Chapter 16.5, Problem 2RC

Interpretation Introduction

Interpretation:

Among the given images the one that is representing the solution of sulfuric acid has to be found.

Concept Introduction:

Sulfuric acid is a diprotic acid which means it consists of two protons.

In the first dissociation, one proton will be lost and the corresponding conjugate base will be formed.

In the second dissociation, the conjugate base of the 1^st dissociation acts an acid which further losses the 2^nd proton and forms its corresponding conjugate base.

The dissociation reactions of sulfuric acid are:

$\begin{array}{l}\text{1st}\text{dissociation}\\ {\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}\stackrel{}{\rightleftharpoons }{\text{HSO}}_4^{-}\text{+}{\text{H}}^{\text{+}}{\text{K}}_{\text{a}}\text{=}2.4\times {10}^{-6}\\ \text{2nd}\text{dissociation}\\ {\text{HSO}}_4^{-}\stackrel{}{\rightleftharpoons }{\text{SO}}_4^{2-}\text{+}{\text{H}}^{\text{+}}{\text{K}}_{\text{a}}\text{=}1.2\times {10}^{-2}\end{array}$