
Interpretation: The two ways in which the concentration of a solution as a percent is to be described.
Concept introduction: The concentration of the solution is defined as the amount of solute present in the given quantity of solution. There are different ways in which the concentration of the solution can be expressed and those are: molarity, molality, normality, percent by mass, and percent by volume. The most widely used concentration term is molarity.

Answer to Problem 21LC
The two ways to express the concentration of a solution in percent are percent by mass and percent by volume.
Explanation of Solution
Concentration of a solution can be expressed in percent by two methods such as:
- Percent by mass.
- Percent by volume.
The percent by mass is used for the system like solid in liquid which means in the system where the solute is solid and the solvent is liquid. The percent by mass can be defined as the ratio of the mass of the solute to the mass of the solution. The formula of percent by mass is as follows:
The other percent is the percent by volume by which a concentration of the solution is expressed. If the system is liquid in liquid that means, the solute and solvent both are liquid then, this is used. The percent by volume is defined as the ratio of the volume of a solute to the volume of the solution. The formula of percent by volume is as follows:
The two ways to express the concentration of a solution in percent are percent by mass and percent by volume.
Chapter 16 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- 0.500 moles of NOCl are placed into a 1.00 L vessesl at 700K and after the system comes to equilibrium, the consentration of NOCl is 0.440 M. Calculate the equilibrium constant Kc for the reaction: 2NOCL (g) --> 2NO (g) + Cl2 (g)arrow_forwardWhat is the hydronium ion concentration in a solution of water that has a hydroxide ion concentrationof 1.0 x 10-2 M?arrow_forwardIdentify conjugate acid-base pairs in the following reactions:HBr (aq) + H2O (l) ⇌ H3O+ (aq) + Br- (aq) - OH (aq) + CH3COOH (aq) ⇌ H2O (l) + CH3COO- (aq)arrow_forward
- 4:45 PM Tue Apr 1 K 77% Problem 9 of 10 Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting structure, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. Then draw any missing organic intermediates or products for this reaction. Include all lone pairs in the structures. Ignore inorganic byproducts, counterions, and solvents. :0: H Select to Add Arrows HI CH3OH H+ ·HO CH3OH, H+ 0:0 H H Select to Add Arrows tion Versirate CH3OH, H* Select to Draw Productarrow_forwardCan I please get help with this graph? If you can show exactly where it needs to pass through.arrow_forwardG 1. PPh3, THF 2. 3. LiH, THF ' THF H Harrow_forward
- Please EnCircle or Fill-In your Choice CLEARLY: 21. Please Sketch the intermediates for each step below. Draw the Product which would result from the following series of reactions. Name each Type of Rx: 1. Br2, FeBr3 2. Mg, ether 3. ethylene oxide 4. H₂O+ 5. PBr3 6. Mg, ether 7. 8. H3O+, heat (-H₂O 9. HF ?arrow_forwardCan I please get help with this question. All required information should be in data table.arrow_forwardesc For the reaction below: 1. Draw all reasonable elimination products to the right of the arrow. 2. In the box below the reaction, redraw any product you expect to be a major product. Major Product: Explanation Check C ☐ + X NaOH Br F1 F2 80 F3 F4 F5 F6 1 ! @ 2 3 $ 4 % 5 Q W LU E S D A F7 * C Click and dr drawing a 2025 McGraw Hill LLC. All Rights Reserv ►II F8 4 F9 6 7 8 9 R T Y U LL F G H Jarrow_forward
- Calculate equilibrium concentrations for the following reaction:N2 (g) + O2 (g) ⇋ 2 NO (g) Kc = 0.10 at 2273K initially [N2] = 0.200M; [O2] = 0.200arrow_forwardFor each scenario below, select the color of the solution using the indicator thymol blue during the titration. When you first add indicator to your Na2CO3solution, the solution is basic (pH ~10), and the color is ["", "", "", "", ""] . At the equivalence point for the titration, the moles of added HCl are equal to the moles of Na2CO3. One drop (or less!) past this is called the endpoint. The added HCl begins to titrate the thymol blue indicator itself. At the endpoint, the indicator color is ["", "", "", "", ""] . When you weren't paying attention and added too much HCl (~12 mL extra), the color is ["", "", "", "", ""] . When you really weren't paying attention and reached the second equivalence point of Na2CO3, the color isarrow_forwardThe following reaction is run in which the initial conditions include only methane (CH4) at a concentration of0.115 M. Once equilibrium was established, the concentration of acetylene (C2H2) was measured to be 0.035M. What is the value of the equilibrium constant, K?2 CH4 (g) ⇋ C2H2 (g) + 3 H2 (g)arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





