Chapter 17, Problem 37A

Interpretation Introduction

Interpretation: The possibility to favor or disfavor the production of glucose with an increase in temperature has to be predicted.

Concept introduction: Reactions in which heat is absorbed are called as endothermic reaction. Endothermic reaction yield products of higher energy than the reactants.

Decomposition of calcium carbonate to give calcium oxide and carbon oxide is an example of endothermic reaction.

  $CaC{O}_3\left(s\right)+556kJ\rightleftharpoons CaO\left(s\right)+C{O}_2\left(g\right)$

Answer to Problem 37A

The reaction would favor the production of glucose with an increase in temperature.

Explanation of Solution

The given reaction is,

  $6C{O}_2\left(g\right)+6H_{2}O\left(g\right)\rightleftharpoons C_6{H}_{12}{O}_6\left(s\right)+6O_2\left(g\right)$

The production of glucose with evolution of oxygen gas from carbon dioxide and water is an example of endothermic reaction. Heat is considered as a reactant in endothermic reaction and in endothermic reactions, heat is absorbed.

In endothermic reaction, the equilibrium constant increases with an increase in temperature, therefore the reaction shifts to the right (towards the product).

By Le Chatelier’s principle, the increase in temperature would shift the equilibrium to the right, producing more glucose and oxygen.

The shift in the equilibrium position would be towards the products when there is an increase in temperature for an endothermic reaction. Hence, it would favor in the production of glucose.

Conclusion

The reaction would favor the production of glucose with an increase in temperature since it is an endothermic reaction.