An Introduction to Physical Science
14th Edition
ISBN: 9781305079137
Author: James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher: Cengage Learning
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Chapter 18.1, Problem 18.1CE
To determine
The distance (in parsecs and light-years) to sirius, the brightest star in the night sky.
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15: A star has a parallax angle of 0.0270 arcseconds and an apparent magnitude of 4.641. What is the distance to this star? Answer: 37
16: What is the absolute magnitude of this star? Answer:1.8
17: Is this star more or less luminous than the Sun? Answer "M" for More luminous or "L" for Less luminous. (HINT: the absolute magnitude of the Sun is 4.8) Answer: M
18: What is the luminosity of this star? (HINT: The luminosity of the Sun is 3.85×1026 W.)
Please answer question #18, #15-17 are correct, the photos provide the work for them.
Use a diagram to explain what is meant by the parallax angle, p, for a star observed twice from Earth, with a 6-month interval between each observation. Hence define the parsec, and calculate its value in astronomical units and metres. The star Betelgeuse is observed to have a parallax angle p = 4.5 × 10−3 arcseconds. State the distance of Betelgeuse in units of parsecs and light years.
The nearest star to our solar system is 4.29 light years away. How much is thisdistance in terms of parsecs? How much parallax would this star (named Alpha Centauri) show when viewed from two locations of the Earth six months apart in its orbit around the Sun ?
Chapter 18 Solutions
An Introduction to Physical Science
Ch. 18.1 - How is the position of a star designated in the...Ch. 18.1 - Prob. 2PQCh. 18.1 - Prob. 18.1CECh. 18.2 - Prob. 1PQCh. 18.2 - Prob. 2PQCh. 18.3 - Prob. 1PQCh. 18.3 - Prob. 2PQCh. 18.4 - Prob. 1PQCh. 18.4 - Prob. 2PQCh. 18.5 - Prob. 1PQ
Ch. 18.5 - Prob. 2PQCh. 18.6 - Prob. 1PQCh. 18.6 - Prob. 2PQCh. 18.7 - Prob. 1PQCh. 18.7 - Prob. 2PQCh. 18.7 - Prob. 18.2CECh. 18 - Prob. AMCh. 18 - Prob. BMCh. 18 - Prob. CMCh. 18 - Prob. DMCh. 18 - Prob. EMCh. 18 - Prob. FMCh. 18 - Prob. GMCh. 18 - Prob. HMCh. 18 - Prob. IMCh. 18 - Prob. JMCh. 18 - Prob. KMCh. 18 - Prob. LMCh. 18 - Prob. MMCh. 18 - Prob. NMCh. 18 - Prob. OMCh. 18 - Prob. PMCh. 18 - Prob. QMCh. 18 - Prob. RMCh. 18 - Prob. SMCh. 18 - Prob. TMCh. 18 - Prob. UMCh. 18 - Prob. VMCh. 18 - Prob. WMCh. 18 - Prob. XMCh. 18 - Prob. YMCh. 18 - Prob. ZMCh. 18 - Prob. AAMCh. 18 - What is the point on the celestial sphere...Ch. 18 - Prob. 2MCCh. 18 - Prob. 3MCCh. 18 - Prob. 4MCCh. 18 - Prob. 5MCCh. 18 - Prob. 6MCCh. 18 - Prob. 7MCCh. 18 - What force keeps the all stars from flying apart?...Ch. 18 - Prob. 9MCCh. 18 - Prob. 10MCCh. 18 - Prob. 11MCCh. 18 - Prob. 12MCCh. 18 - Prob. 13MCCh. 18 - Prob. 14MCCh. 18 - Prob. 15MCCh. 18 - Prob. 16MCCh. 18 - Prob. 17MCCh. 18 - Prob. 18MCCh. 18 - Prob. 19MCCh. 18 - Prob. 20MCCh. 18 - The apparent change of the position of a star due...Ch. 18 - Prob. 2FIBCh. 18 - Prob. 3FIBCh. 18 - Prob. 4FIBCh. 18 - Prob. 5FIBCh. 18 - Prob. 6FIBCh. 18 - Prob. 7FIBCh. 18 - Prob. 8FIBCh. 18 - Prob. 9FIBCh. 18 - Prob. 10FIBCh. 18 - Prob. 11FIBCh. 18 - Prob. 12FIBCh. 18 - Prob. 13FIBCh. 18 - Prob. 14FIBCh. 18 - Prob. 15FIBCh. 18 - Prob. 16FIBCh. 18 - Prob. 17FIBCh. 18 - Prob. 18FIBCh. 18 - Prob. 19FIBCh. 18 - Prob. 20FIBCh. 