Geometry For Enjoyment And Challenge
Geometry For Enjoyment And Challenge
91st Edition
ISBN: 9780866099653
Author: Richard Rhoad, George Milauskas, Robert Whipple
Publisher: McDougal Littell
Question
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Chapter 15.2, Problem 19PSB

a.

To determine

To find: the lateral surface area of the given pattern.

a.

Expert Solution
Check Mark

Answer to Problem 19PSB

  714.0 .

Explanation of Solution

Given:

The pattern shown can be folded to form a prism with a rectangular hexagon base.

  Geometry For Enjoyment And Challenge, Chapter 15.2, Problem 19PSB , additional homework tip  1

Calculation:

According to the question, the form of the pattern is a prism with a rectangular hexagon base.

Thus, the lateral surface area of the given prism is

  LSA=17×7×6LSA=714

Hence, the lateral surface area of the given pattern is 714.0

b.

To determine

To find: the total surface area of the given pattern.

b.

Expert Solution
Check Mark

Answer to Problem 19PSB

  968.6 .

Explanation of Solution

Given:

The pattern shown can be folded to form a prism with a rectangular hexagon base.

  Geometry For Enjoyment And Challenge, Chapter 15.2, Problem 19PSB , additional homework tip  2

Calculation:

According to the question, the form of the pattern is a prism with a rectangular hexagon base.

Thus, the total surface area of the given prism is sum of the lateral surface area and the area of the hexagonal base.

Now, area of the hexagonal base is

  SAHEX=12apSAHEX=12×723×42SAHEX=127.31

Thus, the total surface area of the given prism is

  TSA=LSA+2SAHEXTSA=714+2(127.31)TSA=714+254.6=968.6

Hence, the total surface area of the given pattern is 968.6

c.

To determine

To find: the volume of the given pattern.

c.

Expert Solution
Check Mark

Answer to Problem 19PSB

  V=2164.2 .

Explanation of Solution

Given:

The pattern shown can be folded to form a prism with a rectangular hexagon base.

  Geometry For Enjoyment And Challenge, Chapter 15.2, Problem 19PSB , additional homework tip  3

Calculation:

According to the question, the form of the pattern is a prism with a rectangular hexagon base.

