Concept explainers
(a)
Interpretation:
To identify the disaccharide that fits best in the ordinary table sugar
Concept Introduction :
A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number 1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.
(b)
Interpretation:
Toidentify the disaccharide that fits best in the given description.
Found in milk and milk products
Concept Introduction :
A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number 1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.
(c)
Interpretation:
To identify the disaccharide that fits best in the given description.
Also called malt sugar
Concept Introduction :
A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number 1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.
(d)
Interpretation:
To identify the disaccharide that fits best in the given description.
Contains galactose and glucose
Concept Introduction :
A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number 1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.
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Chapter 18 Solutions
EBK BASIC CHEMISTRY
- (30 MARKS) Give the major product(s ) formed including relevant stereochemistry or the complete reaction conditions for the following reactions. More than one step may be required for each reaction arrow, in which case the steps must be numbered 1), 2) etc. (2 marks each box) h) i) h) OH i) HO H3PO4, heat 2 Brarrow_forwardNonearrow_forwardIndicate which option is false(A). Resistivity has a residual component and a thermal component.(B). In some materials resistivity increases with T and in others it decreases.(C). In insulating materials, resistivity is very low.arrow_forward
- In ceramic materials, in relation to polymorphism, the same substance crystallizes differently when external conditions vary. Is this correct?arrow_forwardIndicate the type of bond that is considered to be a hydrogen bond.(A). Permanent dipole-dipole interaction between polar molecules.(B). Mixed ionic-covalent bond.(C). Principal interatomic bond(D). Van del Waals forces.arrow_forwardRetro aldol: NaOH H₂O H NaOH & d H₂O Harrow_forward
- Draw the product of the reaction shown below. Ignore inorganic byproducts. H conc. HBr Drawing Qarrow_forwardCalculate the atomic packing factor of diamond knowing that the number of Si atoms per cm3 is 2.66·1022 and that the atomic radii of silicon and oxygen are, respectively, 0.038 and 0.117 nm.arrow_forwardA pdf file of your hand drawn, stepwise mechanisms for the reactions. For each reaction in the assignment, you must write each mechanism three times (there are 10 reactions, so 30 mechanisms). (A) do the work on a tablet and save as a pdf., it is expected to write each mechanism out and NOT copy and paste the mechanism after writing it just once. Everything should be drawn out stepwise and every bond that is formed and broken in the process of the reaction, and is expected to see all relevant lone pair electrons and curved arrows. Aldol: NaOH HO H Δ NaOH Δarrow_forward
- Nonearrow_forwardDraw structures corresponding to the following names and give IUPAC names for the following compounds: (8 Point) a) b) c) CH3 CH2CH3 CH3CHCH2CH2CH CH3 C=C H3C H H2C=C=CHCH3 d) CI e) (3E,5Z)-2,6-Dimethyl-1,3,5,7-octatetraene f) (Z)-4-bromo-3-methyl-3-penten-1-yne g) cis-1-Bromo-2-ethylcyclopentane h) (5R)-4,4,5-trichloro-3,3-dimethyldecanearrow_forwardNonearrow_forward
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