18 - Prob. 1SACh. 18 - Prob. 2SACh. 18 - Prob. 3SACh. 18 - What is the vernal equinox, and what does it have...Ch. 18 - Prob. 5SACh. 18 - Prob. 6SACh. 18 - Prob. 7SACh. 18 - Prob. 8SACh. 18 - Prob. 9SACh. 18 - Prob. 10SACh. 18 - Prob. 11SACh. 18 - Prob. 12SACh. 18 - Prob. 13SACh. 18 - Prob. 14SACh. 18 - Prob. 15SACh. 18 - Prob. 16SACh. 18 - Prob. 17SACh. 18 - Prob. 18SACh. 18 - Prob. 19SACh. 18 - Prob. 20SACh. 18 - Prob. 21SACh. 18 - Prob. 22SACh. 18 - Prob. 23SACh. 18 - Prob. 24SACh. 18 - Prob. 25SACh. 18 - Prob. 26SACh. 18 - Prob. 27SACh. 18 - Prob. 28SACh. 18 - Prob. 29SACh. 18 - Prob. 30SACh. 18 - Prob. 31SACh. 18 - Prob. 32SACh. 18 - Prob. 33SACh. 18 - Prob. 34SACh. 18 - Prob. 35SACh. 18 - Prob. 36SACh. 18 - Prob. 37SACh. 18 - Prob. 38SACh. 18 - Prob. 39SACh. 18 - State three experimental findings that support the...Ch. 18 - Prob. 41SACh. 18 - Prob. 42SACh. 18 - Prob. 1VCCh. 18 - Prob. 1AYKCh. 18 - Prob. 2AYKCh. 18 - Prob. 3AYKCh. 18 - If you went outside on a clear night to locate...Ch. 18 - Prob. 5AYKCh. 18 - Prob. 6AYKCh. 18 - What major factor determines the future of the...Ch. 18 - Find the distance in parsecs to the star Altair,...Ch. 18 - The bright star Sirius has a parallax angle of...Ch. 18 - Calculate the number of seconds in a year (365...Ch. 18 - Prob. 4ECh. 18 - Prob. 5ECh. 18 - Prob. 6ECh. 18 - Prob. 7ECh. 18 - Prob. 8ECh. 18 - Prob. 9ECh. 18 - Prob. 10ECh. 18 - Prob. 11ECh. 18 - If Hubbles constant had a value of 75 km/s/Mpc,...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- As seen from Earth, the Sun has an apparent magnitude of about 26.7 . What is the apparent magnitude of the Sun as seen from Saturn, about 10 AU away? (Remember that one AU is the distance from Earth to the Sun and that the brightness decreases as the inverse square of the distance.) Would the Sun still be the brightest star in the sky?arrow_forwardThe star Spica is observed to have a parallax of 0.012000. How far away is it in parsecs answers to three significant figures.arrow_forwardOne of the closest stars to the sun has a parallax of 0.5 arcseconds. What is the distance to this star, in parsecs?arrow_forward
- What is the parallax of a star that is 150 pc from Earth?arrow_forwardThe apparent visual magnitude of star (Rigel) is 0.12. Use the method of spectroscopic parallax to calculate the approximate distance to Rigel in units of parsecs. The absolute visual magnitude of Rigel is −6.8.arrow_forwardYou measure a star to have a parallax angle of 0.12 arc-seconds What is the distance to this star in parsecs? 8.33 Hint: d = 1/p What is the parallax angle of a different star that is twice as far away as the star from the previous problems? [answer in arc-seconds without including the unit]arrow_forward
- In the parallax method of determining stellar distances, the angle to a star is measured while the earth is on one side of the sun and then again six months later, as in the diagram below. Assume the earth-sun distance is 1 Astronomical Unit. The parallax angle of Alpha Centauri is 0= 2.1 x 10-4 ° . Find the distance from the sun to a Centauri in light years. Assume a circular orbit for the Earth. a Centauri Earth (June) Earth (December) Sunarrow_forwardFind the distance in parsecs to Vega, which has an annual parallax of 0.129 arcsec. pcarrow_forwardWhich star in the table below is the closest to Earth? Star Name d (parsecs) Parallax (seconds of arc) Spectral Type $$ \delta $$ Cen 0.026 B2 IV HR 4607 0.039 G8 III HR 4758 20 G0 V HR 39801 0.005 M2 I 9 CMa 2.5 A1 V a. $$ \delta $$ Cen b. HR 4607 c. HR 4758 d. HD 39801 e. 9 CMaarrow_forward
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