(a) Interpretation: The compound A from its spectroscopic data is to be identified. Concept introduction: In mass spectroscopy, compounds can be identified on the basis of mass of compound. When the compound breaks into fragment then they can be distinguished from the other compounds. This technique is also used to differentiate the isotopes of compounds. This technique did not interact with electromagnetic radiation. Two peaks are used to identify the compound, first, the molecular ion peak which is the mass of the compound and second, the base peak which is the most abundant element peak. It may be same or different.

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Question

Chapter 16, Problem 16.59AP

Interpretation Introduction

(a)

Interpretation:

The compound A from its spectroscopic data is to be identified.

Concept introduction:

In mass spectroscopy, compounds can be identified on the basis of mass of compound. When the compound breaks into fragment then they can be distinguished from the other compounds. This technique is also used to differentiate the isotopes of compounds. This technique did not interact with electromagnetic radiation. Two peaks are used to identify the compound, first, the molecular ion peak which is the mass of the compound and second, the base peak which is the most abundant element peak. It may be same or different.

Interpretation Introduction

(b)

Interpretation:

The compound B with molecular formula C10H12O from its spectroscopic data is to be identified.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 2

Question

Chapter 16, Problem 16.59AP

Interpretation Introduction

(a)

Interpretation:

The compound A from its spectroscopic data is to be identified.

Concept introduction:

In mass spectroscopy, compounds can be identified on the basis of mass of compound. When the compound breaks into fragment then they can be distinguished from the other compounds. This technique is also used to differentiate the isotopes of compounds. This technique did not interact with electromagnetic radiation. Two peaks are used to identify the compound, first, the molecular ion peak which is the mass of the compound and second, the base peak which is the most abundant element peak. It may be same or different.

Interpretation Introduction

(b)

Interpretation:

The compound B with molecular formula C10H12O from its spectroscopic data is to be identified.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 3

Question

Chapter 16, Problem 16.59AP

Interpretation Introduction

(a)

Interpretation:

The compound A from its spectroscopic data is to be identified.

Concept introduction:

In mass spectroscopy, compounds can be identified on the basis of mass of compound. When the compound breaks into fragment then they can be distinguished from the other compounds. This technique is also used to differentiate the isotopes of compounds. This technique did not interact with electromagnetic radiation. Two peaks are used to identify the compound, first, the molecular ion peak which is the mass of the compound and second, the base peak which is the most abundant element peak. It may be same or different.

Interpretation Introduction

(b)

Interpretation:

The compound B with molecular formula C10H12O from its spectroscopic data is to be identified.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 4

Question

Chapter 16, Problem 16.59AP

Interpretation Introduction

(a)

Interpretation:

The compound A from its spectroscopic data is to be identified.

Concept introduction:

In mass spectroscopy, compounds can be identified on the basis of mass of compound. When the compound breaks into fragment then they can be distinguished from the other compounds. This technique is also used to differentiate the isotopes of compounds. This technique did not interact with electromagnetic radiation. Two peaks are used to identify the compound, first, the molecular ion peak which is the mass of the compound and second, the base peak which is the most abundant element peak. It may be same or different.

Interpretation Introduction

(b)

Interpretation:

The compound B with molecular formula C10H12O from its spectroscopic data is to be identified.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 5

Chapter 16, Problem 16.59AP

Interpretation Introduction

(a)

Interpretation:

The compound A from its spectroscopic data is to be identified.

Concept introduction:

In mass spectroscopy, compounds can be identified on the basis of mass of compound. When the compound breaks into fragment then they can be distinguished from the other compounds. This technique is also used to differentiate the isotopes of compounds. This technique did not interact with electromagnetic radiation. Two peaks are used to identify the compound, first, the molecular ion peak which is the mass of the compound and second, the base peak which is the most abundant element peak. It may be same or different.

Interpretation Introduction

(b)

Interpretation:

The compound B with molecular formula C10H12O from its spectroscopic data is to be identified.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 6

Chapter 16, Problem 16.59AP

Interpretation Introduction

(a)

Interpretation:

The compound A from its spectroscopic data is to be identified.

Concept introduction:

In mass spectroscopy, compounds can be identified on the basis of mass of compound. When the compound breaks into fragment then they can be distinguished from the other compounds. This technique is also used to differentiate the isotopes of compounds. This technique did not interact with electromagnetic radiation. Two peaks are used to identify the compound, first, the molecular ion peak which is the mass of the compound and second, the base peak which is the most abundant element peak. It may be same or different.

Answer 7

Chapter 16, Problem 16.59AP

Interpretation Introduction

(a)

Interpretation:

The compound A from its spectroscopic data is to be identified.

Concept introduction:

In mass spectroscopy, compounds can be identified on the basis of mass of compound. When the compound breaks into fragment then they can be distinguished from the other compounds. This technique is also used to differentiate the isotopes of compounds. This technique did not interact with electromagnetic radiation. Two peaks are used to identify the compound, first, the molecular ion peak which is the mass of the compound and second, the base peak which is the most abundant element peak. It may be same or different.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The compound B with molecular formula C10H12O from its spectroscopic data is to be identified.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The compound B with molecular formula C10H12O from its spectroscopic data is to be identified.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 10

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Answer 12

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Answer 13

Ch. 16 - Prob. 16.1P Ch. 16 - Prob. 16.2P Ch. 16 - Prob. 16.3P Ch. 16 - Prob. 16.4P Ch. 16 - Prob. 16.5P Ch. 16 - Prob. 16.6P Ch. 16 - Prob. 16.7P Ch. 16 - Prob. 16.8P Ch. 16 - Prob. 16.9P Ch. 16 - Prob. 16.10P

Solution Summary: The author explains the structure of the compound A from its spectroscopic data.

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