Chapter 17, Problem 13E

(a)

Interpretation Introduction

Interpretation: The equation showing the ions present after ${\text{HNO}}_{\text{3}}$ is dissolved in water needs to be determined.

Concept Introduction : A strong electrolyte is a solution or a solute that dissociates in a solution. These ions which is formed due to dissociation act as good conductors of electric current.

Answer to Problem 13E

  ${\text{HNO}}_{\text{3}}\to {\text{H}}^{\text{+}}\left(aq\right)+{\text{NO}}_{\text{3}}{}^{-}\left(aq\right)$ is the equation when ${\text{HNO}}_{\text{3}}$ is completely dissolved in water.

Explanation of Solution

In aqueous solution, ${\text{HNO}}_{\text{3}}$ is completely dissociated and gives ${\text{H}}^{\text{+}}$ and ${\text{NO}}_{\text{3}}{}^{\text{-}}$ ion.

  ${\text{HNO}}_{\text{3}}\to {\text{H}}^{\text{+}}\left(aq\right)+{\text{NO}}_{\text{3}}{}^{-}\left(aq\right)$

(b)

Interpretation Introduction

Interpretation: The equation showing the ions present after ${\text{Na}}_2{\text{SO}}_{\text{4}}$ is dissolved in water needs to be determined.

Concept Introduction : A strong electrolyte is a solution or a solute that dissociates in a solution. These ions which is formed due to dissociation act as good conductors of electric current.

Answer to Problem 13E

  ${\text{Na}}_2{\text{SO}}_{\text{4}}\to 2{\text{Na}}^{\text{+}}\left(aq\right)+{\text{SO}}_{\text{4}}{}^{2-}$ is the equation when ${\text{Na}}_2{\text{SO}}_{\text{4}}$ is completely dissolved in water.

Explanation of Solution

In a aqueous solution, ${\text{Na}}_2{\text{SO}}_{\text{4}}$ dissociate in water as $2{\text{Na}}^{\text{+}}$ and ${\text{SO}}_{\text{4}}{}^{2-}$

  ${\text{Na}}_2{\text{SO}}_{\text{4}}\to 2{\text{Na}}^{\text{+}}\left(aq\right)+{\text{SO}}_{\text{4}}{}^{2-}$

(c)

Interpretation Introduction

Interpretation: The equation showing the ions present after $\text{Al}{\left({\text{NO}}_{\text{3}}\right)}_2$ is dissolved in water needs to be explained.

Concept Introduction : A strong electrolyte is a solution or a solute that dissociates in a solution. These ions which is formed due to dissociation act as good conductors of electric current.

Explanation of Solution

  $\text{Al}{\left({\text{NO}}_{\text{3}}\right)}_2$ dissociates into ${\text{Al}}^{\text{+3}}$ and $3{\text{NO}}_3{}^{-}$

  $\text{Al}{\left({\text{NO}}_{\text{3}}\right)}_2\left(aq\right)\to {\text{Al}}^{\text{+3}}\left(aq\right)+3{\text{NO}}_3{}^{-}\left(aq\right)$ is the equation showing dissociation of $\text{Al}{\left({\text{NO}}_{\text{3}}\right)}_2$

(d)

Interpretation Introduction

Interpretation: The equation showing the ions present after ${\text{SrBr}}_{\text{2}}$ is dissolved in water needs to be determined.

Concept Introduction: A strong electrolyte is a solution or a solute that dissociates in a solution. These ions which is formed due to dissociation act as good conductors of electric current.

Answer to Problem 13E

  ${\text{SrBr}}_{\text{2}}\left(aq\right)\to {\text{Sr}}^{\text{+2}}\left(aq\right)+2{\text{Br}}^{-}\left(aq\right)$ is the equation showing the dissociation of ${\text{SrBr}}_{\text{2}}$

Explanation of Solution

  ${\text{SrBr}}_{\text{2}}$ dissociated into ${\text{Sr}}^{\text{+2}}$ and $2{\text{Br}}^{-}$

  ${\text{SrBr}}_{\text{2}}\left(aq\right)\to {\text{Sr}}^{\text{+2}}\left(aq\right)+2{\text{Br}}^{-}\left(aq\right)$

(e)

Interpretation Introduction

Interpretation: The equation showing the ions present after ${\text{KClO}}_{\text{4}}$ is dissolved in water needs to be determined.

Concept Introduction:A strong electrolyte is a solution or a solute that dissociates in a solution. These ions which is formed due to dissociation act as good conductors of electric current.

