(a)
Interpretation:
The given amine has to be classified as primary, secondary, or tertiary amine.
Concept Introduction:
Amine is an organic derivative. If in ammonia one or more alkyl, cycloalkyl, or aryl groups are substituted instead of hydrogen atom then it is known as amine. Depending on the number of substitution the
Amides are also organic derivative. In an amide, the nitrogen atom is bonded to a carbonyl group. The general structural formula of amide can be given as shown below,
The difference between amine and amide is that in amine, the nitrogen atom is bonded to a hydrocarbon chain. In case of amides, the nitrogen atom is bonded to a carbonyl group.
(b)
Interpretation:
The given amine has to be classified as primary, secondary, or tertiary amine.
Concept Introduction:
Amine is an organic derivative. If in ammonia one or more alkyl, cycloalkyl, or aryl groups are substituted instead of hydrogen atom then it is known as amine. Depending on the number of substitution the amines are classified as primary, secondary or tertiary amine. Primary amine is the one in which only one hydrogen atom in ammonia is replaced by a hydrocarbon group. Secondary amine is the one in which only two hydrogen atoms in ammonia is replaced by a hydrocarbon group. Tertiary amine is the one in which all three hydrogen atoms in ammonia is replaced by a hydrocarbon group. The generalized structural formula for all the amines is,
Amides are also organic derivative. In an amide, the nitrogen atom is bonded to a carbonyl group. The general structural formula of amide can be given as shown below,
The difference between amine and amide is that in amine, the nitrogen atom is bonded to a hydrocarbon chain. In case of amides, the nitrogen atom is bonded to a carbonyl group.
(c)
Interpretation:
The given amine has to be classified as primary, secondary, or tertiary amine.
Concept Introduction:
Amine is an organic derivative. If in ammonia one or more alkyl, cycloalkyl, or aryl groups are substituted instead of hydrogen atom then it is known as amine. Depending on the number of substitution the amines are classified as primary, secondary or tertiary amine. Primary amine is the one in which only one hydrogen atom in ammonia is replaced by a hydrocarbon group. Secondary amine is the one in which only two hydrogen atoms in ammonia is replaced by a hydrocarbon group. Tertiary amine is the one in which all three hydrogen atoms in ammonia is replaced by a hydrocarbon group. The generalized structural formula for all the amines is,
Amides are also organic derivative. In an amide, the nitrogen atom is bonded to a carbonyl group. The general structural formula of amide can be given as shown below,
The difference between amine and amide is that in amine, the nitrogen atom is bonded to a hydrocarbon chain. In case of amides, the nitrogen atom is bonded to a carbonyl group.
(d)
Interpretation:
The given amine has to be classified as primary, secondary, or tertiary amine.
Concept Introduction:
Amine is an organic derivative. If in ammonia one or more alkyl, cycloalkyl, or aryl groups are substituted instead of hydrogen atom then it is known as amine. Depending on the number of substitution the amines are classified as primary, secondary or tertiary amine. Primary amine is the one in which only one hydrogen atom in ammonia is replaced by a hydrocarbon group. Secondary amine is the one in which only two hydrogen atoms in ammonia is replaced by a hydrocarbon group. Tertiary amine is the one in which all three hydrogen atoms in ammonia is replaced by a hydrocarbon group. The generalized structural formula for all the amines is,
Amides are also organic derivative. In an amide, the nitrogen atom is bonded to a carbonyl group. The general structural formula of amide can be given as shown below,
The difference between amine and amide is that in amine, the nitrogen atom is bonded to a hydrocarbon chain. In case of amides, the nitrogen atom is bonded to a carbonyl group.
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Chapter 17 Solutions
EBK GENERAL, ORGANIC, AND BIOLOGICAL CH
- Which representation(s) show polymer structures that are likely to result in rigid, hard materials and those that are likely to result in flexible, stretchable, soft materials?arrow_forward3. Enter the molecular weight of the product obtained from the Williamson Ether Synthesis? OH OH & OH excess CH3l Ag₂Oarrow_forwardPlease answer 1, 2 and 3 on the endarrow_forward
- In the box below, specify which of the given compounds are very soluble in polar aprotic solvents. You may select more than one compound. Choose one or more: NaCl NH4Cl CH3CH2CH2CH2CH2CN CH3CH2OH hexan-2-one NaOH CH3SCH3arrow_forwardOn the following structure, select all of the atoms that could ACCEPT a hydrogen bond. Ignore possible complications of aromaticity. When selecting be sure to click on the center of the atom.arrow_forwardRank the compounds below from lowest to highest melting point.arrow_forward
- 18 Question (1 point) Draw the line structure form of the given partially condensed structure in the box provided. :ÖH HC HC H2 ΙΩ Н2 CH2 CH3 CH3 partially condensed formarrow_forwardsomeone else has already submitted the same question on here and it was the incorrect answer.arrow_forwardThe reaction: 2NO2(g) ⇌ N2O4(g) is an exothermic reaction, ΔH=-58.0 kJ/molrxn at 0°C the KP is 58.If the initial partial pressures of both NO2(g) and N2O4(g) are 2.00 atm:A) Is the reaction at equilibrium? If not, what is the value of Q? B) Which direction will the reaction go to reach equilibrium? C) Use an ICE table to find the equilibrium pressures.arrow_forward
- The dissociation of the weak acid, nitrous acid, HNO2, takes place according to the reaction: HNO2 (aq) ⇌ H+(aq) + NO2–(aq) K=7.2 X 10-4 When 1.00 mole of HNO2 is added to 1.00 L of water, the H+ concentration at equilibrium is 0.0265 M.A) Calculate the value of Q if 1.00 L of water is added? B) How will reaction shift if 1.00 L of water is added?arrow_forwardSuppose a certain copolymer elastomeric material “styrene-butadiene rubber”) contains styrene ("S") monomers –(C8H8)– and butadiene ("B") monomers –(C4H6)– and that their numerical ratio S:B = 1:8. What is the mass ratio mS:mB of the two monomers in the material? What is the molecular mass M of a macromolecule of this copolymer with degree of polymerization n = 60,000? Data: AC = 12.01 u, AH = 1.008 u.arrow_forwardLab Questions from Lab: Gravimetric Determination of Calcium as CaC2O4•H2O What is the purpose of the methyl red indicator? Why does a color change to yellow tell you that the reaction is complete? Why is the precipitate rinsed with ice-cold water in step 4? Why not room temperature or hot water? Why is it important that the funnels be placed in a desiccator before weighing (steps 1 and 5)?arrow_forward
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