FOUND.OF COLLEGE CHEMISTRY
FOUND.OF COLLEGE CHEMISTRY
15th Edition
ISBN: 9781119234555
Author: Hein
Publisher: WILEY
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Chapter 16, Problem 10PE

(a)

Interpretation Introduction

Interpretation:

Shift in equilibrium as volume of vessel is increased in a below reaction has to be determined

  2CO2(g)+N2(g)+1095.9 kJC2N2(g)+2O2(g)

Concept Introduction:

Le Chatelier’s principle states that changes at equilibrium in system respond to reduce the changes and bring back the system to restore its equilibrium under new conditions. According to this principle with increase in temperature reaction rate rises due to rise in kinetic energy. In case of endothermic reaction that is when energy is absorbed then the reaction moves in forward direction. In case of exothermic reaction that is when energy is released then reaction moves in backward direction.

(b)

Interpretation Introduction

Interpretation:

Shift in equilibrium on addition of O2 for a below reaction has to be determined.

  2CO2(g)+N2(g)+1095.9 kJC2N2(g)+2O2(g)

Concept Introduction:

Le Chatelier’s principle states that changes at equilibrium in system respond to reduce the changes and bring back the system to restore its equilibrium under new conditions.

(c)

Interpretation Introduction

Interpretation:

Shift in equilibrium with increase in temperature for a below reaction has to be determined.

  2CO2(g)+N2(g)+1095.9 kJC2N2(g)+2O2(g)

Concept Introduction:

Refer to part (a).

(d)

Interpretation Introduction

Interpretation:

Shift in equilibrium on addition of N2 for a below reaction has to be determined.

  2CO2(g)+N2(g)+1095.9 kJC2N2(g)+2O2(g)

Concept Introduction:

Refer to part (b).

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Students have asked these similar questions
Kc = 0.0600 at 500 °C. (a) Determine whether a mixture that contains 1.35 M N, 1.80 M H,, and 0.215 M NHa is at equilibrium? (b) If not, predict the direction in which a net reaction would occur to reach equilibrium? (c) How would each concentration of N2, H2 and NH3 change (increase or decrease) when the reaction reaches equilibrium?
The equilibrium constant for the reaction2 NO(g) + Br2(g) ⇌ 2 NOBr(g)is Kc = 1.3 x 10-2 at 1000 K. (a) At this temperature doesthe equilibrium favor NO and Br2, or does it favor NOBr?(b) Calculate Kc for 2 NOBr(g)⇌ 2 NO(g) + Br2(g).(c) Calculate Kc for NOBr(g)⇌ NO(g) + 1/2 Br2(g).
Consider the following general reaction:2A(g) + 2B(g) ⇌ 3C(g) The reaction was measured to have an equilibrium reaction constant (K) of 0.0100 at 100 K.  If the reaction has a standard enthalpy change (ΔHrxn) of 500.3 J/mol, what should the equilibrium reaction constant be when the temperature is 800 K? (Please provide your answer to 3 significant figures.)

Chapter 16 Solutions

FOUND.OF COLLEGE CHEMISTRY

Ch. 16.6 - Prob. 16.11PCh. 16.6 - Prob. 16.12PCh. 16.7 - Prob. 16.13PCh. 16.7 - Prob. 16.14PCh. 16.7 - Prob. 16.15PCh. 16.8 - Prob. 16.16PCh. 16 - Prob. 1RQCh. 16 - Prob. 2RQCh. 16 - Prob. 3RQCh. 16 - Prob. 4RQCh. 16 - Prob. 5RQCh. 16 - Prob. 6RQCh. 16 - Prob. 7RQCh. 16 - Prob. 8RQCh. 16 - Prob. 9RQCh. 16 - Prob. 10RQCh. 16 - Prob. 11RQCh. 16 - Prob. 12RQCh. 16 - Prob. 13RQCh. 16 - Prob. 14RQCh. 16 - Prob. 15RQCh. 16 - Prob. 16RQCh. 16 - Prob. 17RQCh. 16 - Prob. 18RQCh. 16 - Prob. 19RQCh. 16 - Prob. 20RQCh. 16 - Prob. 21RQCh. 16 - Prob. 22RQCh. 16 - Prob. 23RQCh. 16 - Prob. 24RQCh. 16 - Prob. 25RQCh. 16 - Prob. 26RQCh. 16 - Prob. 27RQCh. 16 - Prob. 1PECh. 16 - Prob. 2PECh. 16 - Prob. 3PECh. 16 - Prob. 4PECh. 16 - Prob. 5PECh. 16 - Prob. 6PECh. 16 - Prob. 7PECh. 16 - Prob. 8PECh. 16 - Prob. 9PECh. 16 - Prob. 10PECh. 16 - Prob. 11PECh. 16 - Prob. 12PECh. 16 - Prob. 13PECh. 16 - Prob. 14PECh. 16 - Prob. 15PECh. 16 - Prob. 16PECh. 16 - Prob. 17PECh. 16 - Prob. 18PECh. 16 - Prob. 19PECh. 16 - Prob. 20PECh. 16 - Prob. 21PECh. 16 - Prob. 22PECh. 16 - Prob. 23PECh. 16 - Prob. 24PECh. 16 - Prob. 25PECh. 16 - Prob. 26PECh. 16 - Prob. 27PECh. 16 - Prob. 28PECh. 16 - Prob. 29PECh. 16 - Prob. 30PECh. 16 - Prob. 31PECh. 16 - Prob. 32PECh. 16 - Prob. 33PECh. 16 - Prob. 34PECh. 16 - Prob. 35PECh. 16 - Prob. 36PECh. 16 - Prob. 37PECh. 16 - Prob. 38PECh. 16 - Prob. 39PECh. 16 - Prob. 40PECh. 16 - Prob. 41PECh. 16 - Prob. 42PECh. 16 - Prob. 43PECh. 16 - Prob. 44PECh. 16 - Prob. 45PECh. 16 - Prob. 46PECh. 16 - Prob. 47PECh. 16 - Prob. 48PECh. 16 - Prob. 49AECh. 16 - Prob. 50AECh. 16 - Prob. 51AECh. 16 - Prob. 52AECh. 16 - Prob. 53AECh. 16 - Prob. 54AECh. 16 - Prob. 55AECh. 16 - Prob. 56AECh. 16 - Prob. 57AECh. 16 - Prob. 58AECh. 16 - Prob. 59AECh. 16 - Prob. 60AECh. 16 - Prob. 61AECh. 16 - Prob. 62AECh. 16 - Prob. 63AECh. 16 - Prob. 64AECh. 16 - Prob. 65AECh. 16 - Prob. 66AECh. 16 - Prob. 67AECh. 16 - Prob. 68AECh. 16 - Prob. 69AECh. 16 - Prob. 70AECh. 16 - Prob. 71AECh. 16 - Prob. 72AECh. 16 - Prob. 73AECh. 16 - Prob. 74AECh. 16 - Prob. 75AECh. 16 - Prob. 76AECh. 16 - Prob. 77AECh. 16 - Prob. 78AECh. 16 - Prob. 79AECh. 16 - Prob. 80AECh. 16 - Prob. 81AECh. 16 - Prob. 83AECh. 16 - Prob. 84AECh. 16 - Prob. 85AECh. 16 - Prob. 86CECh. 16 - Prob. 87CECh. 16 - Prob. 88CECh. 16 - Prob. 89CE
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