Chapter 16, Problem 78AE

(a)

Interpretation Introduction

Interpretation:

Expression for equilibrium constant for below reaction has to be given:

  ${\text{2A}}_{\text{3}}\text{X}\rightleftharpoons 2{\text{A}}_{\text{2}}\text{X}+{\text{A}}_{\text{2}}$

Concept Introduction:

For equilibrium reaction rate of forward reaction is equal to rate of reverse direction. Consider a general reaction that is as follows:

  $a\text{A}+b\text{B}\rightleftharpoons c\text{C}+d\text{D}$

The expression for equilibrium constant is written as follows:

  $K_{\text{eq}}=\frac{{\left[\text{C}\right]}^c{\left[\text{D}\right]}^d}{{\left[\text{A}\right]}^a{\left[\text{B}\right]}^b}$

Here,

$K_{\text{eq}}$ is equilibrium constant

$\left[\text{A}\right]$, $\left[\text{B}\right]$, $\left[\text{C}\right]$ and $\left[\text{D}\right]$ are concentration of substances in reaction

$a$, $b$, $c$ and $d$ are coefficients of substances

(b)

Interpretation Introduction

Interpretation:

Equilibrium for below reaction lie on right or left has to be determined.

  ${\text{2A}}_{\text{3}}\text{X}\rightleftharpoons 2{\text{A}}_{\text{2}}\text{X}+{\text{A}}_{\text{2}}$

Concept Introduction:

Le Chatelier’s principle states that changes at equilibrium in system respond to reduce the changes and bring back the system to restore its equilibrium under new conditions.