Concept explainers
(a)
Interpretation:
Given amide has to be classified as primary, secondary, or tertiary amide.
Concept Introduction:
Organic compounds are the important basis of life. They include gasoline, coal, dyes, and clothing fibers etc. The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds. Organic compounds are found in earth also apart from living organisms. All the organic compounds contain the element carbon. Urea was synthesized in the laboratory which is an organic compound.
Organic compounds contain heteroatom also. Some of them are nitrogen, sulfur, oxygen etc. Nitrogen containing organic compounds are of two important types and they are
One of the
Amides are also classified as primary, secondary, and tertiary amide.
Primary amide is the one that has a nitrogen atom that is bonded to two hydrogen atoms. Primary amides are also known as unsubstituted amides.
Secondary amide is the one that has a nitrogen atom that is bonded to one hydrogen atom and one alkyl (or aryl) group. Secondary amides are also known as monosubstituted amides.
Tertiary amide is the one that has a nitrogen atom that is bonded to two alkyl (or aryl) groups. Tertiary amides are also known as disubstituted amides.
Apart from linear amides, there are also cyclic amides. They are formed by intramolecular condensation. Cyclic amides are also known as lactams.
(b)
Interpretation:
Given amide has to be classified as primary, secondary, or tertiary amide.
Concept Introduction:
Organic compounds are the important basis of life. They include gasoline, coal, dyes, and clothing fibers etc. The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds. Organic compounds are found in earth also apart from living organisms. All the organic compounds contain the element carbon. Urea was synthesized in the laboratory which is an organic compound.
Organic compounds contain heteroatom also. Some of them are nitrogen, sulfur, oxygen etc. Nitrogen containing organic compounds are of two important types and they are amines, amides.
One of the carboxylic acid derivatives is amide. In this the carboxyl
Amides are also classified as primary, secondary, and tertiary amide.
Primary amide is the one that has a nitrogen atom that is bonded to two hydrogen atoms. Primary amides are also known as unsubstituted amides.
Secondary amide is the one that has a nitrogen atom that is bonded to one hydrogen atom and one alkyl (or aryl) group. Secondary amides are also known as monosubstituted amides.
Tertiary amide is the one that has a nitrogen atom that is bonded to two alkyl (or aryl) groups. Tertiary amides are also known as disubstituted amides.
Apart from linear amides, there are also cyclic amides. They are formed by intramolecular condensation. Cyclic amides are also known as lactams.
(c)
Interpretation:
Given amide has to be classified as primary, secondary, or tertiary amide.
Concept Introduction:
Organic compounds are the important basis of life. They include gasoline, coal, dyes, and clothing fibers etc. The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds. Organic compounds are found in earth also apart from living organisms. All the organic compounds contain the element carbon. Urea was synthesized in the laboratory which is an organic compound.
Organic compounds contain heteroatom also. Some of them are nitrogen, sulfur, oxygen etc. Nitrogen containing organic compounds are of two important types and they are amines, amides.
One of the carboxylic acid derivatives is amide. In this the carboxyl
Amides are also classified as primary, secondary, and tertiary amide.
Primary amide is the one that has a nitrogen atom that is bonded to two hydrogen atoms. Primary amides are also known as unsubstituted amides.
Secondary amide is the one that has a nitrogen atom that is bonded to one hydrogen atom and one alkyl (or aryl) group. Secondary amides are also known as monosubstituted amides.
Tertiary amide is the one that has a nitrogen atom that is bonded to two alkyl (or aryl) groups. Tertiary amides are also known as disubstituted amides.
Apart from linear amides, there are also cyclic amides. They are formed by intramolecular condensation. Cyclic amides are also known as lactams.
(d)
Interpretation:
Given amide has to be classified as primary, secondary, or tertiary amide.
Concept Introduction:
Organic compounds are the important basis of life. They include gasoline, coal, dyes, and clothing fibers etc. The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds. Organic compounds are found in earth also apart from living organisms. All the organic compounds contain the element carbon. Urea was synthesized in the laboratory which is an organic compound.
