Universe: Stars And Galaxies
6th Edition
ISBN: 9781319115098
Author: Roger Freedman, Robert Geller, William J. Kaufmann
Publisher: W. H. Freeman
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 16, Problem 44Q
To determine
(a)
The ratio of the energy flux from a patch of a penumbra of the sunspot to the energy flux from an equally large patch of the undisturbed photosphere.
To determine
(b)
The ratio of the energy flux from a patch of a penumbra of the sunspot to the energy flux from an equally large patch of the umbra.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Chapter #8, Question #2:
Use eqn. 8.4 (F = σT4) to show why the total flux of solar radiant energy is about 105 times greater than that from the Earth.
The solar insolation at the top of the atmosphere is about 342 W/m^2. The total radiation absorbed at the surface of the Earth is 494 W/m^2. Explain how it is possible to absorb more radiation at the surface than comes in at the top of the atmosphere.
(Answer should be one paragraph long)
The best solar panels currently available are about 19% efficient in converting sunlight to electricity. A typical home will use about 40. kWh of electricity per day (1 kWh=1 kilowatt hour; 1kW=1000J/s). Assuming 8.1 hours of useful sunlight per day, calculate the minimum solar panel surface area necessary to provide all of a typical home’s electricity. The energy rate supplied by the sun is 1.0kJ/s times meters squared .
Area = meters squared
Chapter 16 Solutions
Universe: Stars And Galaxies
Ch. 16 - Prob. 1QCh. 16 - Prob. 2QCh. 16 - Prob. 3QCh. 16 - Prob. 4QCh. 16 - Prob. 5QCh. 16 - Prob. 6QCh. 16 - Prob. 7QCh. 16 - Prob. 8QCh. 16 - Prob. 9QCh. 16 - Prob. 10Q
Ch. 16 - Prob. 11QCh. 16 - Prob. 12QCh. 16 - Prob. 13QCh. 16 - Prob. 14QCh. 16 - Prob. 15QCh. 16 - Prob. 16QCh. 16 - Prob. 17QCh. 16 - Prob. 18QCh. 16 - Prob. 19QCh. 16 - Prob. 20QCh. 16 - Prob. 21QCh. 16 - Prob. 22QCh. 16 - Prob. 23QCh. 16 - Prob. 24QCh. 16 - Prob. 25QCh. 16 - Prob. 26QCh. 16 - Prob. 27QCh. 16 - Prob. 28QCh. 16 - Prob. 29QCh. 16 - Prob. 30QCh. 16 - Prob. 31QCh. 16 - Prob. 32QCh. 16 - Prob. 33QCh. 16 - Prob. 34QCh. 16 - Prob. 35QCh. 16 - Prob. 36QCh. 16 - Prob. 37QCh. 16 - Prob. 38QCh. 16 - Prob. 39QCh. 16 - Prob. 40QCh. 16 - Prob. 41QCh. 16 - Prob. 42QCh. 16 - Prob. 43QCh. 16 - Prob. 44QCh. 16 - Prob. 45QCh. 16 - Prob. 46QCh. 16 - Prob. 47QCh. 16 - Prob. 48QCh. 16 - Prob. 49QCh. 16 - Prob. 50QCh. 16 - Prob. 51QCh. 16 - Prob. 52QCh. 16 - Prob. 53QCh. 16 - Prob. 54QCh. 16 - Prob. 55QCh. 16 - Prob. 56QCh. 16 - Prob. 57QCh. 16 - Prob. 58QCh. 16 - Prob. 59QCh. 16 - Prob. 60Q
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Suppose you live in northern Canada and an extremely strong flare is reported on the Sun. What precautions might you take? What might be a positive result?arrow_forwardThe planet Venus is different from the earth in several respects. First, it is only 70% as far from the sun. Second, its thick clouds reflect 77% of all incident sunlight. Finally, its atmosphere is much more opaque to infrared light. Calculate the solar constant at the location of Venus, and estimate what the average surface temperature of Venus would be if it had no atmosphere and did not reflect any sunlight.arrow_forward(A) Every square meter area facing the Sun, at the distance 1 AU from the Sun, receives radiant power = 1.368 kW. Therefore, what is the total power radiated by the Sun? (B) Imagine a spacecraft at distance d from the Sun, which has a solar panel with area A and efficiency e. (I.e., the solar panel converts this fraction of incident sunlight to electric power.) How much electric power can the solar panel produce for the spacecraft? d = 1.56 AU; A = 7.02 m^2; e = 28.5 percent;arrow_forward
- From which atmospheric layer of the Sun did the photons originate that resulted in sunburn? How do you know?arrow_forwardEarth's daylight surface disk absorbs about 1036 W per m2 from the Sun. Using 6400 km for the Earth's radius, how much of this radiative power is emitted by each square meter of the spherical Earth? Hint: Compare the ratio of the disk area to the spherical surface area.arrow_forwardThe photosphere (the visible surface of the Sun) is at a temperature of 5800 K andsunspots on average are around 4200 K. What is the percent difference in temperaturebetween the photosphere and sunspots? At what wavelength does the radiation emittedby each region peak?arrow_forward
- Meridional is derived from meridian. Look up the definition of meridian; what is the direction of solar meridional flow?arrow_forwardUnder what conditions can the outer surface of a vertical cylinder be treated as a vertical plate in natural convection calculations?arrow_forwardHow does energy makes its way from the nuclear core of the Sun to its atmosphere? Choose the correct order for each layer. → O radiative zone, convection zone, photosphere, chromosphere, transition region, corona O convection zone, radiative zone, chromosphere, photosphere, transition region, corona convection zone, radiative zone, photosphere, chromosphere, transition region, corona O radiative zone, convection zone, chromosphere, transition region, photosphere, corona O radiative zone, convection zone, chromosphere, photosphere, transition region, corona #m с d $ 4 e 30 f % 5 t g bo 6 M 7 & 7 h O u 8 9arrow_forward
- An image of the disk of the Sun shows a higher brightness at the centre compared to the edges. Explain with the aid of a sketch the reasons for this darkening at the limb of the solar disk. In images of the solar photosphere there are small regions of the solar disk, about 500 km across, which are about 2.5 times brighter that the surrounding photosphere. Assuming a temperature of 5800 K for the background photosphere, calculate the temperature of these photospheric bright points. One explanation for these bright points is that the density is lower in these regions. Explain briefly how that could produce the observed brightening.arrow_forwardDescribe how a convection current works. In a simple way.arrow_forwardgive 4 examples for convection and radiation and explain your answers.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- AstronomyPhysicsISBN:9781938168284Author:Andrew Fraknoi; David Morrison; Sidney C. WolffPublisher:OpenStaxFoundations of Astronomy (MindTap Course List)PhysicsISBN:9781337399920Author:Michael A. Seeds, Dana BackmanPublisher:Cengage LearningStars and Galaxies (MindTap Course List)PhysicsISBN:9781337399944Author:Michael A. SeedsPublisher:Cengage Learning
Astronomy
Physics
ISBN:9781938168284
Author:Andrew Fraknoi; David Morrison; Sidney C. Wolff
Publisher:OpenStax
Foundations of Astronomy (MindTap Course List)
Physics
ISBN:9781337399920
Author:Michael A. Seeds, Dana Backman
Publisher:Cengage Learning
Stars and Galaxies (MindTap Course List)
Physics
ISBN:9781337399944
Author:Michael A. Seeds
Publisher:Cengage Learning
Heat Transfer: Crash Course Engineering #14; Author: CrashCourse;https://www.youtube.com/watch?v=YK7G6l_K6sA;License: Standard YouTube License, CC-BY