(a) Interpretation: The isomers: mesitylene ( 1, 3, 5-trimethylbenzene ) and p -ethyltoluene , using NMR spectroscopy are to be differentiated. Concept introduction: The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 1

Question

Chapter 16, Problem 16.6P

Interpretation Introduction

(a)

Interpretation:

The isomers: mesitylene(1, 3, 5-trimethylbenzene) and p-ethyltoluene, using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Interpretation Introduction

(b)

Interpretation:

The isomers: 1-bromo-4-ethylbenzene and (2-bromoethyl)benzene(BrCH2CH2Ph), using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Transmitance 3. Which one of the following compounds corresponds to this IR spectrum? Point out the absorption band(s) that helped you decide. OH H3C OH H₂C CH3 H3C CH3 H3C INFRARED SPECTRUM 0.8- 0.6 0.4- 0.2 3000 2000 1000 Wavenumber (cm-1) 4. Consider this compound: H3C On the structure above, label the different types of H's as A, B, C, etc. In table form, list the labeled signals, and for each one state the number of hydrogens, their shifts, and the splitting you would observe for these hydrogens in the ¹H NMR spectrum. Label # of hydrogens splitting Shift (2)

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Answer 2

Question

Chapter 16, Problem 16.6P

Interpretation Introduction

(a)

Interpretation:

The isomers: mesitylene(1, 3, 5-trimethylbenzene) and p-ethyltoluene, using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Interpretation Introduction

(b)

Interpretation:

The isomers: 1-bromo-4-ethylbenzene and (2-bromoethyl)benzene(BrCH2CH2Ph), using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 3

Question

Chapter 16, Problem 16.6P

Interpretation Introduction

(a)

Interpretation:

The isomers: mesitylene(1, 3, 5-trimethylbenzene) and p-ethyltoluene, using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Interpretation Introduction

(b)

Interpretation:

The isomers: 1-bromo-4-ethylbenzene and (2-bromoethyl)benzene(BrCH2CH2Ph), using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 4

Question

Chapter 16, Problem 16.6P

Interpretation Introduction

(a)

Interpretation:

The isomers: mesitylene(1, 3, 5-trimethylbenzene) and p-ethyltoluene, using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Interpretation Introduction

(b)

Interpretation:

The isomers: 1-bromo-4-ethylbenzene and (2-bromoethyl)benzene(BrCH2CH2Ph), using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 5

Chapter 16, Problem 16.6P

Interpretation Introduction

(a)

Interpretation:

The isomers: mesitylene(1, 3, 5-trimethylbenzene) and p-ethyltoluene, using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Interpretation Introduction

(b)

Interpretation:

The isomers: 1-bromo-4-ethylbenzene and (2-bromoethyl)benzene(BrCH2CH2Ph), using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 6

Chapter 16, Problem 16.6P

Interpretation Introduction

(a)

Interpretation:

The isomers: mesitylene(1, 3, 5-trimethylbenzene) and p-ethyltoluene, using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 7

Chapter 16, Problem 16.6P

Interpretation Introduction

(a)

Interpretation:

The isomers: mesitylene(1, 3, 5-trimethylbenzene) and p-ethyltoluene, using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The isomers: 1-bromo-4-ethylbenzene and (2-bromoethyl)benzene(BrCH2CH2Ph), using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The isomers: 1-bromo-4-ethylbenzene and (2-bromoethyl)benzene(BrCH2CH2Ph), using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 10

Expert Solution & Answer

Answer 11

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Answer 12

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Answer 13

Ch. 16 - Prob. 16.1P Ch. 16 - Prob. 16.2P Ch. 16 - Prob. 16.3P Ch. 16 - Prob. 16.4P Ch. 16 - Prob. 16.5P Ch. 16 - Prob. 16.6P Ch. 16 - Prob. 16.7P Ch. 16 - Prob. 16.8P Ch. 16 - Prob. 16.9P Ch. 16 - Prob. 16.10P

Solution Summary: The author explains that the number of NMR signal in a compound is equal to the amount of chemically non-equivalent protons present in that compound.

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Chapter 16 Solutions