Geometry For Enjoyment And Challenge
Geometry For Enjoyment And Challenge
91st Edition
ISBN: 9780866099653
Author: Richard Rhoad, George Milauskas, Robert Whipple
Publisher: McDougal Littell
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Chapter 15.3, Problem 12PSB
To determine

To Prove: The side BC is greater than the side AD in the given figure.

Expert Solution & Answer
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Explanation of Solution

Given:

  1=3BA¯CD¯AC>AD

  Geometry For Enjoyment And Challenge, Chapter 15.3, Problem 12PSB

Concept Used:

The Hinge Theorem: It states that if two sides of two triangles are congruent and angle of one is greater than the angle of second then the third side of the triangle will be greater than the another.

Calculation:

  BA¯CD¯                      (Given)23                       (Two parallel line cut by transversal,each pair of alternateinterior angle are congruent.)1<3                        (Given)1<2                        (Because 23)BC>AC                     (Two side of a triangle are not congruent,then the angles oppositethem are not congruent and the larger angle is opposite the longer side)AC>AD                     (Given)BC>AD                     (Transitive property of inequality and BC>AC and  AC>AD)

Conclusion:

Thus, it is proved that BC>AD

Chapter 15 Solutions

Geometry For Enjoyment And Challenge

Ch. 15.1 - Prob. 11PSBCh. 15.1 - Prob. 12PSBCh. 15.1 - Prob. 13PSBCh. 15.1 - Prob. 14PSCCh. 15.1 - Prob. 15PSCCh. 15.1 - Prob. 16PSCCh. 15.1 - Prob. 17PSCCh. 15.1 - Prob. 18PSCCh. 15.1 - Prob. 19PSCCh. 15.1 - Prob. 20PSDCh. 15.2 - Prob. 1PSACh. 15.2 - Prob. 2PSACh. 15.2 - Prob. 3PSACh. 15.2 - Prob. 4PSACh. 15.2 - Prob. 5PSACh. 15.2 - Prob. 6PSACh. 15.2 - Prob. 7PSBCh. 15.2 - Prob. 8PSBCh. 15.2 - Prob. 9PSBCh. 15.2 - Prob. 10PSBCh. 15.2 - Prob. 11PSBCh. 15.2 - Prob. 12PSBCh. 15.2 - Prob. 13PSBCh. 15.2 - Prob. 14PSBCh. 15.2 - Prob. 15PSBCh. 15.2 - Prob. 16PSBCh. 15.2 - Prob. 17PSBCh. 15.2 - Prob. 18PSBCh. 15.2 - Prob. 19PSBCh. 15.2 - Prob. 20PSCCh. 15.2 - Prob. 21PSCCh. 15.2 - Prob. 22PSCCh. 15.2 - Prob. 23PSCCh. 15.2 - Prob. 24PSCCh. 15.2 - Prob. 25PSCCh. 15.3 - Prob. 1PSACh. 15.3 - Prob. 2PSACh. 15.3 - Prob. 3PSACh. 15.3 - Prob. 4PSACh. 15.3 - Prob. 5PSACh. 15.3 - Prob. 6PSACh. 15.3 - Prob. 7PSACh. 15.3 - Prob. 8PSBCh. 15.3 - Prob. 9PSBCh. 15.3 - Prob. 10PSBCh. 15.3 - Prob. 11PSBCh. 15.3 - Prob. 12PSBCh. 15.3 - Prob. 13PSBCh. 15.3 - Prob. 14PSBCh. 15.3 - Prob. 15PSBCh. 15.3 - Prob. 16PSBCh. 15.3 - Prob. 17PSBCh. 15.3 - Prob. 18PSBCh. 15.3 - Prob. 19PSBCh. 15.3 - Prob. 20PSCCh. 15.3 - Prob. 21PSCCh. 15.3 - Prob. 22PSCCh. 15.3 - Prob. 23PSCCh. 15.3 - Prob. 24PSCCh. 15.3 - Prob. 25PSCCh. 15.3 - Prob. 26PSCCh. 15 - Prob. 1RPCh. 15 - Prob. 2RPCh. 15 - Prob. 3RPCh. 15 - Prob. 4RPCh. 15 - Prob. 5RPCh. 15 - Prob. 6RPCh. 15 - Prob. 7RPCh. 15 - Prob. 8RPCh. 15 - Prob. 9RPCh. 15 - Prob. 10RPCh. 15 - Prob. 11RPCh. 15 - Prob. 12RPCh. 15 - Prob. 13RPCh. 15 - Prob. 14RPCh. 15 - Prob. 15RPCh. 15 - Prob. 16RPCh. 15 - Prob. 17RPCh. 15 - Prob. 18RPCh. 15 - Prob. 19RPCh. 15 - Prob. 20RPCh. 15 - Prob. 21RPCh. 15 - Prob. 22RPCh. 15 - Prob. 23RPCh. 15 - Prob. 24RPCh. 15 - Prob. 25RPCh. 15 - Prob. 1CRCh. 15 - Prob. 2CRCh. 15 - Prob. 3CRCh. 15 - Prob. 4CRCh. 15 - Prob. 5CRCh. 15 - Prob. 6CRCh. 15 - Prob. 7CRCh. 15 - Prob. 8CRCh. 15 - Prob. 9CRCh. 15 - Prob. 10CRCh. 15 - Prob. 11CRCh. 15 - Prob. 12CRCh. 15 - Prob. 13CRCh. 15 - Prob. 14CRCh. 15 - Prob. 15CRCh. 15 - Prob. 16CRCh. 15 - Prob. 17CRCh. 15 - Prob. 18CRCh. 15 - Prob. 19CRCh. 15 - Prob. 20CRCh. 15 - Prob. 21CRCh. 15 - Prob. 22CRCh. 15 - Prob. 23CRCh. 15 - Prob. 24CRCh. 15 - Prob. 25CRCh. 15 - Prob. 26CRCh. 15 - Prob. 27CRCh. 15 - Prob. 28CRCh. 15 - Prob. 29CRCh. 15 - Prob. 30CRCh. 15 - Prob. 31CRCh. 15 - Prob. 32CRCh. 15 - Prob. 33CRCh. 15 - Prob. 34CRCh. 15 - Prob. 35CRCh. 15 - Prob. 36CRCh. 15 - Prob. 37CRCh. 15 - Prob. 38CRCh. 15 - Prob. 39CRCh. 15 - Prob. 40CRCh. 15 - Prob. 41CRCh. 15 - Prob. 42CRCh. 15 - Prob. 43CRCh. 15 - Prob. 44CRCh. 15 - Prob. 45CRCh. 15 - Prob. 46CRCh. 15 - Prob. 47CRCh. 15 - Prob. 48CRCh. 15 - Prob. 49CRCh. 15 - Prob. 50CR
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