Chapter 1.4, Problem 58SPR

To determine

To calculate the distance between pair of points and rounding offto nearest hundred.

Answer to Problem 58SPR

The distance between pair of points $d=12.64$ .

Round off to nearest hundred $d=0$ .

Explanation of Solution

Given information:

  $A(-1,-8),B(3,4)$

Formula used:

Distance formula

  $d=\sqrt{{(x2-x1)}^2+{(y2-y1)}^2}$

Calculation:

Applying the given formula,

  $d=\sqrt{{(x2-x1)}^2+{(y2-y1)}^2}$

Putting values,

  $x1=-1,x2=3,y1=-8,y2=4$

So,

  $d=\sqrt{{(3-(-1))}^2+{(4-(-8))}^2}$

Therefore,

  $d=\sqrt{{(3+1)}^2+{(4+8)}^2}$

On solving,

  $d=\sqrt{{(4)}^2+{(12)}^2}$

On squaring,

  $d=\sqrt{16+144}$

On solving further,

  $d=\sqrt{160}$

Therefore,

  $d=12.64$

Rounding off to nearest hundred.

  $d=0$