
Concept explainers
(a)
Interpretation:
The complete balanced equation for the given reaction and the mass percent of oxalic acid has to be found.
Concept Introduction:
Titration is a widely used method for the determination of unknown concentration of an analyte. In order to determine the unknown concentration, the analyte of known volume is titrated with the titrant of known volume and concentration. The unknown concentration of the analyte is found by the following equation.
Where,
This formula is applicable when one mole of analyte is reacting with one mole of the titrant.
After calculating the unknown concentration of the analyte, its weight is gram is calculated.
Mole is the amount of substance having
Mass percent is the one method that is used to express the concentration of substances in a mixture. It is the ratio of weight of a particular component to the total weight of the sample, multiplied by 100.
(b)
Interpretation:
The complete balanced equation for the given reaction and the mass percent of oxalic acid has to be found.
Concept Introduction:
Titration is a widely used method for the determination of unknown concentration of an analyte. In order to determine the unknown concentration, the analyte of known volume is titrated with the titrant of known volume and concentration. The unknown concentration of the analyte is found by the following equation.
Where,
This formula is applicable when one mole of analyte is reacting with one mole of the titrant.
After calculating the unknown concentration of the analyte, its weight is gram is calculated.
Mole is the amount of substance having Avogadro number of particles. The number of moles of a particular substance is calculated by multiplying the volume of the substance and its concentration.
Mass percent is the one method that is used to express the concentration of substances in a mixture. It is the ratio of weight of a particular component to the total weight of the sample, multiplied by 100.

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Chapter 18 Solutions
Chemistry: Atoms First
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- Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction. For the decomposition reaction of N2O5(g): 2 N2O5(g) · 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 -> NO2 + NO3_(K1) NO2 + NO3 →> N2O5 (k-1) → NO2 + NO3 → NO2 + O2 + NO (K2) NO + N2O5 → NO2 + NO2 + NO2 (K3) Give the expression for the acceptable rate. (A). d[N₂O] dt = -1 2k,k₂[N205] k₁+k₂ d[N₂O5] (B). dt =-k₁[N₂O₂] + k₁[NO2][NO3] - k₂[NO2]³ (C). d[N₂O] dt =-k₁[N₂O] + k₁[N205] - K3 [NO] [N205] (D). d[N2O5] =-k₁[NO] - K3[NO] [N₂05] dtarrow_forwardA 0.10 M solution of acetic acid (CH3COOH, Ka = 1.8 x 10^-5) is titrated with a 0.0250 M solution of magnesium hydroxide (Mg(OH)2). If 10.0 mL of the acid solution is titrated with 20.0 mL of the base solution, what is the pH of the resulting solution?arrow_forwardFor the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3) → Give the expression for the acceptable rate. → → (A). d[N205] dt == 2k,k₂[N₂O₂] k₁+k₁₂ (B). d[N2O5] =-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³ dt (C). d[N2O5] =-k₁[N₂O] + k [NO] - k₂[NO] [NO] d[N2O5] (D). = dt = -k₁[N2O5] - k¸[NO][N₂05] dt Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.arrow_forward
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