Chapter 16.2, Problem 24LC

Interpretation Introduction

Interpretation: The moles of solute present in $50.0\text{ mL }$ of $0.20\text{ M KNO3}$ is to be calculated.

Concept introduction: Moles of solute present in the solution can be found using the molarity of the solution. Molarity is defined as moles of solute present in the solution.

Answer to Problem 24LC

The moles of solute present in $50.0\text{ mL }$ of $0.20\text{ M KNO3}$ is $10.0\text{ moles}$

Explanation of Solution

To determine the concentration, molarity is used. Molarity is defined as the number of moles of solute present in one liter of the solution. The formula of molarity is as follows:

  $\text{Molarity = }\frac{n}{V}$

Where:

n is the number of moles of solute.

V is the volume of solution in liters.

The data given to find out the number of moles of solute is as follows:

The molarity of the solution is $\text{0}\text{.20 M}$ .

The volume of solution is $50.0\text{ mL}$ .

Substitute the values in the molarity formula.

  $\begin{array}{l}\text{Molarity = }\frac{n}{V}\\ 0.20\text{ M = }\frac{n}{50.0\text{ mL}}\\ n=10.0\text{ moles}\end{array}$

Conclusion

The moles of solute present in $50.0\text{ mL }$ of $0.20\text{ M KNO3}$ is $10.0\text{ moles}$