An Introduction to Physical Science
14th Edition
ISBN: 9781305079137
Author: James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher: Cengage Learning
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Chapter 18, Problem 4E
To determine
The number of miles in light-year, when speed of light is
1.86 × 10 5 mi/s
.
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Calculate the number of miles in a light year using (see picture for the equation) mi/s as the speed.
Hint: The number of seconds in a year,365days,will be useful.
Calculate the number of miles in a light-year, using 1.86 105 mi/s as the speed of light. (Hint: The number of seconds in a year, 365 days, will be useful.) Incorrect: Your answer is incorrect. mi/y
What is the number of miles in a light-year, using (see picture) mi/s as the speed of light?
I know the number of seconds in a year and 365 days will help but confused on how to put it in the equation.
Chapter 18 Solutions
An Introduction to Physical Science
Ch. 18.1 - How is the position of a star designated in the...Ch. 18.1 - Prob. 2PQCh. 18.1 - Prob. 18.1CECh. 18.2 - Prob. 1PQCh. 18.2 - Prob. 2PQCh. 18.3 - Prob. 1PQCh. 18.3 - Prob. 2PQCh. 18.4 - Prob. 1PQCh. 18.4 - Prob. 2PQCh. 18.5 - Prob. 1PQ
Ch. 18.5 - Prob. 2PQCh. 18.6 - Prob. 1PQCh. 18.6 - Prob. 2PQCh. 18.7 - Prob. 1PQCh. 18.7 - Prob. 2PQCh. 18.7 - Prob. 18.2CECh. 18 - Prob. AMCh. 18 - Prob. BMCh. 18 - Prob. CMCh. 18 - Prob. DMCh. 18 - Prob. EMCh. 18 - Prob. FMCh. 18 - Prob. GMCh. 18 - Prob. HMCh. 18 - Prob. IMCh. 18 - Prob. JMCh. 18 - Prob. KMCh. 18 - Prob. LMCh. 18 - Prob. MMCh. 18 - Prob. NMCh. 18 - Prob. OMCh. 18 - Prob. PMCh. 18 - Prob. QMCh. 18 - Prob. RMCh. 18 - Prob. SMCh. 18 - Prob. TMCh. 18 - Prob. UMCh. 18 - Prob. VMCh. 18 - Prob. WMCh. 18 - Prob. XMCh. 18 - Prob. YMCh. 18 - Prob. ZMCh. 18 - Prob. AAMCh. 18 - What is the point on the celestial sphere...Ch. 18 - Prob. 2MCCh. 18 - Prob. 3MCCh. 18 - Prob. 4MCCh. 18 - Prob. 5MCCh. 18 - Prob. 6MCCh. 18 - Prob. 7MCCh. 18 - What force keeps the all stars from flying apart?...Ch. 18 - Prob. 9MCCh. 18 - Prob. 10MCCh. 18 - Prob. 11MCCh. 18 - Prob. 12MCCh. 18 - Prob. 13MCCh. 18 - Prob. 14MCCh. 18 - Prob. 15MCCh. 18 - Prob. 16MCCh. 18 - Prob. 17MCCh. 18 - Prob. 18MCCh. 18 - Prob. 19MCCh. 18 - Prob. 20MCCh. 18 - The apparent change of the position of a star due...Ch. 18 - Prob. 2FIBCh. 18 - Prob. 3FIBCh. 18 - Prob. 4FIBCh. 18 - Prob. 5FIBCh. 18 - Prob. 6FIBCh. 18 - Prob. 7FIBCh. 18 - Prob. 8FIBCh. 18 - Prob. 9FIBCh. 18 - Prob. 10FIBCh. 18 - Prob. 11FIBCh. 18 - Prob. 12FIBCh. 18 - Prob. 13FIBCh. 18 - Prob. 14FIBCh. 18 - Prob. 15FIBCh. 18 - Prob. 16FIBCh. 18 - Prob. 17FIBCh. 18 - Prob. 18FIBCh. 18 - Prob. 19FIBCh. 18 - Prob. 20FIBCh. 18 - Prob. 1SACh. 18 - Prob. 2SACh. 18 - Prob. 3SACh. 18 - What is the vernal equinox, and what does it have...Ch. 18 - Prob. 5SACh. 18 - Prob. 6SACh. 18 - Prob. 7SACh. 18 - Prob. 8SACh. 18 - Prob. 9SACh. 18 - Prob. 10SACh. 18 - Prob. 11SACh. 18 - Prob. 12SACh. 18 - Prob. 13SACh. 18 - Prob. 14SACh. 18 - Prob. 15SACh. 18 - Prob. 16SACh. 18 - Prob. 17SACh. 18 - Prob. 18SACh. 18 - Prob. 19SACh. 18 - Prob. 20SACh. 18 - Prob. 21SACh. 18 - Prob. 22SACh. 18 - Prob. 23SACh. 18 - Prob. 24SACh. 18 - Prob. 25SACh. 18 - Prob. 26SACh. 18 - Prob. 27SACh. 18 - Prob. 28SACh. 18 - Prob. 29SACh. 18 - Prob. 30SACh. 18 - Prob. 31SACh. 18 - Prob. 32SACh. 18 - Prob. 33SACh. 18 - Prob. 34SACh. 18 - Prob. 35SACh. 18 - Prob. 36SACh. 18 - Prob. 37SACh. 18 - Prob. 38SACh. 18 - Prob. 39SACh. 18 - State three experimental findings that support the...Ch. 18 - Prob. 41SACh. 18 - Prob. 42SACh. 18 - Prob. 1VCCh. 18 - Prob. 1AYKCh. 18 - Prob. 2AYKCh. 18 - Prob. 3AYKCh. 18 - If you went outside on a clear night to locate...Ch. 18 - Prob. 5AYKCh. 18 - Prob. 6AYKCh. 