To classify the given saccharide as mono, di, tri or polysaccharide. Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

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Answer 1

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 18, Problem 75UTC

(a)

Interpretation Introduction

Interpretation : To classify the given saccharide as mono, di, tri or polysaccharide.

Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

(a)

Expert Solution

Answer to Problem 75UTC

Melezitose is a tri-saccharide as it is composed of three monosaccharide units.

Explanation of Solution

Given:

EBK BASIC CHEMISTRY , Chapter 18, Problem 75UTC

In the given structure of molecule there are three sugar molecules bonded with each other. Hence there are three monosaccharide units bonded to each other by two glycosidic linkages that make it a tri-saccharide molecule.

(b)

Interpretation Introduction

Interpretation : To identify the keto and aldohexose present in melezitose.

Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

(b)

Expert Solution

Answer to Problem 75UTC

Melezitose is composed of two aldohexose (glucose) and one ketohexose (fructose) units.

Explanation of Solution

In the given structure of molecule there are three sugar molecules; out of which two are pyranose rings with total 6 C atoms hence they should be aldohexose monosaccharides whereas one is furanose ring bonded with two −CH₂OH groups at both terminals that proves it as a ketohexose. Hence Melezitose is composed of two aldohexose and one ketohexose units.

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Answer 2

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 18, Problem 75UTC

(a)

Interpretation Introduction

Interpretation : To classify the given saccharide as mono, di, tri or polysaccharide.

Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

(a)

Expert Solution

Answer to Problem 75UTC

Melezitose is a tri-saccharide as it is composed of three monosaccharide units.

Explanation of Solution

Given:

EBK BASIC CHEMISTRY , Chapter 18, Problem 75UTC

In the given structure of molecule there are three sugar molecules bonded with each other. Hence there are three monosaccharide units bonded to each other by two glycosidic linkages that make it a tri-saccharide molecule.

(b)

Interpretation Introduction

Interpretation : To identify the keto and aldohexose present in melezitose.

Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

(b)

Expert Solution

Answer to Problem 75UTC

Melezitose is composed of two aldohexose (glucose) and one ketohexose (fructose) units.

Explanation of Solution

In the given structure of molecule there are three sugar molecules; out of which two are pyranose rings with total 6 C atoms hence they should be aldohexose monosaccharides whereas one is furanose ring bonded with two −CH₂OH groups at both terminals that proves it as a ketohexose. Hence Melezitose is composed of two aldohexose and one ketohexose units.

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Answer 3

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 18, Problem 75UTC

(a)

Interpretation Introduction

Interpretation : To classify the given saccharide as mono, di, tri or polysaccharide.

Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

(a)

Expert Solution

Answer to Problem 75UTC

Melezitose is a tri-saccharide as it is composed of three monosaccharide units.

Explanation of Solution

Given:

EBK BASIC CHEMISTRY , Chapter 18, Problem 75UTC

In the given structure of molecule there are three sugar molecules bonded with each other. Hence there are three monosaccharide units bonded to each other by two glycosidic linkages that make it a tri-saccharide molecule.

(b)

Interpretation Introduction

Interpretation : To identify the keto and aldohexose present in melezitose.

Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

(b)

Expert Solution

Answer to Problem 75UTC

Melezitose is composed of two aldohexose (glucose) and one ketohexose (fructose) units.

Explanation of Solution

In the given structure of molecule there are three sugar molecules; out of which two are pyranose rings with total 6 C atoms hence they should be aldohexose monosaccharides whereas one is furanose ring bonded with two −CH₂OH groups at both terminals that proves it as a ketohexose. Hence Melezitose is composed of two aldohexose and one ketohexose units.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 18, Problem 75UTC

(a)

Interpretation Introduction

Interpretation : To classify the given saccharide as mono, di, tri or polysaccharide.

Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

(a)

Expert Solution

Answer to Problem 75UTC

Melezitose is a tri-saccharide as it is composed of three monosaccharide units.

Explanation of Solution

Given:

EBK BASIC CHEMISTRY , Chapter 18, Problem 75UTC

In the given structure of molecule there are three sugar molecules bonded with each other. Hence there are three monosaccharide units bonded to each other by two glycosidic linkages that make it a tri-saccharide molecule.

(b)

Interpretation Introduction

Interpretation : To identify the keto and aldohexose present in melezitose.

Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

(b)

Expert Solution

Answer to Problem 75UTC

Melezitose is composed of two aldohexose (glucose) and one ketohexose (fructose) units.

Explanation of Solution

In the given structure of molecule there are three sugar molecules; out of which two are pyranose rings with total 6 C atoms hence they should be aldohexose monosaccharides whereas one is furanose ring bonded with two −CH₂OH groups at both terminals that proves it as a ketohexose. Hence Melezitose is composed of two aldohexose and one ketohexose units.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 18, Problem 75UTC

(a)

Interpretation Introduction

Interpretation : To classify the given saccharide as mono, di, tri or polysaccharide.

Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

(a)

Expert Solution

Answer to Problem 75UTC

Melezitose is a tri-saccharide as it is composed of three monosaccharide units.

Explanation of Solution

Given:

EBK BASIC CHEMISTRY , Chapter 18, Problem 75UTC

In the given structure of molecule there are three sugar molecules bonded with each other. Hence there are three monosaccharide units bonded to each other by two glycosidic linkages that make it a tri-saccharide molecule.

(b)

Interpretation Introduction

Interpretation : To identify the keto and aldohexose present in melezitose.

Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

(b)

Expert Solution

Answer to Problem 75UTC

Melezitose is composed of two aldohexose (glucose) and one ketohexose (fructose) units.

Explanation of Solution

In the given structure of molecule there are three sugar molecules; out of which two are pyranose rings with total 6 C atoms hence they should be aldohexose monosaccharides whereas one is furanose ring bonded with two −CH₂OH groups at both terminals that proves it as a ketohexose. Hence Melezitose is composed of two aldohexose and one ketohexose units.

Answer 6

Chapter 18, Problem 75UTC

(a)

Interpretation Introduction

Interpretation : To classify the given saccharide as mono, di, tri or polysaccharide.

Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

(a)

Expert Solution

Answer to Problem 75UTC

Melezitose is a tri-saccharide as it is composed of three monosaccharide units.

Explanation of Solution

Given:

EBK BASIC CHEMISTRY , Chapter 18, Problem 75UTC

In the given structure of molecule there are three sugar molecules bonded with each other. Hence there are three monosaccharide units bonded to each other by two glycosidic linkages that make it a tri-saccharide molecule.

Answer 7

Chapter 18, Problem 75UTC

(a)

Interpretation Introduction

Interpretation : To classify the given saccharide as mono, di, tri or polysaccharide.

Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

Answer 8

(a)

Expert Solution

Answer to Problem 75UTC

Melezitose is a tri-saccharide as it is composed of three monosaccharide units.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Given:

EBK BASIC CHEMISTRY , Chapter 18, Problem 75UTC

In the given structure of molecule there are three sugar molecules bonded with each other. Hence there are three monosaccharide units bonded to each other by two glycosidic linkages that make it a tri-saccharide molecule.

Answer 13

(b)

Interpretation Introduction

Interpretation : To identify the keto and aldohexose present in melezitose.

Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

(b)

Expert Solution

Answer to Problem 75UTC

Melezitose is composed of two aldohexose (glucose) and one ketohexose (fructose) units.

Explanation of Solution

In the given structure of molecule there are three sugar molecules; out of which two are pyranose rings with total 6 C atoms hence they should be aldohexose monosaccharides whereas one is furanose ring bonded with two −CH₂OH groups at both terminals that proves it as a ketohexose. Hence Melezitose is composed of two aldohexose and one ketohexose units.

Answer 14

(b)

Interpretation Introduction

Interpretation : To identify the keto and aldohexose present in melezitose.

Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

Answer 15

(b)

Expert Solution

Answer to Problem 75UTC

Melezitose is composed of two aldohexose (glucose) and one ketohexose (fructose) units.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

In the given structure of molecule there are three sugar molecules; out of which two are pyranose rings with total 6 C atoms hence they should be aldohexose monosaccharides whereas one is furanose ring bonded with two −CH₂OH groups at both terminals that proves it as a ketohexose. Hence Melezitose is composed of two aldohexose and one ketohexose units.

Answer 20

Ch. 18.1 - Prob. 1PP Ch. 18.1 - Prob. 2PP Ch. 18.1 - Prob. 3PP Ch. 18.1 - Prob. 4PP Ch. 18.1 - Prob. 5PP Ch. 18.1 - Prob. 6PP Ch. 18.1 - Prob. 7PP Ch. 18.1 - Prob. 8PP Ch. 18.1 - Prob. 9PP Ch. 18.1 - Prob. 10PP

To classify the given saccharide as mono, di, tri or polysaccharide. Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

Concept explainers

Interpretation : To classify the given saccharide as mono, di, tri or polysaccharide.

Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

Answer to Problem 75UTC

Explanation of Solution

Interpretation : To identify the keto and aldohexose present in melezitose.

Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

Answer to Problem 75UTC

Explanation of Solution

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Chapter 18 Solutions

To classify the given saccharide as mono, di, tri or polysaccharide. Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

Concept explainers

Interpretation : To classify the given saccharide as mono, di, tri or polysaccharide. Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

Answer to Problem 75UTC

Explanation of Solution

Interpretation : To identify the keto and aldohexose present in melezitose. Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

Answer to Problem 75UTC

Explanation of Solution

Want to see more full solutions like this?

Chapter 18 Solutions

Interpretation : To classify the given saccharide as mono, di, tri or polysaccharide.

Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.

Interpretation : To identify the keto and aldohexose present in melezitose.

Concept Introduction : Carbohydrates are composed of certain monomer units called as monosaccharides. Monosaccharides are polyhydroxy aldehyde and ketones which are bonded with each other to form polysaccharides.