Chapter 17, Problem 19A

(a)

Interpretation Introduction

Interpretation:The equilibrium expression for the given reaction has to be written. The given reaction is,

  $C_2{H}_6\left(g\right)+C{l}_2\left(g\right)\rightleftharpoons C_2{H}_{5}Cl\left(g\right)+HCl\left(g\right)$

Concept Introduction : For a balanced chemical reaction,

  $aA+bB\rightleftharpoons cC+dD$

The equilibrium expression is ratio of the concentration of the products to the concentration of the reaction. The concentration of each reactant/product is raised to a power corresponding to their coefficient in the balanced equation.

The law of chemical equilibrium is given by the equilibrium expression,

  $K=\frac{{\left[C\right]}^c{\left[D\right]}^d}{{\left[A\right]}^a{\left[B\right]}^b}$

The equilibrium constant is represented as $K.$

Answer to Problem 19A

The equilibrium expression for the reaction is $K=\frac{\left[C_2{H}_{5}Cl\right]\left[HCl\right]}{\left[C_2{H}_6\right]\left[C{l}_2\right]}.$

Explanation of Solution

The given reaction is,

  $C_2{H}_6\left(g\right)+C{l}_2\left(g\right)\rightleftharpoons C_2{H}_{5}Cl\left(g\right)+HCl\left(g\right)$

For a balanced chemical reaction,

  $aA+bB\rightleftharpoons cC+dD$

The equilibrium expression is ratio of the concentration of the products to the concentration of the reaction. The concentration of each reactant/product is raised to a power corresponding to their coefficient in the balanced equation.

Where,

• $A,B,C,D$ are chemical species.
• $a,b,c$ and $d$ are coefficients in the balanced equation.

The law of chemical equilibrium is given by the equilibrium expression,

  $K=\frac{{\left[C\right]}^c{\left[D\right]}^d}{{\left[A\right]}^a{\left[B\right]}^b}$

The equilibrium constant is represented as $K.$

For the given reaction, the equilibrium expression is written as,

  $K=\frac{\left[C_2{H}_{5}Cl\right]\left[HCl\right]}{\left[C_2{H}_6\right]\left[C{l}_2\right]}$

The equilibrium expression for the reaction is $K=\frac{\left[C_2{H}_{5}Cl\right]\left[HCl\right]}{\left[C_2{H}_6\right]\left[C{l}_2\right]}.$

(b)

Interpretation Introduction

Interpretation: The equilibrium expression for the given reaction has to be written. The given reaction is,

  $4N{H}_3\left(g\right)+5O_2\left(g\right)\rightleftharpoons 4NO\left(g\right)+6H_{2}O\left(g\right)$

Concept Introduction : For a balanced chemical reaction,

  $aA+bB\rightleftharpoons cC+dD$

The equilibrium expression is ratio of the concentration of the products to the concentration of the reaction. The concentration of each reactant/product is raised to a power corresponding to their coefficient in the balanced equation.

The law of chemical equilibrium is given by the equilibrium expression,

  $K=\frac{{\left[C\right]}^c{\left[D\right]}^d}{{\left[A\right]}^a{\left[B\right]}^b}$

The equilibrium constant is represented as $K.$

Answer to Problem 19A

The equilibrium expression for the reaction is $K=\frac{{\left[NO\right]}^4{\left[H_{2}O\right]}^6}{{\left[N{H}_3\right]}^4{\left[O_2\right]}^5}.$

Explanation of Solution

The given reaction is,

  $4N{H}_3\left(g\right)+5O_2\left(g\right)\rightleftharpoons 4NO\left(g\right)+6H_{2}O\left(g\right)$

For a balanced chemical reaction,

  $aA+bB\rightleftharpoons cC+dD$

The equilibrium expression is ratio of the concentration of the products to the concentration of the reaction. The concentration of each reactant/product is raised to a power corresponding to their coefficient in the balanced equation.

Where,

• $A,B,C,D$ are chemical species.
• $a,b,c$ and $d$ are coefficients in the balanced equation.

The law of chemical equilibrium is given by the equilibrium expression,

  $K=\frac{{\left[C\right]}^c{\left[D\right]}^d}{{\left[A\right]}^a{\left[B\right]}^b}$

The equilibrium constant is represented as $K.$

For the given reaction, the equilibrium expression is written as,

  $K=\frac{{\left[NO\right]}^4{\left[H_{2}O\right]}^6}{{\left[N{H}_3\right]}^4{\left[O_2\right]}^5}$

The equilibrium expression for the reaction is $K=\frac{{\left[NO\right]}^4{\left[H_{2}O\right]}^6}{{\left[N{H}_3\right]}^4{\left[O_2\right]}^5}.$

(c)

Interpretation Introduction

Interpretation:The equilibrium expression for the given reaction has to be written. The given reaction is,

  $PC{l}_5\left(g\right)\rightleftharpoons PC{l}_3\left(g\right)+C{l}_2\left(g\right)$

Concept introduction: For a balanced chemical reaction,

  $aA+bB\rightleftharpoons cC+dD$

The equilibrium expression is ratio of the concentration of the products to the concentration of the reaction. The concentration of each reactant/product is raised to a power corresponding to their coefficient in the balanced equation.

The law of chemical equilibrium is given by the equilibrium expression,

  $K=\frac{{\left[C\right]}^c{\left[D\right]}^d}{{\left[A\right]}^a{\left[B\right]}^b}$

The equilibrium constant is represented as $K.$

Answer to Problem 19A

The equilibrium expression for the reaction is $K=\frac{\left[PC{l}_3\right]\left[C{l}_2\right]}{\left[PC{l}_5\right]}.$

Explanation of Solution

The given reaction is,

  $PC{l}_5\left(g\right)\rightleftharpoons PC{l}_3\left(g\right)+C{l}_2\left(g\right)$

For a balanced chemical reaction,

  $aA+bB\rightleftharpoons cC+dD$

The equilibrium expression is ratio of the concentration of the products to the concentration of the reaction. The concentration of each reactant/product is raised to a power corresponding to their coefficient in the balanced equation.

Where,

• $A,B,C,D$ are chemical species.
• $a,b,c$ and $d$ are coefficients in the balanced equation.

The law of chemical equilibrium is given by the equilibrium expression,

  $K=\frac{{\left[C\right]}^c{\left[D\right]}^d}{{\left[A\right]}^a{\left[B\right]}^b}$

The equilibrium constant is represented as $K.$

For the given reaction, the equilibrium expression is written as,

  $K=\frac{\left[PC{l}_3\right]\left[C{l}_2\right]}{\left[PC{l}_5\right]}$

The equilibrium expression for the reaction is $K=\frac{\left[PC{l}_3\right]\left[C{l}_2\right]}{\left[PC{l}_5\right]}.$