Whether the isomaltose is a monosaccharide, disaccharide or polysaccharide should be identified. Concept Introduction : Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C n H 2 n O n where n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

Question

Want to see the full answer?

Answer 1

Question

Chapter 18.2, Problem 15PP

(a)

Interpretation Introduction

Interpretation:

Whether the isomaltose is a monosaccharide, disaccharide or polysaccharide should be identified.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

(b)

Interpretation Introduction

Interpretation:

To determine the monosaccharide unit present in isomlatose.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

(c)

Interpretation Introduction

Interpretation:

The type ofglycosidiclinkage present in isomlatose should be determined.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

(d)

Interpretation Introduction

Interpretation:

To state the form of isomaltose in the given structure.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Which synthesis of a Grignard reagent would fail to occur as written? Why is the correct answer D? Please explain what is happening. Please include a detailed explanation and a drawing of steps needed to understand the reaction or question.

Draw the structure of the major organic product(s) of the reaction. H3C 1. DIBAH, toluene -CH3 + 2. H3O DIBAH = diisobutylaluminum hydride, [(CH3)2CHCH2]2AIH

Which of the following is not an intermediate of the reaction below? Why is the correct answer C? Please explain what is happening. Please include a detailed explanation and a drawing of steps needed to understand the reaction or question.

Answer 2

Question

Chapter 18.2, Problem 15PP

(a)

Interpretation Introduction

Interpretation:

Whether the isomaltose is a monosaccharide, disaccharide or polysaccharide should be identified.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

(b)

Interpretation Introduction

Interpretation:

To determine the monosaccharide unit present in isomlatose.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

(c)

Interpretation Introduction

Interpretation:

The type ofglycosidiclinkage present in isomlatose should be determined.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

(d)

Interpretation Introduction

Interpretation:

To state the form of isomaltose in the given structure.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 18.2, Problem 15PP

(a)

Interpretation Introduction

Interpretation:

Whether the isomaltose is a monosaccharide, disaccharide or polysaccharide should be identified.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

(b)

Interpretation Introduction

Interpretation:

To determine the monosaccharide unit present in isomlatose.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

(c)

Interpretation Introduction

Interpretation:

The type ofglycosidiclinkage present in isomlatose should be determined.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

(d)

Interpretation Introduction

Interpretation:

To state the form of isomaltose in the given structure.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 18.2, Problem 15PP

(a)

Interpretation Introduction

Interpretation:

Whether the isomaltose is a monosaccharide, disaccharide or polysaccharide should be identified.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

(b)

Interpretation Introduction

Interpretation:

To determine the monosaccharide unit present in isomlatose.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

(c)

Interpretation Introduction

Interpretation:

The type ofglycosidiclinkage present in isomlatose should be determined.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

(d)

Interpretation Introduction

Interpretation:

To state the form of isomaltose in the given structure.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 18.2, Problem 15PP

(a)

Interpretation Introduction

Interpretation:

Whether the isomaltose is a monosaccharide, disaccharide or polysaccharide should be identified.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

(b)

Interpretation Introduction

Interpretation:

To determine the monosaccharide unit present in isomlatose.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

(c)

Interpretation Introduction

Interpretation:

The type ofglycosidiclinkage present in isomlatose should be determined.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

(d)

Interpretation Introduction

Interpretation:

To state the form of isomaltose in the given structure.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

Answer 6

Chapter 18.2, Problem 15PP

(a)

Interpretation Introduction

Interpretation:

Whether the isomaltose is a monosaccharide, disaccharide or polysaccharide should be identified.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

Answer 7

Chapter 18.2, Problem 15PP

(a)

Interpretation Introduction

Interpretation:

Whether the isomaltose is a monosaccharide, disaccharide or polysaccharide should be identified.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

Answer 8

(b)

Interpretation Introduction

Interpretation:

To determine the monosaccharide unit present in isomlatose.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

Answer 9

(b)

Interpretation Introduction

Interpretation:

To determine the monosaccharide unit present in isomlatose.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

Answer 10

(c)

Interpretation Introduction

Interpretation:

The type ofglycosidiclinkage present in isomlatose should be determined.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

Answer 11

(c)

Interpretation Introduction

Interpretation:

The type ofglycosidiclinkage present in isomlatose should be determined.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

Answer 12

(d)

Interpretation Introduction

Interpretation:

To state the form of isomaltose in the given structure.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

Answer 13

(d)

Interpretation Introduction

Interpretation:

To state the form of isomaltose in the given structure.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is C_nH₂_nO_nwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 17

Ch. 18.1 - Prob. 1PP Ch. 18.1 - Prob. 2PP Ch. 18.1 - Prob. 3PP Ch. 18.1 - Prob. 4PP Ch. 18.1 - Prob. 5PP Ch. 18.1 - Prob. 6PP Ch. 18.1 - Prob. 7PP Ch. 18.1 - Prob. 8PP Ch. 18.1 - Prob. 9PP Ch. 18.1 - Prob. 10PP

Solution Summary: The author explains that isomaltose contains two monosaccharides in its structure, which are joined together by a glycosidic linkage.

Concept explainers

Want to see the full answer?

Chapter 18 Solutions