Chapter 1.6, Problem 35PPS

To determine

To find the perimeter of square

Answer to Problem 35PPS

  Perimeter is $15\sqrt{2}$ .

Explanation of Solution

Given information:

  Area is 25 square meters.

Calculation:

Let the width be x

According to question,

  Area of rectangle= $length\times breadth$

Substituting values,

  $\frac{1}{2}(x)\times x=25$

Solving,

  $\frac{x^2}{2}=25$

Multiplying by 2,

  $x^2=25$

Rooting,

  $x=\sqrt{5\times 5\times 2}$

Width is x $5\sqrt{2}$

Length is $\frac{x}{2}=\frac{5\sqrt{2}}{2}$

  Perimeter is $2(length+breadth)$

Substituting values,

  Perimeter = $2(\frac{5\sqrt{2}}{2}+5\sqrt{2})$

Solving by taking LCM,

  Perimeter= $2(\frac{5\sqrt{2}+10\sqrt{2}}{2})$

Hence, perimeter is $15\sqrt{2}$ .