Organic compounds contain heteroatom also. Some of them are nitrogen, sulfur, oxygen etc. Nitrogen containing organic compounds are of two important types and they are amines, amides.
One of the carboxylic acid derivatives is amide. In this the carboxyl
Amides are also classified as primary, secondary, and tertiary amide.
Primary amide is the one that has a nitrogen atom that is bonded to two hydrogen atoms. Primary amides are also known as unsubstituted amides.
Secondary amide is the one that has a nitrogen atom that is bonded to one hydrogen atom and one alkyl (or aryl) group. Secondary amides are also known as monosubstituted amides.
Tertiary amide is the one that has a nitrogen atom that is bonded to two alkyl (or aryl) groups. Tertiary amides are also known as disubstituted amides.
Apart from linear amides, there are also cyclic amides. They are formed by intramolecular condensation. Cyclic amides are also known as lactams.
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Chapter 17 Solutions
EBK GENERAL, ORGANIC, AND BIOLOGICAL CH
- Explanation O Conjugated Pi Systems Deducing the reactants of a Diels-Alder reaction Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Click and drag to start drawing a structure. Xarrow_forwardDiels Alder Cycloaddition: Focus on regiochemistry (problems E-F) –> match + of thedienophile and - of the diene while also considering stereochemistry (endo).arrow_forwardHELP! URGENT! PLEASE RESOND ASAP!arrow_forward
- Question 4 Determine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267 First-order, k = 0.210 hour 1 First-order, k = 0.0912 hour 1 O Second-order, k = 0.590 M1 hour 1 O Zero-order, k = 0.0770 M/hour O Zero-order, k = 0.4896 M/hour O Second-order, k = 1.93 M-1-hour 1 10 ptsarrow_forwardDetermine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267arrow_forwardDraw the products of the reaction shown below. Use wedge and dash bonds to indicate stereochemistry. Ignore inorganic byproducts. OSO4 (cat) (CH3)3COOH Select to Draw ઘarrow_forward
- Calculate the reaction rate for selenious acid, H2SeO3, if 0.1150 M I-1 decreases to 0.0770 M in 12.0 minutes. H2SeO3(aq) + 6I-1(aq) + 4H+1(aq) ⟶ Se(s) + 2I3-1(aq) + 3H2O(l)arrow_forwardProblem 5-31 Which of the following objects are chiral? (a) A basketball (d) A golf club (b) A fork (c) A wine glass (e) A spiral staircase (f) A snowflake Problem 5-32 Which of the following compounds are chiral? Draw them, and label the chirality centers. (a) 2,4-Dimethylheptane (b) 5-Ethyl-3,3-dimethylheptane (c) cis-1,4-Dichlorocyclohexane Problem 5-33 Draw chiral molecules that meet the following descriptions: (a) A chloroalkane, C5H11Cl (c) An alkene, C6H12 (b) An alcohol, C6H140 (d) An alkane, C8H18 Problem 5-36 Erythronolide B is the biological precursor of erythromycin, a broad-spectrum antibiotic. How H3C CH3 many chirality centers does erythronolide B have? OH Identify them. H3C -CH3 OH Erythronolide B H3C. H3C. OH OH CH3arrow_forwardPLEASE HELP! URGENT! PLEASE RESPOND!arrow_forward
- 2. Propose a mechanism for this reaction. ہلی سے ملی N H (excess)arrow_forwardSteps and explanationn please.arrow_forwardProblem 5-48 Assign R or S configurations to the chirality centers in ascorbic acid (vitamin C). OH H OH HO CH2OH Ascorbic acid O H Problem 5-49 Assign R or S stereochemistry to the chirality centers in the following Newman projections: H Cl H CH3 H3C. OH H3C (a) H H H3C (b) CH3 H Problem 5-52 Draw the meso form of each of the following molecules, and indicate the plane of symmetry in each: OH OH (a) CH3CHCH2CH2CHCH3 CH3 H3C. -OH (c) H3C CH3 (b) Problem 5-66 Assign R or S configurations to the chiral centers in cephalexin, trade-named Keflex, the most widely prescribed antibiotic in the United States. H2N H IHH S Cephalexin N. CH3 CO₂Harrow_forward
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
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