World of Chemistry, 3rd edition
3rd Edition
ISBN: 9781133109655
Author: Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher: Brooks / Cole / Cengage Learning
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Chapter 17, Problem 44A
Interpretation Introduction
Interpretation: The concentration of dinitrogen tetroxide has to be calculated.
Concept introduction: For a balanced
aA+bB⇌cC+dD
The equilibrium expression is ratio of the concentration of the products to the concentration of the reactants. The concentration of each reactant/product is raised to a power corresponding to their coefficient in the balanced equation.
The law of
K=[C]c[D]d[A]a[B]b
The equilibrium constant is represented as K.
Expert Solution & Answer
Answer to Problem 44A
The concentration of dinitrogen tetroxide is 5.4×10-4 M.
Explanation of Solution
The given chemical reaction is,
N2O4(g)⇌2NO2(g)
Given data,
The equilibrium concentration of [NO2] is 0.0021 M.
The equilibrium constant is 8.1×10-3.
For a balanced chemical reaction,
aA+bB⇌cC+dD
Where,
- A,B,C,D are chemical species.
- a,b,c and d are coefficients in the balanced equation.
The equilibrium expression is given as,
K=[C]c[D]d[A]a[B]b
Where,
K is the value of equilibrium constant.
For the given reaction, the expression for equilibrium constant is written as,
K=[NO2]2[N2O4]
Substitute the values of equilibrium concentration of nitrogen dioxide and equilibrium constant in the above expression,
K=[NO2]2[N2O4](8.1×10-3)=(0.0021)2[N2O4]N2O4=5.4×10-4 M
The concentration of dinitrogen tetroxide is 5.4×10-4 M.
Conclusion
The concentration of dinitrogen tetroxide is 5.4×10-4 M.
Chapter 17 Solutions
World of Chemistry, 3rd edition
Ch. 17.1 - Prob. 1RQCh. 17.1 - Prob. 2RQCh. 17.1 - Prob. 3RQCh. 17.1 - Prob. 4RQCh. 17.1 - Prob. 5RQCh. 17.1 - Prob. 6RQCh. 17.1 - Prob. 7RQCh. 17.2 - Prob. 1RQCh. 17.2 - Prob. 2RQCh. 17.2 - Prob. 3RQ
Ch. 17.2 - Prob. 4RQCh. 17.2 - Prob. 5RQCh. 17.3 - Prob. 1RQCh. 17.3 - Prob. 2RQCh. 17.3 - Prob. 3RQCh. 17.3 - Prob. 4RQCh. 17.3 - Prob. 5RQCh. 17.3 - Prob. 6RQCh. 17.3 - Prob. 7RQCh. 17 - Prob. 1ACh. 17 - Prob. 2ACh. 17 - Prob. 3ACh. 17 - Prob. 4ACh. 17 - Prob. 5ACh. 17 - Prob. 6ACh. 17 - Prob. 7ACh. 17 - Prob. 8ACh. 17 - Prob. 9ACh. 17 - Prob. 10ACh. 17 - Prob. 11ACh. 17 - Prob. 12ACh. 17 - Prob. 13ACh. 17 - Prob. 14ACh. 17 - Prob. 15ACh. 17 - Prob. 16ACh. 17 - Prob. 17ACh. 17 - Prob. 18ACh. 17 - Prob. 19ACh. 17 - Prob. 20ACh. 17 - Prob. 21ACh. 17 - Prob. 22ACh. 17 - Prob. 23ACh. 17 - Prob. 24ACh. 17 - Prob. 25ACh. 17 - Prob. 26ACh. 17 - Prob. 27ACh. 17 - Prob. 28ACh. 17 - Prob. 29ACh. 17 - Prob. 30ACh. 17 - Prob. 31ACh. 17 - Prob. 32ACh. 17 - Prob. 33ACh. 17 - Prob. 34ACh. 17 - Prob. 35ACh. 17 - Prob. 36ACh. 17 - Prob. 37ACh. 17 - Prob. 38ACh. 17 - Prob. 39ACh. 17 - Prob. 40ACh. 17 - Prob. 41ACh. 17 - Prob. 42ACh. 17 - Prob. 43ACh. 17 - Prob. 44ACh. 17 - Prob. 45ACh. 17 - Prob. 46ACh. 17 - Prob. 47ACh. 17 - Prob. 48ACh. 17 - Prob. 49ACh. 17 - Prob. 50ACh. 17 - Prob. 51ACh. 17 - Prob. 52ACh. 17 - Prob. 53ACh. 17 - Prob. 54ACh. 17 - Prob. 55ACh. 17 - Prob. 56ACh. 17 - Prob. 57ACh. 17 - Prob. 58ACh. 17 - Prob. 59ACh. 17 - Prob. 60ACh. 17 - Prob. 61ACh. 17 - Prob. 62ACh. 17 - Prob. 63ACh. 17 - Prob. 64ACh. 17 - Prob. 65ACh. 17 - Prob. 66ACh. 17 - Prob. 67ACh. 17 - Prob. 68ACh. 17 - Prob. 69ACh. 17 - Prob. 70ACh. 17 - Prob. 71ACh. 17 - Prob. 72ACh. 17 - Prob. 73ACh. 17 - Prob. 74ACh. 17 - Prob. 75ACh. 17 - Prob. 1STPCh. 17 - Prob. 2STPCh. 17 - Prob. 3STPCh. 17 - Prob. 4STPCh. 17 - Prob. 5STPCh. 17 - Prob. 6STPCh. 17 - Prob. 7STP
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