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A 60-lb uniform thin panel is placed in a truck with end A resting on a rough horizontal surface and end B supported by a smooth vertical surface. Knowing that the panel remains in the position shown, determine (a) the maximum allowable acceleration of the truck, (b) the corresponding minimum required coefficient of static friction at end A.
Fig. P16.1 and P16.2
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Chapter 16 Solutions
VECTOR MECH. FOR EGR: STATS & DYNAM (LL
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- متوسعة الفرج بو عمامة المستوى رم الواجب المنزلي رقم 04 تمرین الوان حسب يتمعن العبارات الأتية : A= (+2)+(-45) B=(+13)- C = (+17)-(+13)-(-20)+(-19 D= [(-15)-(+15)]-[(+20) + هست قیم مدرج مبدؤه النقطة ة الطول :tcm A(-2,5): B(+ 2,5) ≤ C (+5) المسافتين : BAD ين الثاني لمستوي مبدؤه 8 وحدتهarrow_forwardPlease do not rely too much on AI, because its answer may be wrong. Please consider it carefully and give your own answer!!!!! You can borrow ideas from AI, but please do not believe its answer.Very very grateful! ( If you write by hand or don't use AI, I'll give you a big thumbs up ) Please do not copy other's work,i will be very very grateful!!Please do not copy other's work,i will be very very grateful!!arrow_forwardA thin uniform rod of mass m and length 2r rests in a smooth hemispherical bowl of radius r. A moment M = mgr horizontal plane. is applied to the rod. Assume that the bowl is fixed and its rim is in the HINT: It will help you to find the length l of that portion of the rod that remains outside the bowl. M 2r Ꮎ a) How many degrees of freedom does this system have? b) Write an equation for the virtual work in terms of the angle 0 and the motion of the center of mass (TF) c) Derive an equation for the variation in the position of the center of mass (i.e., Sŕƒ) a. HINT: Use the center of the bowl as the coordinate system origin for the problem. d) In the case of no applied moment (i.e., M = 0), derive an equation that can be used to solve for the equilibrium angle of the rod. DO NOT solve the equation e) In the case of an applied moment (i.e., M: = mgr 4 -) derive an equation that can be used to solve for the equilibrium angle of the rod. DO NOT solve the equation. f) Can the angle 0 and…arrow_forward
- Please do not rely too much on chatgpt, because its answer may be wrong. Please consider it carefully and give your own answer. You can borrow ideas from gpt, but please do not believe its answer.Very very grateful! Please do not copy other's work,i will be very very grateful!!Please do not copy other's work,i will be very very grateful!!arrow_forward= The frame shown is fitted with three 50 cm diameter frictionless pulleys. A force of F = 630 N is applied to the rope at an angle ◊ 43°. Member ABCD is attached to the wall by a fixed support at A. Find the forces indicated below. Note: The rope is tangent to the pully (D) and not secured at the 3 o'clock position. a b •C *су G E e d BY NC SA 2013 Michael Swanbom Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 81 cm b 50 cm с 59 cm d 155 cm For all answers, take x as positive to the right and positive upward. At point A, the fixed support exerts a force of: A = + ĴN and a reaction couple of: →> ΜΑ Member CG is in Select an answer magnitude У as k N-m. and carries a force of N.arrow_forwardThe lower jaw AB [Purple 1] and the upper jaw-handle AD [Yellow 2] exert vertical clamping forces on the object at R. The hand squeezes the upper jaw-handle AD [2] and the lower handle BC [Orane 4] with forces F. (Member CD [Red 3] acts as if it is pinned at D, but, in a real vise-grips, its position is actually adjustable.) The clamping force, R, depends on the geometry and on the squeezing force F applied to the handles. Determine the proportionality between the clamping force, R, and the squeezing force F for the dimensions given. d3 d4 R 1 B d1 2 d2 D... d5 F 4 F Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value d1 65 mm d2 156 mm d3 50 mm 45 d4 d5 113 mm 30 mm R = Farrow_forward
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