Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN: 9781133939146
Author: Katz, Debora M.
Publisher: Cengage Learning
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Chapter 16, Problem 51PQ
To determine
Whether the oscillator is critically damped, when the object mass is increased.
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Check out a sample textbook solutionChapter 16 Solutions
Physics for Scientists and Engineers: Foundations and Connections
Ch. 16.1 - Prob. 16.1CECh. 16.2 - Prob. 16.2CECh. 16.2 - For each expression, identify the angular...Ch. 16.5 - Prob. 16.4CECh. 16.6 - Prob. 16.5CECh. 16.6 - Prob. 16.6CECh. 16 - Case Study For each velocity listed, state the...Ch. 16 - Case Study For each acceleration listed, state the...Ch. 16 - Prob. 3PQCh. 16 - Prob. 4PQ
Ch. 16 - Prob. 5PQCh. 16 - Prob. 6PQCh. 16 - The equation of motion of a simple harmonic...Ch. 16 - The expression x = 8.50 cos (2.40 t + /2)...Ch. 16 - A simple harmonic oscillator has amplitude A and...Ch. 16 - Prob. 10PQCh. 16 - A 1.50-kg mass is attached to a spring with spring...Ch. 16 - Prob. 12PQCh. 16 - Prob. 13PQCh. 16 - When the Earth passes a planet such as Mars, the...Ch. 16 - A point on the edge of a childs pinwheel is in...Ch. 16 - Prob. 16PQCh. 16 - Prob. 17PQCh. 16 - A jack-in-the-box undergoes simple harmonic motion...Ch. 16 - C, N A uniform plank of length L and mass M is...Ch. 16 - Prob. 20PQCh. 16 - A block of mass m = 5.94 kg is attached to a...Ch. 16 - A block of mass m rests on a frictionless,...Ch. 16 - It is important for astronauts in space to monitor...Ch. 16 - Prob. 24PQCh. 16 - A spring of mass ms and spring constant k is...Ch. 16 - In an undergraduate physics lab, a simple pendulum...Ch. 16 - A simple pendulum of length L hangs from the...Ch. 16 - We do not need the analogy in Equation 16.30 to...Ch. 16 - Prob. 29PQCh. 16 - Prob. 30PQCh. 16 - Prob. 31PQCh. 16 - Prob. 32PQCh. 16 - Prob. 33PQCh. 16 - Show that angular frequency of a physical pendulum...Ch. 16 - A uniform annular ring of mass m and inner and...Ch. 16 - A child works on a project in art class and uses...Ch. 16 - Prob. 37PQCh. 16 - Prob. 38PQCh. 16 - In the short story The Pit and the Pendulum by...Ch. 16 - Prob. 40PQCh. 16 - A restaurant manager has decorated his retro diner...Ch. 16 - Prob. 42PQCh. 16 - A wooden block (m = 0.600 kg) is connected to a...Ch. 16 - Prob. 44PQCh. 16 - Prob. 45PQCh. 16 - Prob. 46PQCh. 16 - Prob. 47PQCh. 16 - Prob. 48PQCh. 16 - A car of mass 2.00 103 kg is lowered by 1.50 cm...Ch. 16 - Prob. 50PQCh. 16 - Prob. 51PQCh. 16 - Prob. 52PQCh. 16 - Prob. 53PQCh. 16 - Prob. 54PQCh. 16 - Prob. 55PQCh. 16 - Prob. 56PQCh. 16 - Prob. 57PQCh. 16 - An ideal simple harmonic oscillator comprises a...Ch. 16 - Table P16.59 gives the position of a block...Ch. 16 - Use the position data for the block given in Table...Ch. 16 - Consider the position data for the block given in...Ch. 16 - Prob. 62PQCh. 16 - Prob. 63PQCh. 16 - Use the data in Table P16.59 for a block of mass m...Ch. 16 - Consider the data for a block of mass m = 0.250 kg...Ch. 16 - A mass on a spring undergoing simple harmonic...Ch. 16 - A particle initially located at the origin...Ch. 16 - Consider the system shown in Figure P16.68 as...Ch. 16 - Prob. 69PQCh. 16 - Prob. 70PQCh. 16 - Prob. 71PQCh. 16 - Prob. 72PQCh. 16 - Determine the period of oscillation of a simple...Ch. 16 - The total energy of a simple harmonic oscillator...Ch. 16 - A spherical bob of mass m and radius R is...Ch. 16 - Prob. 76PQCh. 16 - A lightweight spring with spring constant k = 225...Ch. 16 - Determine the angular frequency of oscillation of...Ch. 16 - Prob. 79PQCh. 16 - A Two springs, with spring constants k1 and k2,...Ch. 16 - Prob. 81PQCh. 16 - Prob. 82PQ
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- A uniform annular ring of mass m and inner and outer radii a and b, respectively, is pivoted around an axis perpendicular to the plane of the ring at point P (Fig. P16.35). Determine its period of oscillation. FIGURE P16.35arrow_forwardIf the amplitude of a damped oscillator decreases to 1/e of its initial value after n periods, show that the frequency of the oscillator must be approximately [1 − (8π2n2)−1] times the frequency of the corresponding undamped oscillator.arrow_forwardA block of mass m = 2.00 kg is attached to a spring of force constant k = 500 N/m as shown in Figure P7.15. The block is pulled to a position xi = 5.00 cm to the right of equilibrium and released from rest. Find the speed the block has as it passes through equilibrium if (a) the horizontal surface is frictionless and (b) the coefficient of friction between block and surface is k = 0.350. Figure P7.15arrow_forward
