Chapter 15.2, Problem 1RQ

Interpretation Introduction

Interpretation:Mass percent of acetic acid in vinegar solution made by $\text{33}\text{g}$ of acetic acid to $\text{625}\text{g}$ of water has to be determined.

Concept introduction:Solution is a mixture in which all components are uniformly distributed. Any solution has 2 substances: solute and solvent. The composition of a solution is determined by calculating various quantities like mass percent, molality, molarity and many more.

Mass percent is defined by formula as follows:

  $\text{mass percent}=\frac{\mathrm{mass}ofsolute}{\text{mass}\text{of}\text{solution}}\times 100\%$

Answer to Problem 1RQ

The mass percent of acetic acid in vinegar solution is $5.015\%$ .

Explanation of Solution

Given information: Mass of acetic acid is $\text{33}\text{g}$ and mass of water is $\text{625}\text{g}$ .

Mass of vinegar solution is calculated as follows:

  $\begin{array}{c}\text{mass of vinegar}=\text{mass}\text{of}\text{water}+\text{mass}\text{of}\text{acetic}\text{acid}\\ =\text{33}\text{g}+625\text{g}\\ =\text{658}\text{g}\end{array}$

Mass percent is defined by formula as follows:

  $\text{mass percent}=\frac{\mathrm{mass}ofsolute}{\text{mass}\text{of}\text{solution}}\times 100\%$

Substitute $\text{33}\text{g}$ asthe mass of solute and $\text{658}\text{g}$ as the mass of water in the above equation.

  $\begin{array}{c}\text{mass percent}=\frac{\mathrm{mass}ofsolute}{\text{mass}\text{of}\text{solution}}\times 100\%\\ =\frac{\text{33}\text{g}}{\text{658}\text{g}}\times 100\%\\ =5.015\%\end{array}$

Conclusion

The mass percent of acetic acid in vinegar solution is $5.015\%$ .