18 - What major factor determines the future of the...Ch. 18 - Find the distance in parsecs to the star Altair,...Ch. 18 - The bright star Sirius has a parallax angle of...Ch. 18 - Calculate the number of seconds in a year (365...Ch. 18 - Prob. 4ECh. 18 - Prob. 5ECh. 18 - Prob. 6ECh. 18 - Prob. 7ECh. 18 - Prob. 8ECh. 18 - Prob. 9ECh. 18 - Prob. 10ECh. 18 - Prob. 11ECh. 18 - If Hubbles constant had a value of 75 km/s/Mpc,...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- A light year (LY) is the distance that light travels in one year. 1 LY = 9.46x1015 m. Suppose we have detected a planet that orbits a star that is 104 light years away. How many millions of years would it take us to get there if we used a modern rocket with a maximum speed of 20.0 km/s (about 45,000 mph)? Assume 3 sig figs.arrow_forwardI'm having trouble completing the problem I've attached a picture of below. I was able to find the the Earth's average speed in m/s relative to the sun by doing (2pi*(1.49x10^11))/31536000. But I am struggling to find the average velocity for the same thing over a period of one year in m/s. I was wondering how to calculate that? I've tried doing the (final velocity-initial velocity)/2 but the program doesn't accept my answer when using that approach.arrow_forwardCalculate the number of miles in a light-year, using 1.86 105 mi/s as the speed of light. (Hint: The number of seconds in a year, 365 days, will be useful.)arrow_forward
- A light-year is the distance that light can travel in one year. Similarly, we can define a light-second, light-day, etc. as the distance that light can travel in other time intervals. Calculate the distance represented by each of the following: (Assume that the speed of light is 3 x 10^8m/s) 5 light-minutes 6 light-days 6 light-days, but this time answer in miles (enter just the number with no units)arrow_forwardHow about 11518 light-years? how many sig figs are there?arrow_forwardHow many light years are in one parsec? (Use at least two significant figures)arrow_forward
- (the complete question is in the picture) If the Newtonian constant has units G = [N · m2/kg2], the speed of light has units c = [m/s], the mass has units M = [kg] and the SI unit newtons is equivalentto N = [kg · m/s2], what are the units of the relation GM/c3?A. [kg · s]B. [kg · m2/s]C. [m2/s]D. [s]arrow_forwardSuppose we find an Earth-like planet around one of our nearest stellar neighbors, Alpha Centauri (located only 4.4 light-years away). If we launched a "generation ship" at a constant speed of 1500.00 km/s from Earth with a group of people whose descendants will explore and colonize this planet, how many years before the generation ship reached Alpha Centauri? (Note there are 9.46 ××1012 km in a light-year and 31.6 million seconds in a year.arrow_forwardCalculate the length of one light-year (ca), in metres.arrow_forward
- Recall that Hubble’s Law is given by V=HR; this means that H has units of inverse seconds (1/sec). A convenient laboratory set of units is to give H in km per sec per megaparsec. A parsec is 3.26 light years and the speed of light is 3 X 105 km/sec. Use 3.156 X 107 sec/yr. The first data off the then new Hubble Space telescope suggested a value of H equal to 108 km per sec per megaparsec. What is H in inverse seconds? Hint divide by the number of km in a megaparsec.arrow_forward(a) Astronomers use a special unit to measure distances called astronomical unit (AU) where 1 AU is defined as 92,955,807 miles. They also use another unit called parsecs where 1 parsec is equal to 206,264.4 AU. Convert 1 Zm (zettametre) into kiloparsecs. (Given 1 mi = 1.609 km; 1 km = 1000 m).arrow_forwardWhat is the right ascension in hours, minutes, and seconds of a star at RA 239.768°?arrow_forward
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