The graph G that is obtained by sequence of transformation in graph of y.
The graph G is y=|2x+2| .
Given:
The graph of y=|x| is shifted by 2 units left, then a horizontal shrink by a factor 1/2 and finally a down shift of 4 units.
Concept Used:
The graph of y=f(x) is translated or shifted horizontally left or right according as:
1) If y=f(x−c) , then graph shifted by c units right from y=f(x) .
2) If y=f(x+c) , then graph shifted by c units left from y=f(x) .
And, the graph of y=f(x) is translated or shifted vertically up or down according as:
1) If y=f(x)+c , then graph shifted by c units up from y=f(x) .
2) If y=f(x)−c , then graph shifted by c units down from y=f(x) .
The transformation of horizontal stretches or shrinks from y=f(x) is as follows:
The graph of y=f(xc) transform to horizontal stretches by factor c , when c>1 and horizontal shrinks by factor c when c<1 .
The transformation of vertical stretches or shrinks from y=f(x) is as follows:
The graph of y=c⋅f(x) transform to vertical stretches by factor c , when c>1 and shrinks by factor c when c<1 .
Calculation:
Consider the sequence of transformation,
The graph of y=|x| is shifted by 2 units left,
So x is replace by (x+2) , that is, y=|x+2| .
Thus, the equation y=|x| transform to y=|x+2| .
And, in the next transformation, the graph of y=|x+2| is shrink horizontally by a factor 1/2 ,
So x is replace by x1/2=2x , that is, y=|2x+2| .
Hence, the equation y=|x+4| transform to y=|2x+2| .
The next transformation, the graph of y=|2x+2| shifted down by 4 units,
So 4 is subtracted from left side of function, that is y=|2x+2|−4 .
Hence, the equation y=|2x+2| transform to y=|2x+2|−4 .
Conclusion The equation y=|x| transform to y=|2x+2| .
Chapter 1 Solutions
PRECALCULUS:...COMMON CORE ED.-W/ACCESS
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