
Concept explainers
(a)
Interpretation:
To classify the given monosaccharide as aldohexose, aldopentose, ketopentose or ketohexose.
Concept Introduction :
Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components. They contain about three to seven carbon atoms in total and one of them is a carbonyl group and rest of the carbon atoms are attached to the hydroxyl groups. If a given monosaccharide will contain five carbon atoms in total, then it is called as a pentose, if the number of carbon atoms is six, then it will be known as a hexose. An aldohexose refers to a monosaccharide which contains six carbon atoms and the carbonyl group is an aldehydic group (CH=O). On the other hand a ketohexose refers to the monosaccharide which contains a
(b)
Interpretation:
To classify the given monosaccharide as aldohexose, aldopentose, ketopentose or ketohexose.
Concept Introduction :
Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components .They contain about three to seven carbon atoms in total and one of them is a carbonyl group and rest of the carbon atoms are attached to the hydroxyl groups. If a given monosaccharide will contain five carbon atoms in total ,then it is called as a pentose , if the number of carbon atoms is six, then it will be known as a hexose. An aldohexose refers to a monosaccharide which contains six carbon atoms and the carbonyl group is an aldehydic group (CH=O). On the other hand a ketohexose refers to the monosaccharide which contains a ketonic group (C=O), and six carbon atoms in its carbon skeleton.

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Chapter 18 Solutions
EBK BASIC CHEMISTRY
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- draw skeletal structures for the minor products of the reaction.arrow_forward1. Provide missing starting materials, reagents, products. If a product cannot be made, write NP (not possible) in the starting material box. C7H12O Ph HO H 1) 03-78 C 2) Me₂S + Ph .H OH + 2nd stereoisomer OH Ph D + enantiomer cat OsO 4 NMO H2O acetonearrow_forwardPlease note that it is correct and explains it rightly:Indicate the correct option. The proportion of O, C and H in the graphite oxide is:a) Constant, for the quantities of functional groups of acids, phenols, epoxy, etc. its constants.b) Depending on the preparation method, as much oxidant as the graphite is destroyed and it has less oxygen.c) Depends on the structure of the graphic being processed, whether it can be more tridimensional or with larger crystals, or with smaller crystals and with more edges.arrow_forward
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