
Interpretation:
The yield of metal in smallest mass and largest mass are needed to be identified from the given options for the given solution.
Concept Introduction:
The total number of charges that flow through the circuit is impact on the amount of metal deposited on the electrode. It can be calculated in successive steps. Since coulomb is the amount of electric charge flowing in a circuit in 1s, when current is 1A. So the above statement can be represented by the following equation.
On dividing the number of charges with Faraday constant we can get the number of moles of electron
From knowing the number of mole of electrons and using the stoichiometry of the reaction, the number of moles of the substance reduced or oxidized can be determined.

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Chapter 18 Solutions
Chemistry: Atoms First
- + C8H16O2 (Fatty acid) + 11 02 → 8 CO2 a. Which of the above are the reactants? b. Which of the above are the products? H2o CO₂ c. Which reactant is the electron donor? Futty acid d. Which reactant is the electron acceptor? e. Which of the product is now reduced? f. Which of the products is now oxidized? 02 #20 102 8 H₂O g. Where was the carbon initially in this chemical reaction and where is it now that it is finished? 2 h. Where were the electrons initially in this chemical reaction and where is it now that it is finished?arrow_forward→ Acetyl-CoA + 3NAD+ + 1FAD + 1ADP 2CO2 + CoA + 3NADH + 1FADH2 + 1ATP a. Which of the above are the reactants? b. Which of the above are the products? c. Which reactant is the electron donor? d. Which reactants are the electron acceptors? e. Which of the products are now reduced? f. Which product is now oxidized? g. Which process was used to produce the ATP? h. Where was the energy initially in this chemical reaction and where is it now that it is finished? i. Where was the carbon initially in this chemical reaction and where is it now that it is finished? j. Where were the electrons initially in this chemical reaction and where is it now that it is finished?arrow_forwardRank each of the following substituted benzene molecules in order of which will react fastest (1) to slowest (4) by electrophilic aromatic substitution. OCH 3 (Choose one) OH (Choose one) Br (Choose one) Explanation Check NO2 (Choose one) © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Aarrow_forward
- For each of the substituted benzene molecules below, determine the inductive and resonance effects the substituent will have on the benzene ring, as well as the overall electron-density of the ring compared to unsubstituted benzene. Molecule Inductive Effects O donating O withdrawing O no inductive effects Resonance Effects Overall Electron-Density ○ donating ○ withdrawing O no resonance effects O electron-rich O electron-deficient O similar to benzene Cl O donating O withdrawing ○ donating ○ withdrawing O no inductive effects O no resonance effects O Explanation Check O electron-rich O electron-deficient similar to benzene X © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessarrow_forwardIdentifying electron-donating and For each of the substituted benzene molecules below, determine the inductive and resonance effects the substituent will have on the benzene ring, as well as the overall electron-density of the ring compared to unsubstituted benzene. Molecule Inductive Effects NH2 ○ donating NO2 Explanation Check withdrawing no inductive effects Resonance Effects Overall Electron-Density ○ donating O withdrawing O no resonance effects O donating O withdrawing O donating withdrawing O no inductive effects Ono resonance effects O electron-rich electron-deficient O similar to benzene O electron-rich O electron-deficient O similar to benzene olo 18 Ar 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibilityarrow_forwardRank each of the following substituted benzene molecules in order of which will react fastest (1) to slowest (4) by electrophilic aromatic substitution. Explanation Check Х (Choose one) OH (Choose one) OCH3 (Choose one) OH (Choose one) © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Centerarrow_forward
- Assign R or S to all the chiral centers in each compound drawn below porat bg 9 Br Brarrow_forwarddescrive the energy levels of an atom and howan electron moces between themarrow_forwardRank each set of substituents using the Cahn-Ingold-Perlog sequence rules (priority) by numbering the highest priority substituent 1.arrow_forward
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