Study Guide with Student Solutions Manual for Seager/Slabaugh/Hansen's Chemistry for Today: General, Organic, and Biochemistry, 9th Edition
Study Guide with Student Solutions Manual for Seager/Slabaugh/Hansen's Chemistry for Today: General, Organic, and Biochemistry, 9th Edition
9th Edition
ISBN: 9781305968608
Author: Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher: Cengage Learning
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Chapter 17, Problem 17.53E
Interpretation Introduction

Interpretation:

The following structural characteristics are to be matched with their respective polysaccharide.

a. Contains both α(14) and α(16) glycosidic linkages

b. is composed of glucose monosaccharide units

c. Contains acetal linkages between monosaccharide units

d. is composed of highly branched molecular chains

e. is composed of unbranched molecular chains

f. Contains only α(14) glycosidic linkages

g. Contains only β(14) glycosidic linkages

Concept introduction:

A large molecule formed by combining the multiple numbers of monosaccharides is called polysaccharide. These monosaccharides can be same, known as homo-polysaccharide, or different, known as hetero-polysaccharides. A molecule with a straight chain is called linear polysaccharide and that with a branched chain is called a branched polysaccharide.

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Study Guide with Student Solutions Manual for Seager/Slabaugh/Hansen's Chemistry for Today: General, Organic, and Biochemistry, 9th Edition

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