From the given monoprotic acid systems, the conjugate base with the smallest K b value and the strongest anion base are to be determined. Concept introduction: The ionization of a weak acid takes place as: HA ( aq ) + H 2 O ( l ) ⇌ H 3 O + ( aq ) + A − ( aq ) K a is the measure of dissociation of an acid and is known as the acid-ionization constant, which is specific at a particular temperature. K a = [ H 3 O + ] [ A − ] [ HA ] …… (1) The ionization of its conjugate base takes place as: A − ( aq ) + H 2 O ( l ) ⇌ HA ( aq ) + OH − ( aq ) K b is the measure of ionization of a base and is known as the base-ionization constant, which is specific at a particular temperature. K b = [ HA ] [ OH − ] [ A − ] …… (2) The equation that relates the K a for a weak acid and the K b for its conjugate base is: K w = K a × K b …… (3) Here, K w has the value 1.0 × 10 − 14 .
From the given monoprotic acid systems, the conjugate base with the smallest K b value and the strongest anion base are to be determined. Concept introduction: The ionization of a weak acid takes place as: HA ( aq ) + H 2 O ( l ) ⇌ H 3 O + ( aq ) + A − ( aq ) K a is the measure of dissociation of an acid and is known as the acid-ionization constant, which is specific at a particular temperature. K a = [ H 3 O + ] [ A − ] [ HA ] …… (1) The ionization of its conjugate base takes place as: A − ( aq ) + H 2 O ( l ) ⇌ HA ( aq ) + OH − ( aq ) K b is the measure of ionization of a base and is known as the base-ionization constant, which is specific at a particular temperature. K b = [ HA ] [ OH − ] [ A − ] …… (2) The equation that relates the K a for a weak acid and the K b for its conjugate base is: K w = K a × K b …… (3) Here, K w has the value 1.0 × 10 − 14 .
Solution Summary: The author explains that the conjugate base with the smallest K_b value and the strongest anion base are determined.
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Also calculate the amount of starting materials chlorobenzaldehyde and p-chloroacetophenone
required to prepare 400 mg of the given chalcone product 1, 3-bis(4-chlorophenyl)prop-2-en-1-one
molar mass ok 1,3-bis(4-Chlorophenyl) prop-2-en-1-one = 277.1591m01
number of moles= 0.400/277.15 = 0.00144 moles
2 x 0.00 144=0.00288 moves
arams of acetophenone = 0.00144 X 120.16 = 0.1739
0.1739x2=0.3469
grams of benzaldehyde = 0.00144X106.12=0.1539
0.1539x2 = 0.3069
Starting materials:
0.3469 Ox acetophenone,
0.3069 of benzaldehyde
3
1.
Answer the questions about the following reaction:
(a) Draw in the arrows that can be used make this reaction occur and draw in the product of substitution in this
reaction. Be sure to include any relevant stereochemistry in the product structure.
+
SK
F
Br
+
(b) In which solvent would this reaction proceed the fastest (Circle one)
Methanol
Acetone
(c) Imagine that you are working for a chemical company and it was your job to perform a similar reaction to the
one above, with the exception of the S atom in this reaction being replaced by an O atom. During the reaction, you
observe the formation of three separate molecules instead of the single molecule obtained above. What is the likeliest
other products that are formed? Draw them in the box provided.
3. For the reactions below, draw the arrows corresponding to the transformations and draw in the boxes the reactants
or products as indicated. Note: Part A should have arrows drawn going from the reactants to the middle structure
and the arrows on the middle structure that would yield the final structure. For part B, you will need to draw in
the reactant before being able to draw the arrows corresponding to product formation.
A.
B.
Rearrangement
ΘΗ
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