Explanation Write the expression for the area of the walls include the windows, A = A end walls + A end of attic + A side walls + A roof (I) Here, A is the area of the walls includes the windows, A end walls is the area of the end walls, A end of attic is the area of windows, A side walls is the area of side walls and A roof is the area of the roof. Write the expression for the area of two sides of walls, A = 2 ( l b ) (II) Here, l is the length of the wall and b is the breath of the wall. Using the above equation to (I), A = 2 ( l b ) end walls + 2 ( l b ) end of attic + 2 ( l b ) side walls + 2 ( l b ) roof (III) Write the expression for the power transferred by heat, P = k A Δ T L (IV) Here, P is the power transferred by heat, k is the thermal conductivity of the roof and walls, Δ T is the temperature change and L is the average thickness. Write the expression for the energy transferred through the walls per day by heat, s = P t (V) Here, s is the energy transferred through the walls per day by heat and t is the time taken. Write the expression for the gas needed to replace this transfer, a = s E (VI) Here, a is the gas needed to replace this transfer and E is the energy provided per cubic meter of gas burned. Conclusion: Substitute 8.00 m × 5 .00 m for ( l b ) end walls , 2 × 1 2 × 4.00 m × 4 .00 m ( tan 37.0 o ) for ( l b ) end of attic , 10.0 m × 5.00 m for ( l b ) side walls and 10.0 m ( 4.00 m cos 37.0 ∘ ) in (III) to find A , A = 2 ( 8

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN: 9781133104261

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 17, Problem 81P

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The gas needed to replace the energy transfer.

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Chapter 17, Problem 79P

Chapter 17, Problem 82P

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Principles of Physics: A Calculus-Based Text

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The gas needed to replace the energy transfer.

Solution Summary: The author explains the gas needed to replace the energy transfer. Write the expression for the area of the walls including the windows, the side walls, and the roof.

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Chapter 17 Solutions