Thus, the volume of the given prism is

  V=SAHEX×17V=127.31×17V=2164.2

Hence, the volume of the given pattern is V=2164.2

Chapter 15 Solutions

Geometry For Enjoyment And Challenge

Ch. 15.1 - Prob. 11PSBCh. 15.1 - Prob. 12PSBCh. 15.1 - Prob. 13PSBCh. 15.1 - Prob. 14PSCCh. 15.1 - Prob. 15PSCCh. 15.1 - Prob. 16PSCCh. 15.1 - Prob. 17PSCCh. 15.1 - Prob. 18PSCCh. 15.1 - Prob. 19PSCCh. 15.1 - Prob. 20PSDCh. 15.2 - Prob. 1PSACh. 15.2 - Prob. 2PSACh. 15.2 - Prob. 3PSACh. 15.2 - Prob. 4PSACh. 15.2 - Prob. 5PSACh. 15.2 - Prob. 6PSACh. 15.2 - Prob. 7PSBCh. 15.2 - Prob. 8PSBCh. 15.2 - Prob. 9PSBCh. 15.2 - Prob. 10PSBCh. 15.2 - Prob. 11PSBCh. 15.2 - Prob. 12PSBCh. 15.2 - Prob. 13PSBCh. 15.2 - Prob. 14PSBCh. 15.2 - Prob. 15PSBCh. 15.2 - Prob. 16PSBCh. 15.2 - Prob. 17PSBCh. 15.2 - Prob. 18PSBCh. 15.2 - Prob. 19PSBCh. 15.2 - Prob. 20PSCCh. 15.2 - Prob. 21PSCCh. 15.2 - Prob. 22PSCCh. 15.2 - Prob. 23PSCCh. 15.2 - Prob. 24PSCCh. 15.2 - Prob. 25PSCCh. 15.3 - Prob. 1PSACh. 15.3 - Prob. 2PSACh. 15.3 - Prob. 3PSACh. 15.3 - Prob. 4PSACh. 15.3 - Prob. 5PSACh. 15.3 - Prob. 6PSACh. 15.3 - Prob. 7PSACh. 15.3 - Prob. 8PSBCh. 15.3 - Prob. 9PSBCh. 15.3 - Prob. 10PSBCh. 15.3 - Prob. 11PSBCh. 15.3 - Prob. 12PSBCh. 15.3 - Prob. 13PSBCh. 15.3 - Prob. 14PSBCh. 15.3 - Prob. 15PSBCh. 15.3 - Prob. 16PSBCh. 15.3 - Prob. 17PSBCh. 15.3 - Prob. 18PSBCh. 15.3 - Prob. 19PSBCh. 15.3 - Prob. 20PSCCh. 15.3 - Prob. 21PSCCh. 15.3 - Prob. 22PSCCh. 15.3 - Prob. 23PSCCh. 15.3 - Prob. 24PSCCh. 15.3 - Prob. 25PSCCh. 15.3 - Prob. 26PSCCh. 15 - Prob. 1RPCh. 15 - Prob. 2RPCh. 15 - Prob. 3RPCh. 15 - Prob. 4RPCh. 15 - Prob. 5RPCh. 15 - Prob. 6RPCh. 15 - Prob. 7RPCh. 15 - Prob. 8RPCh. 15 - Prob. 9RPCh. 15 - Prob. 10RPCh. 15 - Prob. 11RPCh. 15 - Prob. 12RPCh. 15 - Prob. 13RPCh. 15 - Prob. 14RPCh. 15 - Prob. 15RPCh. 15 - Prob. 16RPCh. 15 - Prob. 17RPCh. 15 - Prob. 18RPCh. 15 - Prob. 19RPCh. 15 - Prob. 20RPCh. 15 - Prob. 21RPCh. 15 - Prob. 22RPCh. 15 - Prob. 23RPCh. 15 - Prob. 24RPCh. 15 - Prob. 25RPCh. 15 - Prob. 1CRCh. 15 - Prob. 2CRCh. 15 - Prob. 3CRCh. 15 - Prob. 4CRCh. 15 - Prob. 5CRCh. 15 - Prob. 6CRCh. 15 - Prob. 7CRCh. 15 - Prob. 8CRCh. 15 - Prob. 9CRCh. 15 - Prob. 10CRCh. 15 - Prob. 11CRCh. 15 - Prob. 12CRCh. 15 - Prob. 13CRCh. 15 - Prob. 14CRCh. 15 - Prob. 15CRCh. 15 - Prob. 16CRCh. 15 - Prob. 17CRCh. 15 - Prob. 18CRCh. 15 - Prob. 19CRCh. 15 - Prob. 20CRCh. 15 - Prob. 21CRCh. 15 - Prob. 22CRCh. 15 - Prob. 23CRCh. 15 - Prob. 24CRCh. 15 - Prob. 25CRCh. 15 - Prob. 26CRCh. 15 - Prob. 27CRCh. 15 - Prob. 28CRCh. 15 - Prob. 29CRCh. 15 - Prob. 30CRCh. 15 - Prob. 31CRCh. 15 - Prob. 32CRCh. 15 - Prob. 33CRCh. 15 - Prob. 34CRCh. 15 - Prob. 35CRCh. 15 - Prob. 36CRCh. 15 - Prob. 37CRCh. 15 - Prob. 38CRCh. 15 - Prob. 39CRCh. 15 - Prob. 40CRCh. 15 - Prob. 41CRCh. 15 - Prob. 42CRCh. 15 - Prob. 43CRCh. 15 - Prob. 44CRCh. 15 - Prob. 45CRCh. 15 - Prob. 46CRCh. 15 - Prob. 47CRCh. 15 - Prob. 48CRCh. 15 - Prob. 49CRCh. 15 - Prob. 50CR
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