Genetics: From Genes to Genomes, 5th edition
5th Edition
ISBN: 9780073525310
Author: Leland H. Hartwell, Michael L. Goldberg, Janice A. Fischer, Leroy Hood, Charles F. Aquadro
Publisher: McGraw-Hill Education
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Chapter 18, Problem 12P
The molecular identity of the fruit fly rugose gene described in Problem 5 has been established. As a result, cDNA clones corresponding to the rugose gene mRNA and antibodies that recognize the Rugose protein are now available.
| a. | How could you use these reagents to determine in which tissues the rugose gene is expressed? Does the expression of the gene in any particular tissue establish that the Rugose protein plays an essential function there? |
| b. | How could these same materials also help you to determine if a newly discovered recessive allele of rugose is a null or a hypomorphic mutation? If a new allele is dominant to wild type, could the mRNA clone or the antibody help you decide if the allele is antimorphic, hypermorphic, or neomorphic? |
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Chapter 18 Solutions
Genetics: From Genes to Genomes, 5th edition
Ch. 18 - Match each of the terms in the left column to the...Ch. 18 - a. If you were interested in the role of a...Ch. 18 - Prob. 3PCh. 18 - Flies homozygous for recessive null mutations in...Ch. 18 - In 1932, H. J. Muller suggested a genetic test to...Ch. 18 - a. Explain how you could use worms transformed...Ch. 18 - Prob. 7PCh. 18 - Sevenless is an unusual receptor protein in that...Ch. 18 - Suppose that you generated flies containing a...Ch. 18 - Drosophila researchers have collected many strains...
Ch. 18 - As an alternative to random mutagenesis,...Ch. 18 - The molecular identity of the fruit fly rugose...Ch. 18 - Prob. 13PCh. 18 - Prob. 14PCh. 18 - Prob. 15PCh. 18 - Some ts alleles are temperature sensitive during...Ch. 18 - Prob. 17PCh. 18 - Hypomorphic alleles of a pleiotropic gene...Ch. 18 - Prob. 19PCh. 18 - Prob. 20PCh. 18 - a. Explain the difference between maternal...Ch. 18 - Prob. 22PCh. 18 - Prob. 23PCh. 18 - Some genes are required both zygotically and...Ch. 18 - How would a human with a mutation in a maternal...Ch. 18 - One important demonstration that Bicoid is an...Ch. 18 - Prob. 27PCh. 18 - Prob. 28PCh. 18 - Wild-type embryos and mutant embryos lacking the...Ch. 18 - The Drosophila even-skipped eve gene has four...Ch. 18 - Prob. 31PCh. 18 - Prob. 32P
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