prob. 19.38ECh. 19 - Prob. 19.39ECh. 19 - Explain why the molecular diameter for argon, at...Ch. 19 - Prob. 19.41ECh. 19 - Prob. 19.42ECh. 19 - Prob. 19.43ECh. 19 - A 1.00-mol sample of Xe gas is kept at a...Ch. 19 - Prob. 19.45ECh. 19 - Prob. 19.46ECh. 19 - Prob. 19.47ECh. 19 - Prob. 19.48ECh. 19 - Prob. 19.49ECh. 19 - Consider a gas mixture containing equal...Ch. 19 - The inverse of the collision rate, 1/z, is the...Ch. 19 - Prob. 19.52ECh. 19 - Prob. 19.53ECh. 19 - Prob. 19.54ECh. 19 - Prob. 19.55ECh. 19 - Estimate the rate at which Hg effuses out a hole...Ch. 19 - Prob. 19.57ECh. 19 - Knudsen effusion cells are used to determine vapor...Ch. 19 - Prob. 19.59ECh. 19 - Prob. 19.60ECh. 19 - Prob. 19.61ECh. 19 - Prob. 19.62ECh. 19 - Prob. 19.63ECh. 19 - Prob. 19.64ECh. 19 - Prob. 19.65ECh. 19 - Prob. 19.66ECh. 19 - Prob. 19.67ECh. 19 - Prob. 19.68ECh. 19 - Prob. 19.69ECh. 19 - Prob. 19.70ECh. 19 - Prob. 19.71ECh. 19 - Prob. 19.72ECh. 19 - Prob. 19.73E
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