World of Chemistry
7th Edition
ISBN: 9780618562763
Author: Steven S. Zumdahl
Publisher: Houghton Mifflin College Div
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Chapter 15.3, Problem 1RQ
Interpretation Introduction
Interpretation: The steps for determining the number of moles when solutions are mixed to produce a reaction has to be stated.
Concept introduction: Solution is mixture in which all components are uniformly distributed. Any solution has 2 substances: solute and solvent. For formation of solution compatibility between solute and solvent is required. Example is salt solution and sugar solution.
Expert Solution & Answer
Answer to Problem 1RQ
The steps for determining the number of moles when solutions are mixed to produce a reaction are:
- Firstly a balanced equation for the reaction is written. For ionic reactions, a net ionic equation is expressed.
- Then moles of reactant involved are determined.
- Limiting reactant is identified.
- Moles of other reactant or product required are then estimated.
- Using conversion factors moles obtained are converted to grams or other units.
Explanation of Solution
When any solution is mixed with other for reaction then stoichiometry of the reaction resulted from it is obtained by following steps:
- Firstly a balanced equation for the reaction is written. For ionic reactions, a net ionic equation is expressed.
- Then moles of reactant involved are determined.
- Limiting reactant is identified.
- Moles of other reactant or product required are then estimated.
- Using conversion factors moles obtained are converted to grams or other units.
Conclusion
The steps for determining the number of moles when solutions are mixed to produce a reaction are:
- Firstly a balanced equation for the reaction is written. For ionic reactions, a net ionic equation is expressed.
- Then moles of reactant involved are determined.
- Limiting reactant is identified.
- Moles of other reactant or product required are then estimated.
- Using conversion factors moles obtained are converted to grams or other units.
Chapter 15 Solutions
World of Chemistry
Ch. 15.1 - Prob. 1RQCh. 15.1 - Prob. 2RQCh. 15.1 - Prob. 3RQCh. 15.1 - Prob. 4RQCh. 15.1 - Prob. 5RQCh. 15.1 - Prob. 6RQCh. 15.2 - Prob. 1RQCh. 15.2 - Prob. 2RQCh. 15.2 - Prob. 3RQCh. 15.2 - Prob. 4RQ
Ch. 15.2 - Prob. 5RQCh. 15.2 - Prob. 6RQCh. 15.2 - Prob. 7RQCh. 15.3 - Prob. 1RQCh. 15.3 - Prob. 2RQCh. 15.3 - Prob. 3RQCh. 15.3 - Prob. 4RQCh. 15.3 - Prob. 5RQCh. 15.3 - Prob. 6RQCh. 15.3 - Prob. 7RQCh. 15.3 - Prob. 8RQCh. 15 - Prob. 1ACh. 15 - Prob. 2ACh. 15 - Prob. 3ACh. 15 - Prob. 4ACh. 15 - Prob. 5ACh. 15 - Prob. 6ACh. 15 - Prob. 7ACh. 15 - Prob. 8ACh. 15 - Prob. 9ACh. 15 - Prob. 10ACh. 15 - Prob. 11ACh. 15 - Prob. 12ACh. 15 - Prob. 13ACh. 15 - Prob. 14ACh. 15 - Prob. 15ACh. 15 - Prob. 16ACh. 15 - Prob. 17ACh. 15 - Prob. 18ACh. 15 - Prob. 19ACh. 15 - Prob. 20ACh. 15 - Prob. 21ACh. 15 - Prob. 22ACh. 15 - Prob. 23ACh. 15 - Prob. 24ACh. 15 - Prob. 25ACh. 15 - Prob. 26ACh. 15 - Prob. 27ACh. 15 - Prob. 28ACh. 15 - Prob. 29ACh. 15 - Prob. 30ACh. 15 - Prob. 31ACh. 15 - Prob. 32ACh. 15 - Prob. 33ACh. 15 - Prob. 34ACh. 15 - Prob. 35ACh. 15 - Prob. 36ACh. 15 - Prob. 37ACh. 15 - Prob. 38ACh. 15 - Prob. 39ACh. 15 - Prob. 40ACh. 15 - Prob. 41ACh. 15 - Prob. 42ACh. 15 - Prob. 43ACh. 15 - Prob. 44ACh. 15 - Prob. 45ACh. 15 - Prob. 46ACh. 15 - Prob. 47ACh. 15 - Prob. 48ACh. 15 - Prob. 49ACh. 15 - Prob. 50ACh. 15 - Prob. 51ACh. 15 - Prob. 52ACh. 15 - Prob. 53ACh. 15 - Prob. 54ACh. 15 - Prob. 55ACh. 15 - Prob. 56ACh. 15 - Prob. 57ACh. 15 - Prob. 58ACh. 15 - Prob. 59ACh. 15 - Prob. 60ACh. 15 - Prob. 61ACh. 15 - Prob. 62ACh. 15 - Prob. 63ACh. 15 - Prob. 1STPCh. 15 - Prob. 2STPCh. 15 - Prob. 3STPCh. 15 - Prob. 4STPCh. 15 - Prob. 5STPCh. 15 - Prob. 6STPCh. 15 - Prob. 7STPCh. 15 - Prob. 8STPCh. 15 - Prob. 9STPCh. 15 - Prob. 10STPCh. 15 - Prob. 11STP
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