Answer to Problem 13E

  ${\text{KClO}}_{\text{4}}\left(aq\right)\to {\text{K}}^{+}\left(aq\right)+{\text{ClO}}_{\text{4}}{}^{-}\left(aq\right)$ is the equation showing dissociation of ${\text{KClO}}_{\text{4}}$

Explanation of Solution

  ${\text{KClO}}_{\text{4}}$ dissociates into ${\text{K}}^{+}$ and ${\text{ClO}}_{\text{4}}{}^{-}$

  ${\text{KClO}}_{\text{4}}\left(aq\right)\to {\text{K}}^{+}\left(aq\right)+{\text{ClO}}_{\text{4}}{}^{-}\left(aq\right)$

(f)

Interpretation Introduction

Interpretation: The equation showing the ions present after ${\text{NH}}_{\text{4}}\text{Br}$ is dissolved in water needs to be determined.

Concept Introduction: A strong electrolyte is a solution or a solute that dissociates in a solution. These ions which is formed due to dissociation act as good conductors of electric current.

Answer to Problem 13E

  ${\text{NH}}_{\text{4}}\text{Br}\left(aq\right)\to {\text{NH}}_4{}^{+}\left(aq\right)+{\text{Br}}^{-}\left(aq\right)$ is the equation showing the dissociation of ${\text{NH}}_{\text{4}}\text{Br}$

Explanation of Solution

  ${\text{NH}}_{\text{4}}\text{Br}$ gives ${\text{NH}}_4{}^{+}$ and ${\text{Br}}^{-}$

  ${\text{NH}}_{\text{4}}\text{Br}\left(aq\right)\to {\text{NH}}_4{}^{+}\left(aq\right)+{\text{Br}}^{-}\left(aq\right)$

(g)

Interpretation Introduction

Interpretation: The equation showing the ions present after ${\text{NH}}_{\text{4}}{\text{NO}}_{\text{3}}$ is dissolved in water needs to be determined.

Concept Introduction: A strong electrolyte is a solution or a solute that dissociates in a solution. These ions which is formed due to dissociation act as good conductors of electric current.

Answer to Problem 13E

  ${\text{NH}}_{\text{4}}{\text{NO}}_{\text{3}}\left(aq\right)\to {\text{NH}}_4{}^{+}\left(aq\right)+{\text{NO}}^{-}\left(aq\right)$ is the equation showing the dissociation of ${\text{NH}}_{\text{4}}{\text{NO}}_{\text{3}}$

Explanation of Solution

  ${\text{NH}}_{\text{4}}{\text{NO}}_{\text{3}}$ gives ${\text{NH}}_4{}^{+}$ and ${\text{NO}}^{-}$

The reaction is represented as follows:

  ${\text{NH}}_{\text{4}}{\text{NO}}_{\text{3}}\left(aq\right)\to {\text{NH}}_4{}^{+}\left(aq\right)+{\text{NO}}^{-}\left(aq\right)$

(h)

Interpretation Introduction

Interpretation: The equation showing the ions present after ${\text{CuSO}}_{\text{4}}$ is dissolved in water needs to be determined.

Concept Introduction:A strong electrolyte is a solution or a solute that dissociates in a solution. These ions which is formed due to dissociation act as good conductors of electric current.

Answer to Problem 13E

  ${\text{CuSO}}_{\text{4}}\left(aq\right)\to {\text{Cu}}^{+2}\left(aq\right)+{\text{SO}}_{\text{4}}{}^{2-}\left(aq\right)$ shows the dissociation of ${\text{CuSO}}_{\text{4}}$

Explanation of Solution

  ${\text{CuSO}}_{\text{4}}$ dissociates into ${\text{Cu}}^{+2}$ and ${\text{SO}}_{\text{4}}{}^{2-}$

The reaction is represented as follows:

  ${\text{CuSO}}_{\text{4}}\left(aq\right)\to {\text{Cu}}^{+2}\left(aq\right)+{\text{SO}}_{\text{4}}{}^{2-}\left(aq\right)$

(i)

Interpretation Introduction

Interpretation: The equation showing the ions present after $\text{NaOH}$ is dissolved in water needs to be determined.

Concept Introduction:A strong electrolyte is a solution or a solute that dissociates in a solution. These ions which is formed due to dissociation act as good conductors of electric current.

Answer to Problem 13E

  $\text{NaOH}\left(aq\right)\to {\text{Na}}^{+}\left(aq\right)+{\text{OH}}^{-}\left(aq\right)$ is the equation that gives the dissociation of $\text{NaOH}$

Explanation of Solution

  $\text{NaOH}$ gives ${\text{Na}}^{+}$ and ${\text{OH}}^{-}$

  $\text{NaOH}\left(aq\right)\to {\text{Na}}^{+}\left(aq\right)+{\text{OH}}^{-}\left(aq\right)$