
Interpretation:
The illustration that represents an equilibrium mixture have to be shown. The number of molecules of A2B reacted initially have to be stated.
Concept Introduction:

Answer to Problem 72A
The first snapshot illustrates that the container contains 4 molecules of A2B, 2 molecules of A2 and 1 molecule of B2. The second snapshot represents that the container contains 2 molecules of A2B, 4 molecules of A2 and 2 molecules of B2 and the third snapshot represents that the container contains 2 molecules of A2B, 4 molecules of A2 and 2 molecules of B2. Therefore the number of molecules remain constant in the third snapshot. That means the system is in equilibrium and the number of molecules are not changing.
So the second snapshot represents the equilibrium mixture.
From the equation we see that 2 molecules of A2B give 2 molecules of A2 and 1 molecule of B2. The first snapshot illustrates that the container contains 2 molecules of A2 and 1 molecule of B2. That means 2 molecules of A2B reacted initially.
Explanation of Solution
The given chemical equation is-
The first snapshot illustrates that the container contains 4 molecules of A2B, 2 molecules of A2 and 1 molecule of B2. The second snapshot represents that the container contains 2 molecules of A2B, 4 molecules of A2 and 2 molecules of B2 and the third snapshot represents that the container contains 2 molecules of A2B, 4 molecules of A2 and 2 molecules of B2. Therefore the number of molecules remain constant in the third snapshot. That means the system is in equilibrium and the number of molecules are not changing.
So the second snapshot represents the equilibrium mixture.
From the equation we see that 2 molecules of A2B give 2 molecules of A2 and 1 molecule of B2. The first snapshot illustrates that the container contains 2 molecules of A2 and 1 molecule of B2. That means 2 molecules of A2B reacted initially.
Chapter 17 Solutions
World of Chemistry, 3rd edition
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