THERMODYNAMICS (LL)-W/ACCESS >CUSTOM<
9th Edition
ISBN: 9781266657610
Author: CENGEL
Publisher: MCG CUSTOM
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Chapter 16.6, Problem 111FEP
To determine
The equilibrium constant for the reaction
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(9) Figure Q9 shows a 2 m long symmetric I beam where the upper and lower sections are 2X wide and the middle section is X wide, where X is 49 mm. The I beam sections are all Y=48 mm in depth. The beam is loaded in the middle with a
load of Z=59 kN causing reaction forces at either end of the beam's supports.
What is the maximum (positive) bending stress experienced in the beam in terms of mega-Pascals?
State your answer to the nearest whole number.
Z KN
Y mm
Y mm
Y mm
X mm
2X mm
Figure Q9
2 m
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Chapter 16 Solutions
THERMODYNAMICS (LL)-W/ACCESS >CUSTOM<
Ch. 16.6 - Why is the criterion for chemical equilibrium...Ch. 16.6 - Write three different KPrelations for reacting...Ch. 16.6 - Is a wooden table in chemical equilibrium with the...Ch. 16.6 - A reaction chamber contains a mixture of CO2, CO,...Ch. 16.6 - A reaction chamber contains a mixture of N2and N...Ch. 16.6 - A reaction chamber contains a mixture of CO2, CO,...Ch. 16.6 - Which element is more likely to dissociate into...Ch. 16.6 - Prob. 8PCh. 16.6 - Prob. 9PCh. 16.6 - Prob. 10P
Ch. 16.6 - Prob. 11PCh. 16.6 - Prob. 12PCh. 16.6 - Prob. 13PCh. 16.6 - Prob. 14PCh. 16.6 - Prob. 15PCh. 16.6 - Prob. 16PCh. 16.6 - Prob. 17PCh. 16.6 - Prob. 18PCh. 16.6 - Prob. 19PCh. 16.6 - Prob. 20PCh. 16.6 - Prob. 21PCh. 16.6 - Prob. 22PCh. 16.6 - Prob. 23PCh. 16.6 - Determine the equilibrium constant KP for the...Ch. 16.6 - Prob. 26PCh. 16.6 - Prob. 27PCh. 16.6 - Carbon monoxide is burned with 100 percent excess...Ch. 16.6 - Prob. 30PCh. 16.6 - Prob. 31PCh. 16.6 - Estimate KP for the following equilibrium reaction...Ch. 16.6 - Prob. 33PCh. 16.6 - A mixture of 3 mol of N2, 1 mol of O2, and 0.1 mol...Ch. 16.6 - Prob. 35PCh. 16.6 - Prob. 36PCh. 16.6 - Prob. 37PCh. 16.6 - Prob. 38PCh. 16.6 - Prob. 40PCh. 16.6 - What is the equilibrium criterion for systems that...Ch. 16.6 - Prob. 43PCh. 16.6 - Prob. 44PCh. 16.6 - Prob. 45PCh. 16.6 - Prob. 47PCh. 16.6 - Prob. 48PCh. 16.6 - Prob. 51PCh. 16.6 - Prob. 52PCh. 16.6 - Prob. 53PCh. 16.6 - Prob. 54PCh. 16.6 - Prob. 55PCh. 16.6 - Prob. 56PCh. 16.6 - Prob. 58PCh. 16.6 - Prob. 59PCh. 16.6 - Prob. 60PCh. 16.6 - Prob. 61PCh. 16.6 - Using the Henrys constant data for a gas dissolved...Ch. 16.6 - Prob. 63PCh. 16.6 - Prob. 64PCh. 16.6 - Prob. 65PCh. 16.6 - Prob. 66PCh. 16.6 - A liquid-vapor mixture of refrigerant-134a is at...Ch. 16.6 - Prob. 68PCh. 16.6 - Prob. 69PCh. 16.6 - An oxygennitrogen mixture consists of 30 kg of...Ch. 16.6 - Prob. 71PCh. 16.6 - Prob. 72PCh. 16.6 - Prob. 73PCh. 16.6 - Prob. 74PCh. 16.6 - Prob. 75PCh. 16.6 - Prob. 76PCh. 16.6 - An ammoniawater absorption refrigeration unit...Ch. 16.6 - Prob. 78PCh. 16.6 - Prob. 79PCh. 16.6 - Prob. 80PCh. 16.6 - One lbmol of refrigerant-134a is mixed with 1...Ch. 16.6 - Prob. 82RPCh. 16.6 - Prob. 83RPCh. 16.6 - Prob. 84RPCh. 16.6 - Prob. 85RPCh. 16.6 - Prob. 88RPCh. 16.6 - Prob. 89RPCh. 16.6 - Prob. 90RPCh. 16.6 - Prob. 91RPCh. 16.6 - Prob. 92RPCh. 16.6 - A constant-volume tank contains a mixture of 1 mol...Ch. 16.6 - Prob. 94RPCh. 16.6 - Prob. 95RPCh. 16.6 - Prob. 96RPCh. 16.6 - Prob. 97RPCh. 16.6 - Prob. 99RPCh. 16.6 - Consider a glass of water in a room at 25C and 100...Ch. 16.6 - Prob. 101RPCh. 16.6 - Prob. 102RPCh. 16.6 - Prob. 105RPCh. 16.6 - Prob. 106RPCh. 16.6 - Prob. 107RPCh. 16.6 - Prob. 108RPCh. 16.6 - Prob. 109FEPCh. 16.6 - Prob. 110FEPCh. 16.6 - Prob. 111FEPCh. 16.6 - Prob. 112FEPCh. 16.6 - Prob. 113FEPCh. 16.6 - Prob. 114FEPCh. 16.6 - Propane C3H8 is burned with air, and the...Ch. 16.6 - Prob. 116FEPCh. 16.6 - Prob. 117FEPCh. 16.6 - The solubility of nitrogen gas in rubber at 25C is...
