Chapter 19, Problem 19.106SP

Interpretation Introduction

Interpretation:

The value of $\text{pH}$ for the given cell diagram of ${\text{H}}_{\text{2}}\text{/Ni}$ in the anode compartment is to be determined.

Concept introduction:

The substances that have a higher reduction potential will undergo reduction at the cathode, while the substances that have a lower reduction potential will undergo oxidation at the anode.

The expression to calculate the cell potential is as follows:

${\text{E}}_{\text{cell}}={\text{E}}_{\text{cell}}^o-\frac{0.0592}{\text{n}}\log {\text{K}}_{\text{eq}}$

The expression to calculate $\text{pH}$ of the solution is shown below:

$\text{pH}=-\log \left[{\text{H}}^{+}\right]$