- The position of a particle attached to a vertical spring is given by y=(y0cost)j. The y axis points upward, y0 = 14.5 cm. and = 18.85 rad/s. Find the position of the particle at a. t = 0 and b. t = 9.0 s. Give your answers in centimeters.arrow_forwardThe total energy of a simple harmonic oscillator with amplitude 3.00 cm is 0.500 J. a. What is the kinetic energy of the system when the position of the oscillator is 0.750 cm? b. What is the potential energy of the system at this position? c. What is the position for which the potential energy of the system is equal to its kinetic energy? d. For a simple harmonic oscillator, what, if any, are the positions for which the kinetic energy of the system exceeds the maximum potential energy of the system? Explain your answer. FIGURE P16.73arrow_forwardA vibration sensor, used in testing a washing machine, consists of a cube of aluminum 1.50 cm on edge mounted on one end of a strip of spring steel (like a hacksaw blade) that lies in a vertical plane. The strips mass is small compared with that of the cube, but the strips length is large compared with the size of the cube. The other end of the strip is clamped to the frame of the washing machine that is not operating. A horizontal force of 1.43 N applied to the cube is required to hold it 2.75 cm away from its equilibrium position. If it is released, what is its frequency of vibration?arrow_forward
- A simple harmonic oscillator has amplitude A and period T. Find the minimum time required for its position to change from x = A to x = A/2 in terms of the period T.arrow_forwardFor each expression, identify the angular frequency , period T, initial phase and amplitude ymax of the oscillation. All values are in SI units. a. y(t) = 0.75 cos (14.5t) b. vy (t) = 0.75 sin (14.5t + /2) c. ay (t) = 14.5 cos (0.75t + /2) 16.3arrow_forwardA lightweight spring with spring constant k = 225 N/m is attached to a block of mass m1 = 4.50 kg on a frictionless, horizontal table. The blockspring system is initially in the equilibrium configuration. A second block of mass m2 = 3.00 kg is then pushed against the first block, compressing the spring by x = 15.0 cm as in Figure P16.77A. When the force on the second block is removed, the spring pushes both blocks to the right. The block m2 loses contact with the springblock 1 system when the blocks reach the equilibrium configuration of the spring (Fig. P16.77B). a. What is the subsequent speed of block 2? b. Compare the speed of block 1 when it again passes through the equilibrium position with the speed of block 2 found in part (a). 77. (a) The energy of the system initially is entirely potential energy. E0=U0=12kymax2=12(225N/m)(0.150m)2=2.53J At the equilibrium position, the total energy is the total kinetic energy of both blocks: 12(m1+m2)v2=12(4.50kg+3.00kg)v2=(3.75kg)v2=2.53J Therefore, the speed of each block is v=2.53J3.75kg=0.822m/s (b) Once the second block loses contact, the first block is moving at the speed found in part (a) at the equilibrium position. The energy 01 this spring-block 1 system is conserved, so when it returns to the equilibrium position, it will be traveling at the same speed in the opposite direction, or v=0.822m/s. FIGURE P16.77arrow_forward
- A 1.50-kg mass is attached to a spring with spring constant 33.0 N/m on a frictionless, horizontal table. The springmass system is stretched to 4.00 cm beyond the equilibrium position of the spring and is released from rest at t = 0. a. What is the maximum speed of the 1.50-kg mass? b. What is the maximum acceleration of the 1.50-kg mass? c. What are the position, velocity, and acceleration of the 1.50-kg mass as functions of time?arrow_forwardThe mechanical energy of an undamped block-spring system is constant as kinetic energy transforms to elastic potential energy and vice versa. For comparison, explain what happens to the energy of a damped oscillator in terms of the mechanical, potential, and kinetic energies.arrow_forwardUse the position data for the block given in Table P16.59. Sketch a graph of the blocks a. position versus time, b. velocity versus time and c. acceleration versus time. There is no need to label the values of velocity or acceleration on those graphs. TABLE P16.59arrow_forward
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SIMPLE HARMONIC MOTION (Physics Animation); Author: EarthPen;https://www.youtube.com/watch?v=XjkUcJkGd3Y;License: Standard YouTube License, CC-BY