Chapter 16, Problem 74AE

(a)

Interpretation Introduction

Interpretation:

Expression for equilibrium constant for below reaction has to be given:

  ${\text{3O}}_{\text{2}}\left(\text{g}\right)\rightleftharpoons 2{\text{O}}_3\left(\text{g}\right)$

Concept Introduction:

For equilibrium reaction rate of forward reaction is equal to rate of reverse direction. Consider a general reaction that is as follows:

  $a\text{A}+b\text{B}\rightleftharpoons c\text{C}+d\text{D}$

The expression for equilibrium constant is written as follows:

  $K_{\text{eq}}=\frac{{\left[\text{C}\right]}^c{\left[\text{D}\right]}^d}{{\left[\text{A}\right]}^a{\left[\text{B}\right]}^b}$

Here,

$K_{\text{eq}}$ is equilibrium constant

$\left[\text{A}\right]$, $\left[\text{B}\right]$, $\left[\text{C}\right]$ and $\left[\text{D}\right]$ are concentration of substances in reaction

$a$, $b$, $c$ and $d$ are coefficients of substances

(b)

Interpretation Introduction

Interpretation:

Expression for equilibrium constant in below reaction has to be given:

  ${\text{H}}_{\text{2}}\text{O}\left(g\right)\rightleftharpoons {\text{H}}_{\text{2}}\text{O}\left(l\right)$

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

Expression for equilibrium constant in below reaction has to be given:

  ${\text{MgCO}}_{\text{3}}\left(s\right)\rightleftharpoons \text{MgO}\left(s\right)+{\text{CO}}_2\left(g\right)$

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

Expression for equilibrium constant in below reaction has to be given:

  ${\text{2 Bi}}^{3+}\left(aq\right)+3{\text{H}}_{\text{2}}\text{S}\left(aq\right)\rightleftharpoons {\text{Bi}}_{\text{2}}{\text{S}}_{\text{3}}\left(s\right)+6{\text{H}}^{\text{+}}\left(aq\right)$

Concept Introduction:

Refer to part (a).