
a.
To find perimeter of
a.

Answer to Problem 30PPS
Perimeter is 36 meters
Explanation of Solution
Given information:
Calculation:
Perimeter = sum of all sides
Substituting values,
Perimeter=
Hence perimeter is 36 meters
b.
To find the area
b.

Answer to Problem 30PPS
area is 27m.
Explanation of Solution
Given information:
Base is 6m
Height is 9m
Formula used:
Calculation:
Substituting values,
Area=
Solving,
Area=
Hence, area is 27m.
c.
To find the effect on area and perimeter
c.

Answer to Problem 30PPS
Area is increased 4 times.
Perimeter is doubled.
Explanation of Solution
Given information:
Lengths are doubled.
Calculation:
New lengths are 30, 18, 24 m
New perimeter=
Solving,
New perimeter= 72
Hence, perimeter is doubled.
New area=
Solving,
New area=
So,
area is 108
Comparing areas,
Area is increased 4 times.
d.
To find the effect on area and perimeter.
d.

Answer to Problem 30PPS
Area is decreased 9 times.
Perimeter is decreased 3 times.
Explanation of Solution
Given information:
Lengths are decreased 3 times.
Calculation:
New Perimeter =
Solving,
New perimeter=
So,
new perimeter=12
Hence, perimeter is decreased 3 times.
Now
New area=
Solving,
New area=
Hence new area is 3. Now comparing,
Area1 is 27.
Area2 is 3
Hence area is decreased 9 times.
Chapter 1 Solutions
Geometry, Student Edition
Additional Math Textbook Solutions
Elementary Statistics (13th Edition)
University Calculus: Early Transcendentals (4th Edition)
Basic Business Statistics, Student Value Edition
Elementary Statistics: Picturing the World (7th Edition)
A First Course in Probability (10th Edition)
College Algebra with Modeling & Visualization (5th Edition)
- MI P X /courses/segura10706/products/171960/pages/611?locale=&platformId=1030&lms=Y ☆ Finish Part I: Mathematics for Elementary and Middle School Teachers Continue in the app JJ 576 Chapter 12. Area of Shapes 9. Determine the area of the shaded shapes in Figure 12.48. Explain your reasoning. 1 unit S Figure 12.48 1 unit unit and the yarn for thearrow_forwardChrom ESS $425 5. Ar Dive for x 21) Name 1. Classify the triangles based on their side lengths and angle measures. 89° 30° Acute Scalene Right Scalene 130° Date A +100 Obtuse Equiangular Isosceles Equilateral What additional information would you need to prove these triangles congruent by ASA? If marrow_forwardBoth find out Only 100% sure experts solve it correct complete solutions okkk don't use chat gpt or other ai okkarrow_forwardOnly 100% sure experts solve it correct complete solutions okkk don't use chat gpt or other ai okkarrow_forwardLogin HAC Home View Summary MwMerriam-Webster: A... Lizard Point Quizze... G Home | Gimkit Quizlet Live | Quizlet K! Kahoot! 7.2 HW Central Angles, Arcs, and Arc Lengths POSSIBLE POINTS: 6.67 11. If myQ=(y+7), mQR = (x+11), mRS = (3y), and mST = 65°, find the values of x and y. R V X = y = W S T q W a It N S C % 65 54 # m d DELL 96 t y 0 27 & J * 00 8 x= y= f g h J k X C V b n 3 ES 1 Feb 26 alt ctrlarrow_forwardThe three right triangles below are similar. The acute angles LL, LR, and ZZ are all approximately measured to be 66.9°. The side lengths for each triangle are as follows. Note that the triangles are not drawn to scale. Z 20.17 m 60.51 m 66.9° 7.92 m 66.9° 80.68 m 66.9° 23.76 m 31.68 m Take one 18.55 m K P 55.65 m X 74.2 m Y (a) For each triangle, find the ratio of the length of the side opposite 66.9° to the length of the hypotenuse. Round your answers to the nearest hundredth. JK JL PQ PR XY ☐ XZ (b) Use the ALEKS Calculator to find sin 66.9°, cos 66.9°, and tan 66.9°. Round your answers to the nearest hundredth. sin 66.9° = ☐ cos 66.9° tan 66.9° = ☐ (c) Which trigonometric function gives each ratio of sides in part (a)? Osine Ocosine Otangent none of thesearrow_forwardT Figure E Statement 33 33° H 40 R 37° 83° S T 55 45 K S 30 U 44 87 H 56 36 ° 54 F 83° 66 P 33 87° ° I 42 200 Rarrow_forwardStella's friends got her a skydiving lesson for her birthday. Her helicopter took off from the skydiving center, ascending in an angle of 37°, and traveled a distance of 2.1 kilometers before she fell in a straight line perpendicular to the ground. How far from the skydiving center did Stella land? Be sure to have all three parts of a CER answer: make a claim, provide evidence, and explain your reasoning for full credit. 2.1 km Landing spot 37% Skydiving centerarrow_forwardIn the graph provided, triangle N'O'P' is the image of triangle NOP after a dilation. 104 -9- -8- 7 6 N 5 0 -4- N 3 2 1 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10 -1 -2 -3 -4 p -5 -6 -7 -8 Xarrow_forward104 8 6 4 G G 2 F -10 -8 -6 -4 -2 0 2 4 6 8 10 N H -4 H 6 8 10arrow_forwardThe coordinates of AABC are shown on the coordinate plane provided. AABC is dilated from the origin by scale factor r=2. 2 3 -2 0 1 2 2 m 17arrow_forwardIn the diagram provided, AABC-AAPQ. Read each statement and then arrange the true/false statements in order. B P A Carrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
- Elementary Geometry For College Students, 7eGeometryISBN:9781337614085Author:Alexander, Daniel C.; Koeberlein, Geralyn M.Publisher:Cengage,Elementary Geometry for College StudentsGeometryISBN:9781285195698Author:Daniel C. Alexander, Geralyn M. KoeberleinPublisher:Cengage Learning