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- Multiple answers are allowedarrow_forward(5) Figure Q5 shows a beam which rests on two pivots at positions A and C (as illustrated below). The beam is loaded with a UDL of 100 kN/m spanning from position B and ending at position D (as illustrated). The start location of B is Y=2.0 m from A. The total span of the UDL is twice the length of Z, where Z=2.4 m. What is the bending moment value at position X=2.5 m, (using the convention given to you in the module's formula book). State your answer in terms of kilo-Newton-metres to 1 decimal place. Bending Moment Value? A Ym X = ? B Zm Figure Q5 C UDL = 100 kN/m Zm Darrow_forwardPlease do not rely too much on chatgpt, because its answer may be wrong. Please consider it carefully and give your own answer. You can borrow ideas from gpt, but please do not believe its answer.Very very grateful! Please do not copy other's work,i will be very very grateful!!arrow_forward
- Please do not rely too much on chatgpt, because its answer may be wrong. Please consider it carefully and give your own answer. You can borrow ideas from gpt, but please do not believe its answer.Very very grateful! Please do not copy other's work,i will be very very grateful!!arrow_forwardPlease do not rely too much on chatgpt, because its answer may be wrong. Please consider it carefully and give your own answer. You can borrow ideas from gpt, but please do not believe its answer.Very very grateful! Please do not copy other's work,i will be very very grateful!!arrow_forward(8) Figure Q8 shows a T cross-section of a T beam which is constructed from three metal plates each having a width of 12 mm and sectional lengths of X=85 mm, Y=77 mm and Z=107 mm, where the plates are used for the web section, and the two flange sections respectively, as illustrated in Figure Q8. Calculate the neutral axis of the T-beam cross-section (as measured from the base) in units of millimetres, stating your answer to the nearest 1 decimal place. Z mm Y mm 12 mm X mm Figure Q8 12 mm 12 mmarrow_forward
- (2) Figure Q2 shows a 10 m long beam which has a concentrated load of X=95 KN located at the position A on the beam (x=0 m) as well as another load Z=42 kN at the end of the beam at position E (x=10 m). There is also a Uniform Distributed Load (UDL) of loading Y=84 kN/m which starts at position C (x=5 m) and ends at position D (x=7 m). There are two reaction pivots: - a left one located at B (x=3 m) and a right pivot located at D (x=7 m). Calculate the reaction force RD experienced by the pivot at the position D in terms of kilo-Newtons to 1 decimal place. X KN A 2m B 2m C Y kN/m 2m Figure Q2 D D 4m Z kN Earrow_forwardSelect the valid option from the list below. E F G 20 kN RAX = ?? KN 30° 30° 30° 30° 30° 30° A B D RAY = ?? KN A The solution to the problem is found to be -10.0 kN. B. The solution to the problem is found to be -20.0 KN. ○ C. The solution to the problem is found to be +11.5 kN. D. The solution to the problem is found to be +23.1 kN. E. No Valid Answer Roy = ?? KNarrow_forwardPlease do not rely too much on chatgpt, because its answer may be wrong. Please consider it carefully and give your own answer. You can borrow ideas from gpt, but please do not believe its answer.Very very grateful! Please do not copy other's work,i will be very very grateful!!arrow_forward
- Answer by selecting the correct options from the following multichoice selection. ப 4m B A C D 3m 3 m Figure Q17 FL 12 kN E 16 KN A. We should resolve forces in the horizontal direction to easily identify the internal force DF. B. The solution to the problem is found to be -16 kN (C). C. We should resolve forces in the vertical direction to first identify the internal force DF. D. We should use Method of Joints at node F to find the internal force in member DF. E. We should Method of Sections by cutting through members DF, DE and CE. F. The starting point to solve this problem is to find all reactions at nodes A and B as they will be required for DF calculations. G. The solution to the problem is found to be 16 kN (T). H. The most appropriate method to find DF use is Method of Joints. I. The most appropriate method to use is Method of Sections. J. A good starting point to solve this problem is to find the horizontal reaction at node B but this is not required to the internal forcearrow_forwardH 2 kN K 2 kN M N www RAY RAX A G B C D E F 3 m ↑ RGY 4m Fill in the multiple blanks. Figure Q19 Finding the vertical reactions is the starting point which can be done by taking moments at A and G but since this is symmetrical loading case the vertical reactions can simply be calculated by halving the total loading 4 kN. Ideally, we can solve the problem using the Method of cutting through the members JK, DJ and It would be sensible to select the left-hand side of the diagram as there are less full members and only one force from the reaction at node A. This will expose the internal forces which can be labelled with the names of the members themselves. Since we are required to find JK, examining the framework shows it is not a straight-forward matter, and we will require finding all three unknown internal forces. The easiest internal force to find is Next, we can take moments at node , as we can resolve forces in the vertical direction. in order to find the internal force JK and find…arrow_forwardPlease do not rely too much on chatgpt, because its answer may be wrong. Please consider it carefully and give your own answer. You can borrow ideas from gpt, but please do not believe its answer.Very very grateful! Please do not copy other's work,i will be very very grateful!!arrow_forward
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