Chapter 1.5, Problem 27PPS

To determine

To calculate the value of the angles

Answer to Problem 27PPS

  $\angle 1=40$ and $\angle 2=140$

Explanation of Solution

Given information:

  $\angle 1$ and $\angle 2$ are supplementary.

Value of 2 is 40 times more than twice of angle 1’s complement

Let the value of $\angle 1$ be “ $x$ ”

Hence, value of $\angle 2$ is,

  $40+2(90-x)$

On solving,

  $\angle 2=220-2x$

Substituting the values,

  $x+220-2x=180$

So,

  $-x+220=180$

Shifting the values,

  $x=220-180$

On solving,

  $x=40$

Hence,

  $\angle 1=40$

And

  $\angle 2=220-2(40)$

So,

  $\angle 2=140$

Hence, $\angle 1=40$ and $\angle 2=140$