Among the given solutions, the solution whose pH will be lowered on addition of equal volume of 0.60 M NaOH is to be determined. Concept introduction: pH of a strong base added to water is determined by its hydronium ion concentration. pH = − log [ H 3 O + ] …… (1) The relationship between [ OH − ] and [ H 3 O + ] is: [ H 3 O + ] = 1.0 × 10 − 14 [ OH − ] …… (2) When a strong acid is neutralized by a strong base, the pH of the solution is determined by the unused moles of either acid or base. These moles are expressed in terms of concentration and the pH is calculated. When a strong base is added into another strong base, the equivalent concentration of hydroxide ions and hydronium ions are calculated. This is then used to calculate the pH of the solution.
Among the given solutions, the solution whose pH will be lowered on addition of equal volume of 0.60 M NaOH is to be determined. Concept introduction: pH of a strong base added to water is determined by its hydronium ion concentration. pH = − log [ H 3 O + ] …… (1) The relationship between [ OH − ] and [ H 3 O + ] is: [ H 3 O + ] = 1.0 × 10 − 14 [ OH − ] …… (2) When a strong acid is neutralized by a strong base, the pH of the solution is determined by the unused moles of either acid or base. These moles are expressed in terms of concentration and the pH is calculated. When a strong base is added into another strong base, the equivalent concentration of hydroxide ions and hydronium ions are calculated. This is then used to calculate the pH of the solution.
Solution Summary: The author explains how the pH of a strong base is determined by its hydronium ion concentration.
Among the given solutions, the solution whose pH will be lowered on addition of equal volume of 0.60MNaOH is to be determined.
Concept introduction:
pH of a strong base added to water is determined by its hydronium ion concentration.
pH=−log[H3O+] …… (1)
The relationship between [OH−] and [H3O+] is:
[H3O+] = 1.0×10−14[OH−] …… (2)
When a strong acid is neutralized by a strong base, the pH of the solution is determined by the unused moles of either acid or base. These moles are expressed in terms of concentration and the pH is calculated.
When a strong base is added into another strong base, the equivalent concentration of hydroxide ions and hydronium ions are calculated. This is then used to calculate the pH of the solution.
Suppose that, instead of using NaOH, a base such as Ba(OH)2 had been used. What changes in the calculations would then have to be made to determine the molar concentrations of the base?
(a) What is the pH of 0.75 M NaF?(b) What is the pH of 0.88 M pyridinium chloride, C₅H₅NHCl?
Given that Ka’s for hydrofluoric acid (HF) and boric acid (H3BO3) are 6.3 × 10^–4 and 5.4 × 10^–10, respectively, calculate the pH of the following solutions:
(a) The mixture from adding 50 mL 0.2 M HF to 50 mL 0.5 M sodium borate (NaH2BO3).
(b) The mixture from adding an additional 150 mL 0.2 M HF to the solution in (a), i.e., a total of 200 mL 0.2 M HF was added to 50 mL 0.5 M NaH2BO3.
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